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@naturallyInconsistent thanks

@naturallyInconsistent also is it somewhat like the Kronig-Penney but the coefficients that is the r,t and i are undetermined here?

@naturallyInconsistent so at the end we are just imposing conditions of continuity at +- a/2?

@naturallyInconsistent So the solution in -a/2 <x< a/2 is just a general solution and may not contain sines and cosines? But how have the solution parts of psi_L and psi_R? They found solutions outside this region. Since the potential is greater than the energy in the region -a/2 <x< a/2, shouldn't the solution consist of exponential parts? I am confused how they are trying to solve it. If you could help me out from the basics that would be really helpful. Thanks

Could someone help me understand the solution discussed in ashcroft solid state? Chapter 8 problems, problem 1. I don't understand this solution . Why are they taking scattering states as the solution in the region -a/2 <x <a/2 ? Could someone help me understand the idea?

I am learning lagrangian mechanics from Goldstein's book and a few lectures from here and there. Any advice for a beginner?

Hey there!

@JohnRennie but here I don't think it is possible to write U as a function of only r, it will contain r_dot terms as well. I am doing this using Lagrangian mechanics

@JohnRennie Could you please explain more?

Hey guys, could you please help me solve this problem? I have been stuck for so much time. The problem is from Goldstein's classical mechanics book. It involves perturbation of a circular orbit however the answer given in the comment doesn't look right to me. physics.stackexchange.com/questions/758675/…