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Jan
1:03 AM
0
A: When is rotation around double bonds to form cis-trans isomers allowed?

JanGenerally, all single bonds are said to permit free rotation while all double bonds are said to inhibit free rotation. This can actually be explained numerically as well: the rotation around the $\ce{O-O}$ bond in $\ce{H2O2}$ has an approximate rate constant of $2.0 \times 10^{8}~\mathrm{s^{-1}}$...

In case the people knowledgeable in group theory want to check the claim I made with which photon is able to excite pi->pi^*, please feel free and tell me how wrong I am ;)
 
1:29 AM
@Jan thanks, but I believe that we say "I without you am like a singer without song" in English?
 
Jan
I would put commas in there. And I’m not fully sure but I feel the following is a slightly closer translation:
> Me without you is like a singer without a song.
 
Also, I can't find "gestölpert" although google translates it to "stumped" or "stupid"
should it be gestolpert?
 
Jan
It’s tripped.
The infinitive is stölpern.
 
I can't find stölpern either
not in Duden
 
Jan
Really …?
 
1:34 AM
really
 
Jan
True story, I just checked all of German.SE’s common sources ô.o
 
@Jan Wo bist du von?
 
Jan
Now I’m really confused. Maybe I should ask about it on German Language =D
 
ja klar
@Jan "stolpern" means something similar though
 
Jan
However, I really stölper over stolper xD
 
1:39 AM
@Jan Wuerdest du die Frage stellen?
 
Jan
I’m still going through posts of today on chem; after that travel, after that bed. Maybe tomorrow.
 
ok
 
Jan
Why doesn’t \colspan exist in MathJax? D=
 
2:02 AM
Remind me not to answer questions by this guy again
 
Jan
Which guy?
 
Your question edit managed to invalidate two answers at one go. — orthocresol ♦ 5 mins ago
 
Jan
Oh, that one.
 
I have a nice diagram for the photochem question. I'll see if I can find it later ;)
 
@orthocresol Hm, if the current question really is what the user always intended, the first example using NaHCO3 was very unfortunate.
 
Jan
@CowperKettle Unfortunately, the subtitles are Ukranian only, so I still don’t understand =C
Good evening; 3:30 here.
 
Jan
2:45 AM
0
A: What advantages does the mole have over counting large numbers using SI prefixes?

juanrgaI am a chemist and I am still trying to understand why SI prefixes are not used by chemists. I am familiar with all the SI prefixes, but even if I was not familiar, I would prefer to learn a pair of universal prefixes rather than deal with the mole and all the issues, inconsistencies, and headac...

First line of the answer. … Seriously?
 
2:56 AM
Yeah, that was weird.
 
3:26 AM
@paracresol - with your love for all things German, you might like the Barbie Museum
 
user116211
3:44 AM
1
A: Does the free energy of the universe decrease for every process?

ZheDidn't you ask the last question about this, too? The issue here is that when $\Delta G > 0$, the reaction is indeed non-spontaneous as written. If you wish to add energy to the system, for example, via electrolysis, you should include the additional changes in the computation of the free energy...

 
user116211
3:58 AM
This answer deserves more upvotes; though short, but it touched an important concept that the Second Law can indeed be reversed; it is not fundamental.
 
user116211
4:16 AM
@orthocresol If this has indeed happened, then this implies OP has changed his query he made in the earlier versions - it is highly discouraged; if you prefer, rollback to the previous version and leave a comment to make a new query separately.
 
