mikeazo

general recent conversations

Discussion on question by spoodledy: …

Imported from a comment discussion on workplace.stackexchange....

mikeazo

Feb 14, 2020 20:23

@nvoigt, no clue. Perhaps ask on Meta?

mikeazo

Feb 14, 2020 19:17

Need a moderator to lock the post so the OP stops self-vandalizing the post.

Discussion on answer by jamesqf: My p…

Imported from a comment discussion on money.stackexchange.com/...

mikeazo

Jun 12, 2019 20:17

fastweb.com/financial-aid/articles/…

mikeazo

Jun 12, 2019 20:17

See here

mikeazo

Jun 12, 2019 20:16

@GaneshSittampalam I think that may be after 24 years old or marriage. So OP could get married an then not have to use parent's income on FAFSA.

Discussion on question by CoedRhyfelw…

Imported from a comment discussion on politics.stackexchange.c...

mikeazo

Apr 3, 2019 05:58

Is your question about "capitalists" or "capitalism"?

The Side Channel

Mostly randomly generated noise. – crypto.stackexchange.com

mikeazo

Dec 3, 2018 21:21

Could use some more votes on questions to help push it along.

mikeazo

Dec 3, 2018 21:21

seL4

Proposed Q&A site for developers, maintainers, and users of the seL4 microkernel and systems running on top of seL4.

Currently in definition.

mikeazo

Dec 3, 2018 21:21

FYI, there is a new stackexchange proposed site that some here may be interested in.

mikeazo

Dec 3, 2018 21:20

Go for it!

mikeazo

Dec 3, 2018 21:20

@kelalaka I've definitely seen that in the past.

mikeazo

Feb 9, 2018 15:25

Why is it that I really want to respond with blockchain?

mikeazo

Feb 9, 2018 15:25

Q: Is there a cryptographic solution for this “dating protocol”?

The article Cryptographic Protocols with Everyday Objects by James Heather, Steve Schneider, and Vanessa Teague describes the following dating protocol (due to Charles Bennett): Alice and Bob wish to determine whether they both want to go on a date; but they want to avoid the embarrassing ...

protocol-design

mikeazo

Jan 31, 2018 17:58

@e-sushi I'll tell you in a few more weeks :)

mikeazo

Dec 20, 2017 18:22

With an upcoming challenge to find and exploit their backdoor.

Discussion on question by Thunderforg…

Imported from a comment discussion on law.stackexchange.com/qu...

mikeazo

Oct 30, 2018 19:52

If you file a provisional patent, then never file the real thing, would that make the USPTO more aware of it? Do they search previously submitted provisional patent applications?

Discussion on question by Mubee: Divi…

Imported from a comment discussion on crypto.stackexchange.com...

mikeazo

Feb 2, 2018 13:42

If you want to verify, do the math on the unencrypted values. (141*2.modInverse(n)).mod(n), that sort of thing.

mikeazo

Feb 2, 2018 13:41

No, I'm saying that as far as I can tell, you are getting the right answer. Nothing else to do.

mikeazo

Feb 2, 2018 13:39

What I'm saying is that what you think is a random number is not actually random. It is in fact the right answer. For example, in the numbers I wrote above, you might have seen 9 and thought "man, why I am I getting this random number 9, that doesn't make sense." But 9 is in fact the right answer.

mikeazo

Feb 2, 2018 13:37

Are you just getting a blank line? Or are you getting a random number?

mikeazo

Feb 2, 2018 13:36

So what are you seeing?

mikeazo

Feb 2, 2018 13:36

Or is your question more of how to modify the decryption function such that you get 70.5?

mikeazo

Feb 2, 2018 13:34

So in your code example, you are expecting that last System.out.println to produce 70.5?

mikeazo

Feb 2, 2018 13:28

I'm confused as to what you are expecting. What do you expect to be seeing?

mikeazo

Feb 2, 2018 13:24

Are you getting an exception or something when trying to decrypt?

mikeazo

Feb 2, 2018 13:24

So in the example I gave you above, you would decrypt and get 9. You'd see that and think, "that is not what I was expecting, why is decryption failing". When in fact, decryption is not failing.

mikeazo

Feb 2, 2018 13:23

You should be able to decrypt it. The decryption might just not really be what you are expecting.

mikeazo

Feb 2, 2018 13:21

Yep.

mikeazo

Feb 2, 2018 13:18

Does this all make sense up to now?

mikeazo

Feb 2, 2018 13:18

Notice that there are no decimal values in my original set ({0,1,2,3,4,5,6,7,8,9,10}), so you cannot get something like 3.5.

mikeazo

Feb 2, 2018 13:17

Now, where it gets tricky is if the sum is not divisible by 2. Let say instead you had 7*2^{-1} (mod 11). Well that is the same thing as 7*6 (mod 11), which is 42 (mod 11). And 42 is equivalent to 9 mod 11. So, 7/2 (mod 11) is 9. Not what you expected, right?

mikeazo

Feb 2, 2018 13:15

Which is the answer you would have expected, right?

mikeazo

Feb 2, 2018 13:15

So, 6*2^{-1} is equivalent to 6*6 (mod 11). 36 is equivalent to 3 (mod 11).

mikeazo

Feb 2, 2018 13:13

It is not 0.5, but rather 6.

mikeazo

Feb 2, 2018 13:13

What is 2^{-1} (mod 11)?

mikeazo

Feb 2, 2018 13:12

Consider this, say I am working in the integers mod 11. So possible value are {0,1,2,3,4,5,6,7,8,9,10}. Lets say I want to compute (2+4)/2 (mod 11). That is the same as 6/2 (mod 11), which is the same as 6*2^{-1} (mod 11)

mikeazo

Feb 2, 2018 13:10

anyways, back to your code. You are correct, dividing an encrypted value that is even by 2 will result in what you expect. Dividing an encrypted value that is odd will not result in what you expect, but it does result in what I expect.

mikeazo

Feb 2, 2018 13:09

@Mubee, in your question you state I was wondering is it possible to divide two encrypted numbers which results in decimal ?. I'm saying that it is not possible to divide two encrypted numbers. Now, in your code, you are not dividing 2 encrypted numbers, you are dividing the sum of 2 encrypted numbers by the plaintext value 2.

mikeazo

Feb 2, 2018 12:14

Even then, you will not get a decimal answer.

mikeazo

Feb 2, 2018 12:14

@Mubee, you cannot divide two encrypted numbers. You can only divide by an unencrypted number.

2018 Cryptography Moderator Election …

Open Discussion for crypto.stackexchange.com/election/2

mikeazo

Jan 29, 2018 20:41

Definitely not a formal requirement.

mikeazo

Jan 29, 2018 20:35

That said, the people here are pretty good about helping with the moderation.

mikeazo

Jan 29, 2018 20:35

always good to have more math folks :)

mikeazo

Jan 29, 2018 20:28

No more than a handful a week.

mikeazo

Jan 29, 2018 20:28

@MaartenBodewes That has definitely gotten less and less and tends to increase at the beginning of college semesters :)

mikeazo

Jan 29, 2018 20:26

~10-15

mikeazo

Jan 29, 2018 20:22

Including one order of magnitude more edits

mikeazo

Jan 29, 2018 20:22

@MaartenBodewes For the record, according to the current flag count, I've handled more than double the number of flags as e-sushi. :) (though he beats me in every other category).

mikeazo

Jan 29, 2018 20:15

The mod load is definitely not bad.

mikeazo

Jan 29, 2018 20:14

@MaartenBodewes The election is my fault. I decided that I was ready to step down. I've been at it 5 years now, so I figured I'd let someone else have a go.