Bhavay

something like these : ^

The reason why I think it spoiled the divinity of the room.

@Mitra To adding to my point .. While film heroines also sang and danced, it was the vamp who wore more revealing clothes, smoked, drank, and sang sexually suggestive lyrics.[3] The vamp was portrayed as immodest rather than evil, and her dance performances were sexualized by male producers.

@Mitra I have never seen any such songs in the western films. Moreover wikipedia states : . The trend was started by Cuckoo in films like Awaara (1951), Aan (1952) and Shabistan (1951).

@Mitra I don't know what else do you expect me to say ?

@Mitra for the first part I think Wikipedia defines it perfectly : > In Indian cinema, an item number or item song is a musical number inserted into a film that may or may not have any relevance to the plot. The term is commonly used within Indian films to describe a catchy, upbeat, often provocative dance sequence for a song performed in a movie.

@Malavika Probably a little late ;p . Happy Holi to you too! :)

@Mitra Hi . I meant the visuals might be a little above PG-13 and can spoil the divinity of the room. I don't have any problem by the song (music/lyrics) as such :-)

Another composition based on Raag Des

+

hmm .. okay sir , I see if I have time left and then will do it

@JohnRennie by "this" you mean this ?

or my format is good enough?

@JohnRennie Sir do you think I should do this to all my codes .. this can take a little more time

sorry i missed the message

got it

yes

well we won't have 100 hundred of step integral in the exam

I mean group all the 4*f(k) together and 2*f(k) together

prnt.sc/22s0z48

I thought it would be nice i can make answer look like formula :

Sir so far it is doing pretty good .

// if h or step size is given , then n= upper-lower/h

#include<iostream>
#include <iomanip>
#include<cmath>
using namespace std;

// Define the fn whose integral you want to calculate
double f(double x)
{
double a=1/(1+pow(x,1));
return a;
}


// Set precision and intedentation

void print_num(float x, int width = 10, int precision = 10)
{
cout << setw(width) << setprecision(precision) << x;
}

int main()
{

// declare the variables
float lower_limit, upper_limit, integration=0.0, step_size, k;

btw yesterday code was fixed .. even the calculation part .

Sir I was editing simpson's 1/3 code ..

@JohnRennie Hi sir

@JohnRennie Sir

dy/dx= 1/0.2[[1.18+ 2(-2)+1] * 0.28/2+ [3(-2)^2 + 6(-2) +2 ]*0.01/6]

This is slightly wrong

dy/dx= 1/0.2[[1.18+ 2(-2)+1/2] * 0.28+ [3(-2)^2 + 6(-2) +2 ]*0.01/6]

Okay trying that..

I want to print that for every ques

then the values will change no

but what if I change the ques

currently it directly jumps to the final ans.

Yes

I want to print that calculation stuff

you see the image that I sent you

no

it already calculates the final ans

values calculated by eqn

I think I need to use cout in final for loop

Yes

One more thing sir..

That seems right