I would say "yes", but that's just me

(@MartinSleziak)

I will certainly admit that differentiation is more natural if it is in the form $\sum(k+1)\binom nk$. Maybe there are other methods which are more natural in this form...?

Still, it seems rather easy to transform one problem to the other one.

Perhaps I could wait a bit to see whether somebody will react to my comment there.

This post is rather similar, too: How can I solve $\sum\limits_{i = 1}^k i \binom{k}{i-1}$.