Rick

Can someone help in this question? I drew a diagram, but it gets very complicated..don't know how to proceed from there

Can someone help in this question? I drew a diagram, but it gets very complicated..don't know how to proceed from there

@AkivaWeinberger Thanks a lot! Got it now

oh ok..yes

desmos.com/calculator/xdiuor9kxx

hmm yes it does

I'm getting stuck using triangle inequality I wrote$ | |z|−|3-2i| | \leq |z−(3-2i)|$ so $| |z| - \sqrt{13} | \leq |z−(3-2i)| \leq 4 $ or $-4 \leq |z| - \sqrt{13} \leq 4 $ which gives $\sqrt{13}-4 \leq |z| \leq \sqrt{13}+4$ but that lower bound is negative.. ? should I take the lower bound as 0 instead? When I drew a picture, I'm getting the lower limit for |z| to be $ 4 - \sqrt{13}$, what's going wrong here? I'm confused, why does triangle inequality give a different result?

@AkivaWeinberger $|z - 3 + 2i| \leq 4$, what's the range of |z|?

I have a small complex number question

@AkivaWeinberger hey

But when I drew a picture, I'm getting the lower limit for |z| to be $ 4 - \sqrt{13}$, what's going wrong here? I'm confused, why does triangle inequality give a different result?

or $-4 \leq |z| - \sqrt{13} \leq 4 $ which gives $\sqrt{13}-4 \leq |z| \leq \sqrt{13}+4$ but that lower bound is negative.. ? should I take the lower bound as 0 instead?

so $| |z| - \sqrt{13} | \leq 4 $

I'm getting stuck using triangle inequality I wrote$ | |z|−|3-2i| | \leq |z−(3-2i)|$ so $| |z| - \sqrt{13} | \leq |z−(3-2i)| \leq 4 $

If $|z - 3 + 2i| \leq 4$, what's the range of |z| ?

@Tanuj hi

Where am I going wrong here? - ~(p∨q)∨(~p∧q) == (~p∧~q)∨(~p∧q) == ~p ∧ ( ~q ∨ q) == ~p ∧ T == T

ok

no nvm

I mean 12 cm in front of the mirror..

not sure

Is the answer the same place as the object?

ok..

this question..i think abcd or someone asked him

I think its better you ask JR this..even I'm not too sure. I remember him solving this some time back

not sure how to answer that..by the way you've drawn it, it looks like the center of the small circle

ok

yeah..?

You too!

yup

the exact same :D

oh wow

not so good

I'm getting 128 according to Rao IIT's key..

hey

anyone else ?

@abcd what do you think? looks like a simple pinacol rearrangement question?

The answer given is B.. how? I'm getting D

anyhow the question should have asked what's the change in freezing point temp

yup

that's how depression in freezing point is defined?

1.8 x Kf x (moles of impurity)/(wt of HCl in kg)

yeah that's what I got too..

so you can ignore that middle branch when trying to find current

after a long time capacitor will be saturated with charge and no current can pass through it

you can write the equations for the two loops and solve the differential equation..but sid's method is easier

@Tanuj ok