code_report

However, in APL I get:
(0⌈+)\¯2 1 ¯3 4 ¯1 2 1 ¯5 4
¯2 0 0 0 0 1 2 1 2

Is that the simplest way? : (
I was hoping something like the PSI combinator (⍥) could be use here ... but it doesn't look like it
(⌈⍥⊃∘⌽)/↓,∘≢⌸1 2 2 6 6 6 6 7 10

Say I have a nested array:
↓,∘≢⌸1 2 2 6 6 6 6 7 10
┌───┬───┬───┬───┬────┐
│1 1 │ 2 2│ 6 4│ 7 1│ 10 1│
└───┴───┴───┴───┴────┘
How do I take the "maximum sub array" by only comparing the 2nd element. So the answer would be:
6 4

Say I want a snippet of code that gives me a 26 element array for letter frequency, i.e.:
{+⌿⍵∘.=⎕C⎕A} 'bcd'
0 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
However, if you pass this a one letter string, you get:
{+⌿⍵∘.=⎕C⎕A} 'a'
1
How do I avoid this?

Can anyone show me the comprehensive solution for this problem? https://leetcode.com/problems/excel-sheet-column-title/
I initially thought it was super easy: convertToTitle ← {⎕A[26(⊥⍣¯1)⍵]}
But this fails for the case of 701 because inverse decode yields 1 0 25 instead of 26 25.

A is mine
B is hyper neutrino

a s → 4.6E¯6 | 0% ⎕⎕⎕⎕⎕
b s → 3.9E¯5 | +742% ⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕
c s → 1.7E¯5 | +263% ⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕⎕