The Crusade of Answers

Our menace: the Unanswered queue. Our goal: total annihilation...
May 11, 2014 21:02
I was reviewing some close votes, and this came up: http://math.stackexchange.com/questions/263919/delta-subset-phi-is-a-base-in-a-root-system-imples-delta-vee-subset-ph
So how are we to deal with these questions where--1. old question, perhaps highly upvoted but has no answer, 2. along with newer duplicate question which does have an answer
Apr 28, 2014 08:07
How to deal with this question? math.stackexchange.com/questions/771521/…
Oct 25, 2013 06:54
That's too bad there's been such a massive increase in traffic. I really wanted to see this room succeed.
Aug 18, 2013 03:27
@Lord_Farin I'm a bit confused by that...can you explain what you mean?
Aug 15, 2013 02:58
Has anyone been keeping careful records of the unanswered # and total # over time? It would be nice to see our progress.
Aug 7, 2013 00:05
@AlexanderKonovalov Yeah, but just two days ago it was at 24,000.
Aug 5, 2013 01:00
Take #68876 for example.
Aug 5, 2013 00:58
What should be done with crossposted duplicates? Should there be a way to "mark as duplicate" if there's a correct answer at mathoverflow?
Aug 5, 2013 00:41
CW answered: $45207$
Aug 5, 2013 00:18
Should #122291 be closed (too old to migrate)?
Jul 7, 2013 23:32
How should we address #141491: correct answer was given by OP in an edit, incorrect answer was posted as an answer?
Jun 13, 2013 21:24
12 follows from $9$ immediately, just universal generalization and the definition of subset.
Jun 13, 2013 21:23
So just substitution $5,8$ actually.
Jun 13, 2013 21:22
And step 9 follows by $Y \in F \to \exists x,y: Y = \langle x,y \rangle \land \langle x,y \rangle \in F$
$\to \exists x,y: Y = \langle x,y \rangle \land \langle x,y \rangle \in G$
$\to Y \in G$
Jun 13, 2013 21:20
@Lord_Farin Part 2, step 7 should read $\langle x,y \rangle \in F \to \langle x,y \rangle \in G$.
Jun 13, 2013 21:17
Sorry for putting you through that.
Jun 13, 2013 21:17
@Lord_Farin Wow, a lot more than I thought it would take.
Jun 13, 2013 03:51
@user79365 If there were a way to star an answer without sending it to the RSS feed, I would.
Jun 13, 2013 02:33
@Gmath This room is not intended for asking math questions. If you want an answer, I recommend going to the main math room or asking your question on the main site.
Jun 12, 2013 21:49
23796 unanswered right now!
Jun 11, 2013 21:24
@JulianKuelshammer I agree. I wanted to see what other people thought.
Jun 11, 2013 21:20
Do you think we should use this room to coordinate close votes?
Jun 11, 2013 07:52
@Lord_Farin Sorry...out of votes for the day. But I will upvote it tomorrow if someone else hasn't by then.
Jun 10, 2013 09:15
Jun 10, 2013 09:14
CW post: #252529
Jun 10, 2013 03:33
Comments can be converted into an answer: #412812
Jun 10, 2013 03:31
Comment promotion from @BrianM.Scott? #127044
Jun 9, 2013 10:54
@user79365 Helpful, thanks
Jun 9, 2013 10:08
I'm out.
Jun 9, 2013 10:08
upvote request: #$414085$
Jun 9, 2013 09:38
Is there an explanation for this?
Jun 9, 2013 09:35
I just hit my vote cap at 33.
 
May 6, 2014 03:43
Do the same for *'
May 6, 2014 03:41
And 2x +' 2y = 2x + 2y - 4
May 6, 2014 03:40
So 2x-4 + 2y-4 + 4 = 2x +' 2y
May 6, 2014 03:40
2x = 2a + 4, so 2x - 4 = 2a. Similarly, 2y - 4 = 2b.
May 6, 2014 03:39
This doesn't give us any information yet--we want an expression for 2x +' 2y, so we have to make a change of variables first.
May 6, 2014 03:39
2(a+b) + 4 = 2a+4 +' 2b+4
May 6, 2014 03:38
f(a+b) = f(a) +' f(b)
May 6, 2014 03:38
Let's use +' for addition in our new ring R and *' for multiplication.
May 6, 2014 03:37
OK, so let's just go through this.
May 6, 2014 03:36
@D-Man OK, the answer has been updated in light of this.
May 6, 2014 03:36
@D-Man You're confusing unit with unity. $1$ is a unity, whereas you're giving the definition of a unit. $-1$ is a unit in the ring $\mathbb Z$ since $-1 \cdot -1 = 1$, but it is not the unity $1$.
May 6, 2014 03:36
The fact that it is even integers is irrelevant. The $1$ of $R$ is $f(1)$, since $f$ is an isomorphism. $f(1) = 6$. We don't solve any equations, (we only solve the equation $2x+4 = 6$ if we know $6$ is the $1(R)$ and we're trying to get the unity of $\mathbb Z$.
May 6, 2014 03:36
@D-Man then we are all in agreement.
May 6, 2014 03:36
@D-Man The answer still stands; just ignore the second paragraph.
 

 Mathematics

Associated with Math.SE; for both general discussion & math qu...
Jun 13, 2013 02:41
Or is it some feature I don't know about?
Jun 13, 2013 02:41
10K+ users?
Jun 13, 2013 02:41
Moderators?
Jun 13, 2013 02:41
So who actually reviews the flagged comments?