Jun 22, 2017 00:46
thanks for your hekp
Jun 22, 2017 00:46
min = 3pi/2
Jun 22, 2017 00:46
Solved max = 7pi/2
 

 Mathematics

Associated with Math.SE; for both general discussion & math qu...
Jun 22, 2017 00:45
what is worthy of noting in this picture?
Jun 22, 2017 00:44
spring shape
Jun 22, 2017 00:44
nvm sounds like it has something to do with sine
Jun 22, 2017 00:44
I don't know what sinusoidal means
Jun 22, 2017 00:43
that was very helpful
Jun 22, 2017 00:43
thank you
Jun 22, 2017 00:43
hm
Jun 22, 2017 00:43
true value for the total area?
Jun 22, 2017 00:41
as minimum
Jun 22, 2017 00:41
and 3pi/2
Jun 22, 2017 00:41
as my maximum area
Jun 22, 2017 00:41
oh pi/2*7
Jun 22, 2017 00:40
or is it pi/2*f(7)?
Jun 22, 2017 00:40
so pi/2*f(pi/4)= max area?
Jun 22, 2017 00:39
Unless you're saying those are my maximum and minimum areas?
Jun 22, 2017 00:39
so those are my bounds, I still have the integrand of 3+4sin(2x) and the given bounds of 0 to pi/2 to evaluate maximum and minimum value.
Jun 22, 2017 00:38
whether it is f(0) or f(pi/2) its still 3
Jun 22, 2017 00:37
3,7?
Jun 22, 2017 00:37
on the lower bound f(0)= 3
Jun 22, 2017 00:37
on the upper bound
Jun 22, 2017 00:37
so f(pi/4) = 7
Jun 22, 2017 00:36
pi/4 is a value of f(x)? no?
Jun 22, 2017 00:35
0,pi/4?
Jun 22, 2017 00:33
?
Jun 22, 2017 00:33
pi/2 is my min bound
Jun 22, 2017 00:33
pi/4 is my max?
Jun 22, 2017 00:33
So you're saying what exactly?
Jun 22, 2017 00:32
-16
Jun 22, 2017 00:31
2*2^(1/2)+3
Jun 22, 2017 00:30
7
Jun 22, 2017 00:30
f(pi/2) = 3
Jun 22, 2017 00:29
f(0)= 3
Jun 22, 2017 00:29
so f(0) and f(pi/20
Jun 22, 2017 00:29
s0 f
Jun 22, 2017 00:28
i have some integrand 3+4sin(2x) on the bounds 0 to pi/2
Jun 22, 2017 00:28
but I have now a min at x=pi/4...
Jun 22, 2017 00:27
makes sense
Jun 22, 2017 00:27
yes
Jun 22, 2017 00:26
oh minimum
Jun 22, 2017 00:26
so we have a maximum
Jun 22, 2017 00:25
4 sqrt(2)
Jun 22, 2017 00:24
pi/4
Jun 22, 2017 00:23
yeah, cos(pi/2)?
Jun 22, 2017 00:22
oh 0
Jun 22, 2017 00:21
?
Jun 22, 2017 00:21
pi/2+pi*n for all n in integers
Jun 22, 2017 00:20
no