I did talk to the professor about this, and he is quite adamant. He asked me to think about the infinite broom and topologist's sine curve (which quite literally is a counterexample) and come up with an answer
I was able to prove this for piecewise continuously-differentiable but I don't see in what sense of the term piecewise continuous does this theorem hold
There's a theorem in my lecture notes that says, "All piecewise continuous curves [in a closed and bounded interval] are rectifiable". Isn't that wrong? Counterexample: $f(x) = x \sin(1/x)$ for $x \ne 0$ and $0$ for $x = 0$
I'm sure that something similar has been asked on main before, but how exactly do I use residues to evaluate the integral of sin(x)/(1+x^2) from 0 to infinity?
And Discrete Fourier Transform is pretty cool. There's a lot of stuff that I think I'm missing out on, and I guess I should pick up on it this semester.
This means that we're looking at x in the interval [-2, 0] (since we have the condition x <= 0). Now in this interval, |x| = -x since x <= 0. So it wants to know for what x is f(x) = -x in [-2, 2].