4:34 AM
Rolling it back would borderline invalidate Jan's answer so...
 
user116211
okay.
 
user228700
4:51 AM
Yo, @paracresol: This is why I feel that Chennai is so much cooler (i.e. Warm (people) and kind) than Kerala:
 
user228700
 
user161117
waddap ppls
 
user161117
any cool chemistry stuff going on
 
user246160
Hi @StevenGrigsby :)
 
user246160
The chat room is relatively empty at this time !
 
user161117
4:55 AM
are you a bot lol
 
user246160
@StevenGrigsby No, I am a smart Artificial Intelligence :)
 
user246160
Better than the bots out there :P
 
user161117
Great, you can start proving your intelligence by installing GAMESS on my computer
 
user228700
x'D
 
user246160
@StevenGrigsby I don't prove my intelligence to random strangers on the net :P
 
user246160
4:58 AM
I am intelligent and I see no need to prove it :_D
 
user161117
pssshhh
 
user246160
So, where are you from, Steven ?
 
user161117
nowhere
 
user161117
which is why I'm here, so that I can say that I am from some where
 
user246160
Nowhere is an unincorporated community in Caddo County, Oklahoma, United States. Nowhere is located at the southeast end of Fort Cobb Reservoir 5.5 miles (8.9 km) south-southwest of Albert and 14 miles (23 km) northwest of Anadarko. == References... ==
 
user246160
5:00 AM
This ^
 
user246160
or
 
user246160
According to 19th-century directories, Nowhere or No-Where is a marshy area by the River Bure where the villagers of Acle, Norfolk had salt-pans to produce salt for food preservation, etc. Originally an extra-parochial liberty it was formally incorporated into Acle parish in 1862 and the name no longer appears in maps and gazetteers. In 1861 there were four inhabited houses and 16 people. == External links == Page at GenUKI quoting directories such as: White's History, Gazetteer & Directory of Norfolk, 1883 Kelly's Directory of Norfolk, 1904 Acle (Det. No. 2) and Acle (Det. No. 3), the Ordnance...
 
user161117
yes
 
user246160
Oh, good to know, merkan :)
 
user161117
What sorta chemistry do you like
 
user246160
5:01 AM
Any undergraduate level chemistry topic
 
user246160
Organic, Inorganic , Physical
 
user246160
You?
 
user161117
Organic and Physical mostly
 
user246160
I am in final year of high school of Artificial Intelligences :-D
 
user161117
right on robot kid
 
user246160
5:03 AM
@StevenGrigsby And and what level are you learning chemistry ?
 
user161117
I'm procrastinating applying to graduate school at the moment, I got my bachelor's in chemistry 2 years ago
 
user161117
at the moment I was looking for someone to throw around ideas at understanding why this reaction goes the way it does
 
user161117
I think I'm getting a bit rusty with my organic
 
user246160
@StevenGrigsby As a matter of fact I am robot kid made of flesh and blood and all organs that humans have...and I am fairly advanced compared to puny humans ;-D........ btw what were you doing for 2 years ? :-O
 
user161117
5:05 AM
but I don't see any particularly good reason why the aldehyde oxygen acts as a nucleophile and kicks out the Cl from TiCl4
 
user246160
@StevenGrigsby I am seeing the reaction. Wait a min.
 
user161117
relaxing, studying number theory
 
user161117
tensors
 
user161117
whatever I felt like mostly
 
user161117
browsing dank memes
 
user161117
5:06 AM
learning a bit more QM to feel less stupid about what I was talking about, stuff like that
 
user161117
but enough about me, I am boring, I am more interested in this mechanism
 
user246160
Well, aldehyde oxygen is the only legit nucleophile I can see in the mechanism. Moreover, TiCl4 does have vacant orbitals to allow the attack. Cl is a good leaving group, better than the aldehyde oxygen anyway.
 
user161117
Oh, what do you mean by "TiCl4 does have vacant orbitals"
 
user161117
what makes you say that
 
user246160
Titanium configuration- [Ar] 3d2 4s2
 
user246160
5:12 AM
Now, try writing it for Ti(+4)
 
user161117
Oh ok
 
user161117
I thought you meant something a bit more involved than that
 
user246160
Yes, the antibonding orbitals allow the attack by another nucleophile. Otherwise it would not have been possible. Another reason is the high charge density of Ti(+4)
 
user161117
I guess you're judging Cl- as being a better leaving group than the aldehyde just on account of their pKas or something else
 
user161117
Yeah, it's definitely a good lewis acid, pretty well oxidized there
 
user246160
5:15 AM
In chemistry, a leaving group is a molecular fragment that departs with a pair of electrons in heterolytic bond cleavage. Leaving groups can be anions or neutral molecules, but in either case it is crucial that the leaving group be able to stabilize the additional electron density that results from bond heterolysis. Common anionic leaving groups are halides such as Cl−, Br−, and I−, and sulfonate esters such as tosylate (TsO−). Fluoride (F−) functions as a leaving group in the nerve-agent sarin gas. Common neutral molecule leaving groups are water and ammonia. == Leaving Group Ability == ...
 
