I have a doubt:
We have a pair of linear equations
(a1)x + (b1)y + c1 = 0 say equation-1
(a2)x + (b2)y + c2 = 0 say equation-2
If we multiply equation-1 by b2, equation-2 by b1 and subtract them we get:
x = (b1c2 - b2c1) / (a1b2 - a2b1)
Similarly we can get
y = (c1a2 - c2a1) / (a1b2 - a2b1)
I get stuck when (a1b2 - a2b1 = 0) i.e. a1/a2 = b1/b2
When this is the case 'x' becomes '(b1c2 - b2c1) / 0' therefore should be undefined.
The problem is, when a1/a2 = b1/b2 = c1/c2 and (a1b2 - a2b1 = 0)
