@Sektor I'm afraid I bring bad news... I tried QQ, email, onsite chat and direct phone call, none of them received any response.
Also my engineer friend said this kind of old and rare connectors are nearly impossible to find.
Another discouraging clue is that I found the mainpage of the same company hosted on Alibaba, they don't show your connector there. (Also they leave the same contact information there so I was unable to reach any real human being..)
@Silvia Damn ... Well, thank you, a lot, for the effort you put in ! If we meet @ WTC you've got a beverage of any kind from me :D
@OleksandrR. I don't think there is... Which SATA connector are you referring to, specifically ? I don't have the pin spec on the top of my head, but will have to make sure it is compatible at the end of the day.
@OleksandrR. And another thing -- I don't want to take apart the computer and/or use pogo pins or soldering. I just need a serial connection, that's all :D
@OleksandrR. It is a project, but I don't want to turn it into an even bigger hardware one :D But in any case this will happen -- I am waiting for a GoodFET and will prolly try to flash its ROM, etc
@Silvia No worries; You have clearly done more than enough |^^
@OleksandrR. And also -- Why do I think the eSATA had 7 pins ? The Honda I am referring to is a 9 pin connector
@Sektor oh, yes, you're right. Sorry, in the drawing it only shows 6 pins clearly. Another similar connector with enough pins would be an HDMI or DisplayPort connector. Apart from that I can't think of anything else
@OleksandrR. The HDMI won't fit; The one doesn't have lots of space. It's good -- the hunt for something rare from the computing history, the wait, etc., but on the other hand -- nobody producing it, a few people selling it, have to buy in bulk. It's just a headache at one point
@Sektor it's an American garden hose fitting. 1 1/16"-11 1/2, not used anywhere else in the world, and in America not for anything apart from garden hoses (and lasers, apparently)
@William Aehm, nope. As long as there can be money made with it, this is surely not going to happen.
There is of course the possibility that Mathematica 15 is so unusable, unstable and full of bugs, that no one uses it anymore. Then there is the chance of the same outcome as with Macsyma.
History suggests that the marked share of WRI needs to drop below 1% for this to happen :-)
How can I rotate these curve such that all my end points lie on the same plane (i.e. x-axis)as the starting point, without changing the basic nature of these curve: imgur.com/0k9rjgy
If you mean the pipe fitting, don't worry about it. If you just wanted to know, the garden hose thread spec is 1 1/16" OD, 11 1/2 TPI. ;) It's a really bizarre specification and I don't know why they chose these odd numbers for it.
@psimeson I don't follow. Do you just have the image or what?
@OleksandrR. ToPolarCoordinates should suppose to do what you are saying but since I have origin as my coordinates and ToPolarCoordinates breaks at that point
Hey guys, this is driving me insane, why is CoordinateTransform["Polar" -> "Cartesian", {2, 4}] giving me the error CoordinateTransform::bdpt: "Evaluation point {2,4} is incompatible with the coordinate assumptions of the specified coordinate chart."
@Murta I don't understand what that means, "and graduate students" seems like such a diverse group of people that it doesn't fit into what I think it means :P
(wouldn't understand it if it were only physicists either, I'm afraid)
@psimeson well, I didn't really mean using any specific function. ToPolarCoordinates is new in 10.1 but I'm using 9 at the moment. You can move the origin easily enough. Or, yes, apply a rotation matrix to the points, after you figure out the angular separation of the first and last points
@Sektor I have one on the way from America. And today I ordered another from Amazon from an American supplier, in case the first supplier delays more. But thanks anyway.
@Sektor the only two companies that seem to make these are Parker and Bosch. Each of them have enormous catalogues with tens of thousands of products... you'd love it ;)
Does anyone know a good way to interpolate a function in polar coordinates?
as in, I have a list of pairs {theta, r} and I essentially want to join each point to the adjacent ones, so if I give it a theta, it'll give me an r that's the best option
@YungHummmma yes; one evidently can do it, but to do it efficiently will be the trick. That's why I say it will make a good question (if you can be bothered to write it up as such--it takes a fair amount of effort, I know; sometimes more than just solving the problem independently)
@YungHummmma actually, Nearest takes DistanceFunction, so maybe it will not be so difficult after all
@William be careful what you type in the help search then. These get sent to WRI. If you're typing "Oh Stephen, your programming is amazing... I want to have your babies", I'm not sure if he'd be best pleased