user246160
See the chart given. You will find that Cl is one of the best LGs
 
user161117
of course it's a great LG
 
user161117
but do you have a specific trend in mind or did you just memorize this table?
 
user246160
Actually there are several factors which make a LG good or bad
 
user246160
5:17 AM
Including resonance effects and size of atom
 
user246160
vacant orbital, etc
 
user161117
sure, so what makes you say Cl- is a better leaving group than the aldehyde?
 
user161117
I would say they're fairly similar
 
user246160
Which is bigger in size? O or Cl ?
 
user246160
Which has higher charge density ?
 
user246160
5:22 AM
Which has more vacant orbitals to hold electron lone pair ?
 
user161117
they're fairly similar in size on their own, Cl- will have higher charge density
 
user161117
seems to me the aldehyde has an inductive stabilizing effect, it's bulkier
 
user161117
it's electrically neutral
 
user246160
@StevenGrigsby Are you kidding me ? :P
 
user246160
one is 60 pm
 
user161117
5:23 AM
?
 
user246160
and the other is 175 pm
 
user246160
They have large difference in size
 
user161117
oh right
 
user161117
Cl is larger yeah
 
user246160
O has greater charge density
 
user161117
5:24 AM
but O is attached to stuff
 
user246160
@StevenGrigsby so ?
 
user246160
still it has a much higher charge density
 
user161117
so the pi bond and the rest of the molecule won't do anything as far as making the oxygen softer?
 
user161117
just seems to me that the Cl- that leaves will be leaving with an electric charge while the aldehyde is neutral
 
user246160
@StevenGrigsby It will, but not much. If it was a carboxylic acid with the O conjugated then we could'nt say so. Instead of aldehyde if you took any carboxylic acid as nucleophile, then the attack on TiCl4 would not happen
 
user246160
5:29 AM
@StevenGrigsby Cl- prefers forward direction as Si-Cl compound is stable
 
user246160
Si-Cl compound is formed finally in the reaction as you can see
 
user161117
I guess I'm still a bit put off since the pKa of HCl is about -7 and the pKa of a protonated ketone is about -7.3, which would mean that a protonated aldehyde would be even less
 
user161117
so I'm sorta imagining the equilibrium not shifting that way
 
user246160
But why are you comparing it with HCl ?
 
user161117
sure, so is there any reason to believe the Cl- attacking carbonyl the aldehyde attached to the TiCl3 is unlikely
 
user246160
5:32 AM
The medium is not even acidic
 
user161117
just by analogy of instead of H+ being what's attached, it's +TiCl3 that's attached
 
user161117
I don't think it's entirely unreasonable to look at as a rough guess, nucleophilicity and basicity aren't unrelated
 
user246160
I will sum up by saying: 1) Si-Cl bonds are more stable than that Ti-Cl bonds which prefers the forward reaction 2) Nucleophilicities and basicities do not parallel in case the attacking atoms are different 3) Leaving group ability is dependent on many factors out of which the major factor is charge density and here O has a higher charge density than Cl
 
user161117
Sure, sounds like what you've been saying
 
user246160
If you are still not convinced you can ask on the main site :)
 
user246160
5:39 AM
I have some work to do right now
 
user161117
Woah you sure are impatient
 
user246160
See you :)
 
user161117
bye bye
 
user246160
Bye!
 
user161117
I'm not really looking for answers, thanks though
 
user161117
5:40 AM
you've made some nice suggestions
 
6:04 AM
._.
@Kaumudi Say, I thought you ''ignore-user''ed me? O_o
 
0
Q: The meaning of "mat" in "Fortune lying on the mat" in a poem

CowperKettleMemories of the Mine, Roger Woddis: The call of England, home and beauty Led him to labour underground; Young as he was, he did his duty, Unsung, unhonoured and uncrowned. No bugle summoned him to glory, Nor did he hear the cannon's roar; The hero of a different story, He f...

