hansika

Goodnight! Take care guys! <3

All the best for JEE advanced y'all! Don't take too much stress, y'all will do great!<3

@Wolgwang ayooo <3

@Wolgwang It's complicated, it seems worth it at times, it sucks at times, know once you get in here! ;)

@Wolgwang You don't need to give me a proper goodbye, I will keep coming back!

@RajdeepSindhu nooo T_T

@Wolgwang i came back, i didn't :(

@HopefulWhitepiller to me too!

@Wolgwang trust me, they won't get wasted!

@Wolgwang yeah, it is gonna reflect! you should be very proud of yourself honestly at this point for surviving jee! and never giving up!

@RajdeepSindhu your skills will show up :)

@RajdeepSindhu yes yes, dw about that..you'll get a good IIT :)

@RajdeepSindhu it does perhaps ;)

@Wolgwang seeing your mains and everything, you'll be at a good position even if you fuck up the exam..so just chill as of now ;)

@RajdeepSindhu ahaan

i don't remember when I changed it :')

@RajdeepSindhu you got this!

@Wolgwang Hola! How you doin?

@RajdeepSindhu both!

I would like to see you at IIT-Delhi, if you'd chose it over bombay?

@RajdeepSindhu damnn, @Wolgwang killing!

they're literally going to ask us what is welding and stuffs

@RajdeepSindhu "majdoori"

@RajdeepSindhu oo lala..i'll be careful😂

@RajdeepSindhu End sem exams coming! I have one tomorrow :')

@RajdeepSindhu don't want to disappoint anyone here, but it's all a fuckin' lie :)

@RajdeepSindhu me everyday :')

hbu? serious about advanced yet?

@RajdeepSindhu lessgooo!

@RajdeepSindhu i guess, he did seem to be very tall!

@RajdeepSindhu yeah!!

wassuupp you guys?

@RajdeepSindhu yeahh lmaoo

@RajdeepSindhu I am!

nvm i got it!

In this answer how is $\frac 18(f''(c_1)-f''(c_2))$ written as $\frac{2A}{8}$

happy new year everyone!!

@BoxBoxBoxBox take care!

I just hope I don't fail

I fucked up my mid sems big time T_T

@BoxBoxBoxBox that has become such a normal thing here :')

@Wolgwang wanna meet up sometime?

@Wolgwang aah.. nice

thank you sir :)

ohh okay..got my mistake

yes

In c part..Shouldn't the recoil kinetic energy of electrons be 150+0.25? Since the energy of incident photons is 150 and the resting energy of electrons is $mc^2$ =0.50 MeV, so energy before conservation is 150+0.50 MeV, after conservation energy of scattered photons is $(mc^2)/2$=0.25MeV so recoil kinetic energy= 150+0.50-0.25?

@JohnRennie Hi sir :)