Mathematics

Associated with Math.SE; for both general discussion & math qu...
Apr 19, 2017 18:47
Goodbye everyone
Apr 19, 2017 18:43
@Evinda euclidean algorithm
Apr 19, 2017 18:38
@Evinda yes
Apr 19, 2017 18:27
oh lol
Apr 19, 2017 18:26
why is that a projector
Apr 19, 2017 18:25
why?
Apr 19, 2017 18:22
I've never heard of it
Apr 19, 2017 18:22
@Semiclassical but thanks for introducing that lemma
Apr 19, 2017 18:20
@Semiclassical yes
Apr 19, 2017 18:19
@Semiclassical my approach is very ugly lol
Apr 19, 2017 18:15
@Trucy maybe you should study the equivalence relation "x and y have the same parity"
Apr 19, 2017 18:12
(since I have no idea
Apr 19, 2017 18:12
@BalarkaSen you might be interested
Apr 19, 2017 18:12
1
Q: Compute matrix determinant

lappen68Given $n\in \mathbb N$, how can I compute the determinant of $(a_{ij})_{1\leq i,j \leq n} \in \mathcal M_{n\times n}(\mathbb R)$ where, for each $1\leq i,j\leq n:$ $$a_{ij}= \begin{cases} \lambda &i=j \\ \mu & i\neq j \end{cases}$$ The only (or the only easy) way to do this I think involves using...

Apr 19, 2017 18:09
@AlessandroCodenotti and $\Bbb Z$ has more irreducibles, lol
Apr 19, 2017 18:08
but I don't know why it fails
Apr 19, 2017 18:08
I know how it fails
Apr 19, 2017 18:06
I'm more interested in why my "theorem" fails
Apr 19, 2017 18:05
@AlessandroCodenotti that's nice
Apr 19, 2017 18:02
if a polynomial $p$ with integer coefficients is irreducible in $\Bbb Q[x]$, then it must be irreducible in $\Bbb Z[x]$.
Apr 19, 2017 18:01
what amazes me is the falseness of the following "theorem":
Apr 19, 2017 18:01
I see
Apr 19, 2017 18:00
alright
Apr 19, 2017 18:00
$2 = -1 \times -2$ and $-1$ is a unit
Apr 19, 2017 18:00
@AlessandroCodenotti how is that contradictory?
Apr 19, 2017 17:56
@AlessandroCodenotti thanks
Apr 19, 2017 17:56
oh, never mind
Apr 19, 2017 17:55
I'm not understanding what it means
Apr 19, 2017 17:55
$\Bbb R$
Apr 19, 2017 17:55
sorry
Apr 19, 2017 17:53
I thought in R every element is a unit
Apr 19, 2017 17:53
i cannot write it as a product of two non-units
Apr 19, 2017 17:53
how is it not irreducible?
Apr 19, 2017 17:51
what does "up to units" mean?
Apr 19, 2017 17:51
in R[X], 2x^2-6x+4 = (2x-2)(x-2) = (x-1)(2x-4)
Apr 19, 2017 17:51
And I'm glad you came
Apr 19, 2017 17:51
@AlessandroCodenotti I'm having much trouble understanding all this
Apr 19, 2017 17:49
Right
Apr 19, 2017 17:42
@Evinda have you proved that (b,p^t) = 1?
Apr 19, 2017 17:41
UFD is every ... can be written as a product of irreducibles and unit
Apr 19, 2017 17:41
i mean
Apr 19, 2017 17:40
@Evinda well, k=1, but continue
Apr 19, 2017 17:39
and unit
Apr 19, 2017 17:38
@Evinda right
Apr 19, 2017 17:38
@BAYMAX define UFD
Apr 19, 2017 17:36
so is R[X] a UFD?
Apr 19, 2017 17:36
in R[X], 2x^2-6x+4 = (2x-2)(x-2) = (x-1)(2x-4)
Apr 19, 2017 17:35
@BAYMAX yes, Z5 is a field
Apr 19, 2017 17:35
namely, R[x]
Apr 19, 2017 17:35
if you still don't understand, let's move to another field that we are more familiar with