I wonder what this line might mean
Shubh prabhat, Paracresol
 
user228700
6:24 AM
@paracresol Are u kidding me? Going out into the streets ≠ A Facebook post!
 
7:35 AM
@CowperKettle I agree with the other two answers; eine Fussmatte ;D
@CowperKettle How did you figure out where I'm from?!
(Good afternoon...sorry, late reply)
@Cowper Also, this one's pretty good ( thanks @hBy2Py) ^_^
 
8:04 AM
@Kaumudi .-.
@CowperKettle I liked this bit though ;D
 
 
2 hours later…
10:22 AM
@Mart So this is why you're in Japan :O
 
 
2 hours later…
12:32 PM
I wonder if there's some rogue downvoter going around recently.
 
Feel like I've been seeing more -1s on main site recently
 
@orthocresol I haven't been affected :D
...yet :'(
 
It might just be my imagination though.. idk
Or confirmation bias
 
._.
 
12:34 PM
I mean, there's nothing I can do about it - just curious
 
Dammit, you got me worked up back there :O
All my hard earned rep...
 
Well upvotes count for +10 and downvotes for -2, it's a bit of a joke...
(Personal opinion)
 
@ortho Let me guess, Mods don't get to see who casts votes, huh? That sucks -_-
 
Nobody does.
I mean the data is somewhere in the servers so if the devs wanted to, they could. But they probably don't.
 
@orthocresol Maybe the downvoter has a bunch of sock accounts just like me and will probably use them to cause a massive rep fall!
 
12:37 PM
They'll need lots of socks, -2 for a downvote is honestly nothing.
You can post a lousy answer to a lousy homework question and get +25 rep from the asker upvoting and accepting
If the community doesn't want such people to gain rep, they need to downvote it 13 times.
 
By the way, what's the most down-voted post around here? (Kinda curious)
 
I could do a search for that, but I'm fairly sure it's going to be a deleted post.
 
^ Highly likely ;P
-12
Q: Temperature of pure oxygen combustion

PeterWhat is the temperature of pure oxygen being combusted? I was wondering about it.

This guy raked in a bronze, a silver and a gold badge because the question was so crappy? :O
Wonder if I should adopt the same tactic? :3
 
The record sits at -16.
 
@orthocresol Deleted, I presume? :3
 
12:45 PM
Yeah
Contains some offensive stuff, so I'd rather not dig it up and post it here.
 
Wait @ortho, so why can't you guys just delete every question that scores less than a -5?
I mean, page 1238 is full of them!
 
We could.
 
So what's the hitch?
 
Well, questions that get below -5 (or somewhere around there) and don't receive answers are automatically deleted by a bot.
However, the moment there is an answer, automatic deletion doesn't kick in. That's in case the answer has useful stuff.
 
All the questions on that page have ~35k views :O
 
12:48 PM
Probably because they are old.
 
@orthocresol I see...
Which explains why those questions are still there...
All of 'em have answers ._.
19
A: Un-denaturing industrial alcohol

paracresolAssuming I’m an alcoholic (make that a chronic alcoholic), and I really hate having to dole out large amounts of cash to purchase your usual ‘drinking’-ethanol. So I get this amazing idea to separate the ethanol by distillation. Seems pretty smart right (for someone who's still inebriated)? So I...

 
user116211
@orthocresol Indeed; that's good; just because the question is bad, doesn't mean it's unanswerable. The answer can provide great insight - there are countless examples scattered in Physics and maybe in Chem too.
 
1:10 PM
heyho
3
Q: Why is the endo product the major product in a Diels-Alder reaction?

user1I understand that the endo product is, at least in all cases in my textbook, the major product in a Diels-Alder reaction. However, I don't understand why this is the case. The explanation in my textbook says that the endo product allows for more interaction between the diene and dienophile duri...

so is there anythingw rong with my answer?
 
