Marcus Andrews

Try [1, 2, 3, 4, 5]

@Poke doesn't work with odd-length

same as every-other-letter from left to right and then the same wrapping around to the left (accounts for both even and odd)

shorter way to do this either in python or ruby? (s is a string):

print((s+s[::-1])[::2])

nvm found shorter ways

for a single hex sent in through stdin?

any way to do this without read n?

Or a bash method perhaps

Is there a shorter way to convert hex to decimal in ruby than p gets.to_i(16)?

impressive!

my best is

n,r=gets.split.map &:to_i
puts n.times.map{|i|i*r}*" "

also reading in the input

output would need to be same line

Shorter way in Ruby (<54 bytes, my best) to print n terms of an arithmetic sequence starting from 0 with common term r?


Input
6 2
Output
0 2 4 6 8 10

Input
4 0
Output
0 0 0 0

Would there happen to be a shorter way to do a,b=gets.split.map(&:to_i) in Ruby?

from what I can tell tr doesn't allow any reverse range workarounds without adding more chars anyway

does that work with my tr code?

e.g. if I am doing tr 01234 98765 I can do tr 0-4 98765 but it doesn't like tr 0-4 9-5 because the 9-5 is in reverse order

Hm is there a shorter way in bash to do a reverse range?

thanks Conor

ah perfect!

Hm or a shorter way to read in a sorted string in ruby other than gets.split("").sort ?

Given a line of space-separated integers, is there a short ruby method for finding the product of that list?

19

(at 28 currently)

Shortest way to count letters in a sentence using Ruby?

I guess you have to join straight from the map rather than each

(nvm I had to do puts gets.split.map{|k|s[k.to_i-1]}*"" but curious why the previous one didn't work)

(for a line of indices such as "5 3 1 4" etc)

is this not the right way to print out a join of chars from a string s by indices?

puts gets.split.map(&:to_i).each{|i|s[i-1]}*""

two lines: integer m, and then a line of space-separated integers -- is there a shorter way in ruby?

m=gets.to_i
p gets.split.map{|x|x.to_i%m}.sum

if g=="M", output 5/6 times w. If "F", 6/5 times w. Otherwise "UNKNOWN"

this is as far as I got

Is there a shorter way in Ruby to do the following?

g=gets.chop
w=gets.to_i
puts g==?M?w*5/6:g==?F?w*6/5:"UNKNOWN"

if just for one pair then
p gets.split.map{|x|x.to_i.to_s(2).to_i}.sum

61
gets.to_i.times{p gets.split.map{|x|x.to_i.to_s(2).to_i}.sum}

I tried to put the to_s(2).to_i stuff in the map but it doesn't like it

is my approach

gets.to_i.times{a,b=gets.split.map(&:to_i);p a.to_s(2).to_i+b.to_s(2).to_i}

then loop and print over each pair

you read in n, the number of pairs

I forgot to mention that it's over a list

i'm at 75 char ruby atm

any shorter way to do this one in python or ruby?

take in two numbers (one line, space-delimieted), convert to binary, and add them as if they were decimal.

input: 13 89
output: 1012102

has to be case insensitive

46 ruby

my current best: print(*(sum(l.lower()in"aeiou"for l in w)for w in input().split()))

(in either python or ruby?)