Moti Rattan Gupta

What is total volume of gaseous mixture containing 1.1g CO2 and 4.0g He at STP? I was getting wrong answer by applying PV= nRT with P=1atm, n= n(co2)+n(He),T=298K. Please help.

and my webcam is very poor

I'm on my laptop

@DivyankaChaudhari I'm sorry for not sending as currently I

But that energy must come from somewhere. That somewhere is actually the field. The field gives transforms its potential energy( interaction energy) into kinetic energy of the mass. As energy is lost by the field, therefore potential at that point is negative.

Abhinav, let us first look at what is grav. potential ? It is the potential energy associated with a unit mass to bring it from infinite separation to the given point. So, as we know that in classical physics, grav. force is always attractive, therefore it is the grav. field that is doing the work, not we as an external agent. As field field is doing the work, therefore it increasing the kinetic energy of that mass.

I might be able to help

Abhinav, what exactly is your question, can you repharse it?

Typing the whole solution is bit difficult

@DivyankaChaudhari Yes, please check out. It's a very good book. After doing it, you don't need any other book

@DivyankaChaudhari Do you have Cengage Current and Electricity volume? It's solution is present there

Can someone help me out?

This seems to be in conflict with Gauss' law

The question is that a cavity is located unsymmetrically in a solid non conducting sphere. The centres of the sphere and cavity are O1 and O2 respectively. The electric field of an inside point P in the cavity is found to be proportional to the separation between O1 and O2. But according to Gauss' law, net flux is generated by inside charges only but in reality we have taken the cavity to be empty( by defination of cavity).

ok. thank you.

Can someone help me on a problem on electrostatics? It's solution seems to go against Gauss'law?

That's not an issue, just replace down by up and up by down

Did you get what I said about free length?

on it

Ok. I'm not registered p

How can I post images in this chat room so that I can post the diagram of what I am saying?

Abcd, when the pulley m goes down by let say X, there will be two free lengths created and as the left end of the string is fixed, that string will be stretched from the man end which is movable