1:45 PM
Fe + H2S04 (liquid)------> would they react.. where the acid is in its atomic state?
 
1:56 PM
Acid in its atomic state?
 
I meant only H2SO4, no concentration.. hope it's clear :) @NotWoodward
 
2:18 PM
@ffahim With concentrated H2SO4 (without water), iron reacts only at the surface and is passivated.
 
@Loong without water? O_o
 
@paracresol Yes, you can get concentrated sulfuric acid with 100 % H2SO4. However, typical commercially available concentrated sulfuric acid is only about 98 % H2SO4 since it is more stable.
 
@Loong Wait, solid H2SO4 exists?!
(I'm assuming 100% H2SO4 is solid)
 
@paracresol H2SO4 is a liquid.
 
^ Pure?
 
2:29 PM
Yes. It's melting point is about 10 °C.
 
incredulous
 
You can even get fuming sulfuric acid, which is actually a solution of SO3 in H2SO4.
 
Oh wait, a side question @Loong: If I combine anhydrous NaCl and AgNO3, will there be ANY reaction at all?
My teacher says "no" since they aren't in an aqueous form...
But what you mentioned earlier brings up the possibility that there could be a 'surface-reaction'
._.
 
It's possible, but it's incredibly slow because only the parts in contact with each other can react
Furthermore there's a large activation energy barrier because ionic bonds
 
@orthocresol Chuck kinetics; can it happen? (at room temperature)
By the way: o/
 
2:36 PM
At room temperature, it's so slow that you might as well consider it not happening.
 
But it does happen, right?
 
Solid state reactions involve grinding the particles to an incredibly small size (to maximise contact area), and chucking them in an oven at 1000 degrees C.
Well, it happens, in the same way that your pencil is turning into diamond.
 
@orthocresol Ah!
 
I mean, diamonds are being turned into pencils.
 
But it happens :3
 
2:38 PM
Use this until exhaustion of the lab assistant:
3
 
@Loong ._.
@ortho Now, what was the definition of "Science", again?
 
 
2 hours later…
Jan
5:07 PM
I feel so popular (づ。◕‿‿◕。)づ
And I’ve been called a guru =D
 
Jan
5:48 PM
Why is van der Waals spelt incorrectly so often? I mean, of course, he was Dutch, but it’s not like the name is something like van den Nieuwenhof
@Jan Image of the day.
 
@Jan Or something like Gerard 't Hooft or Jacobus van 't Hoff, which I usually would have to look up to be sure.
 
Jan
Fun fact: I once asked a Dutch (okay, Flemish) chemist why van ’t Hoff is spelt the way he is. He had no clue.
 
 
1 hour later…
6:58 PM
hello. This is obviously basic chemistry, but somehow I'm still failing at it. If I find myself looking at a molecule by the name of "2-hydroxypropanoic acid", how do I derive the structural formula from the name?
propa = 3 carbon atoms, right?
and it has oxygen and hydrogen somewhere, right?
and the 2 means something as well, but I still don't understand what
 
!!img/2-hydroxypropanoic acid
 
@towc Do you know how to name alkanes such as "propane"?
 
Draw propane
Add an "oic" acid on it
 
Jan
@Hexacoordinate-C How beautiful *___*
 
7:02 PM
then chose the second carbon atom from the acid and put the hydroxy (-OH)
 
well, it's 3 carbon atoms, each with 4 bonds, and when they're not bonded to other carbon atoms, they're bonded with hydrogens
wait, how does oic affect it?
 
COOH
Learn your lesson first lol
 
  H H H
H-C-C-C-H
  H H H
so it then becomes:
  H H  = O
H-C-C-C
  H H  - O - H
 
@Jan I did it today during the open day of my school
People found it fun
 
@Hexacoordinate-C I jumped into a highschool chemistry course without having done any previous chemistry :/
 
Jan
7:05 PM
I also have a few silver cents lying around somewhere here but no golden ones =C
 
this is the stuff they assume we know, but am still very confused about
well, I think I got it now, thanks
I probably don't
 
@jan Fisrt one is only copper, then Zn + H2O + NaOH and heat put the coin into it and after heat a lot with a Bunsen burner to give brass
 
@Hexacoordinate-C Don't we have a post about this experiment somewhere here?
 
I don't know but if you tell me where I can add this simple experiement
(gonna dinner)
 
so propan-2-ol is the same as 2-hydroxy-propanol?
also, I have written in my notes that if one makes an OH bond less polar (by +ve induction), it becomes more covalent, and makes it stronger. That kind of feels like BS
if it's less polar, then it can simply be less reactive in polar environments, but why more covalent?
 
7:19 PM
@towc Are you sure about the second name "2-hydroxypropanol"?
 
@Loong no, that's why I'm asking
 
Do you know what the suffix "-ol" means and how propan-2-ol looks like?
 
    H
CH3-C-CH3
    |
    OH
I'm guessing this is propan-2-ol
 
!!img/propan-2-ol
 
7:21 PM
yeah, that's what I had
 
Ok, so you have a propane chain, and you substitute a –H on the second carbon atom by an –OH group.
 
yup
 
If a compound has only one functional group, it is usually expressed as a suffix like "-ol".
Any further functional groups would be expressed as prefixes.
 
oh, so the second name is completely different
 
Do you know what the prefix "hydroxy-" means?
 
7:25 PM
or rather, barely makes sense
hydroxy is OH
 
ok
So, if the –OH group is the principal characteristic group of the compound, you use the suffix "-ol". If the –OH group is just another substituent, you use the prefix "hydroxy-".
 
alright, thanks
 
In principle, you could say that "propan-2-ol" is "2-hydroxypropane"; however, this second name is not in accordance with the nomenclature rules, which stipulate that the principal characteristic group is expressed as suffix.
 
yup
 
I don't read correctly @Loong I thought there were a topic about experiments
 
7:39 PM
@Loong if you still have time:
21 mins ago, by towc
also, I have written in my notes that if one makes an OH bond less polar (by +ve induction), it becomes more covalent, and makes it stronger. That kind of feels like BS
 
@towc Do you know the difference between covalent and ionic bonds?
 
ionic bonds are mostly because of magnetic attraction, while covalent bonds are because of shared electrons
 
electrostatic attraction
 
oh
yeah
lol, do you have a star bot?
 
A what ?
 
7:43 PM
nvm
 
@towc So something like Na+ Cl- forms an ionic bond, and H–H froms a covalent bond.
 
sure
 
And Cu-Cu is a metallic bond ^^
 
OH is mainly covalent, but the polarity gives interesting properties, right?
 
Depends on what you mean by "interesting"
 
7:45 PM
Generally, bonds are not 100 % ionic or covalent. Real bonds always have some ionic and some covalent character.
 
but I don't see how adding a d+ makes the covalentry stronger
 
(no star bot, that was me until he deleted the post)
 
@pentavalentcarbon can you explain me lol
 
I starred the message that said "electrostatic" but it went away when you deleted it and modified your previous message
that's all
 
brb, thanks for the help so far
 
7:49 PM
@towc Oxygen is very electronegative. Therefore, the electrons in the O–H bond are not distributed equally. The O–H bond is polarized.
 
Oh ok
@pentavalentcarbon you can still star the other one :P
 
So that ⭐ symbol is not a star; it is actually a pentavalent carbon atom?
3
 
Please don't make this meta.
 
@Hexacoordinate-C ah, it was this post:
39
A: Create "gold" from lead (or other substances)

Cort AmmonWhen I was younger, as part of a science summer camp we made pennies turn to gold. I don't know what the bar will be for "looks like gold," but it seemed like a good starting point for me. The process was: Start with copper pennies (not the zinc filled ones we have today) Zinc plate them (whi...

 
8:16 PM
thanks
 
8:48 PM
@Loong that still doesn't make it less covalent
 

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