Mathematics

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Apr 19, 2013 01:11
in set theory is the only time where they really distinguish between them
Apr 19, 2013 01:11
so it is a set. outside of set theory most people say class just to mean collection without worrying about anything
Apr 19, 2013 01:10
its contained in some amount of power sets of D
Apr 19, 2013 01:10
just the word
Apr 19, 2013 01:09
but the "class of all ordinals" is a proper class so we can't do much with it
Apr 19, 2013 01:08
for instance the ordinals are extremely useful
Apr 19, 2013 01:08
the objects inside the class may still be useful
Apr 19, 2013 01:08
well we just cannot use them like they are sets
Apr 19, 2013 01:07
@PeterTamaroff yes
Apr 19, 2013 01:05
for instance the class of all sets is a proper class
Apr 19, 2013 01:05
a proper class just means that it is a class i.e. is defined by a formula but cannot be a set
Apr 19, 2013 00:39
I added it as an edit, because it shows why I'm asking the first question, but essentially asks a second question about a different integral
Apr 19, 2013 00:38
would it be acceptable to post my important edit on this post math.stackexchange.com/questions/365152/… as a second question? or is it better left in this one
Apr 19, 2013 00:38
quick meta- question
Apr 19, 2013 00:31
The elements of the power set are by definition subsets of the original set
Apr 19, 2013 00:30
for the second part (a,b) = {{a}, {a,b}} and both a and b are in {a,b} so they are in the union set
Apr 19, 2013 00:28
(a,b) = {{a}, {a,b}} both {a}, {a,b} are in P({a,b}) and so {{a}, {a,b}} is in PP({a,b})
Feb 8, 2012 07:00
carried an extra one there somehow
Feb 8, 2012 07:00
woops sorry I meant 3/8
Feb 8, 2012 06:11
I'm unsure if I erred somewhere along the way though seems like an odd number
Feb 8, 2012 06:11
I ended up doing out the whole thing and getting \int^1_0 x^2 dF(x) = 7/16
Feb 8, 2012 06:10
is there a program which will calculate this numerically if i enter in "cantor function * x) integral
Feb 8, 2012 05:52
that seems like it should work, thanks for the help I'll do it out now and see
Feb 8, 2012 05:52
yeah I see
Feb 8, 2012 05:49
riemann-stieltjes integral
Feb 8, 2012 05:49
calculate \int^1_0 xF(x) dx where F(x) is the cantor function (devil's staircase)
Feb 8, 2012 05:49
it is essentially this
Feb 8, 2012 05:46
correct
Feb 8, 2012 05:46
this is 1/2
Feb 8, 2012 05:41
I don't see how tht would help me integrate
Feb 8, 2012 05:41
You see, even if I had that though
Feb 8, 2012 05:31
tbh I've never heard that term before, but I assume it means something like it's essentially the same in both intervals?
Feb 8, 2012 05:31
prove that it is "self-similar"?
Feb 8, 2012 05:28
(he wrote a where I write F)
Feb 8, 2012 05:28
he seem's to think (at least from his hint) that it can be done using properties of F ... rather than some sequence
Feb 8, 2012 05:27
yeah that's another of my concerns
Feb 8, 2012 05:24
I suppose not, however at the point of going down and figuring that out the solution seems to be getting a bit more convoluted than I would expect it to be
Feb 8, 2012 05:20
however thats likely unhelpful since we have u+2
Feb 8, 2012 05:20
I'm unsure you can get something like 1/18 \int^1_0 (u+2)f_n(u) du
Feb 8, 2012 05:01
but the ones on the edges seem to go to 0 unless I'm seeing it wrong, but that seems wrong to me, e.g it seems wrong that in 0,1/3 and 2/3,1 the integral would be 0
Feb 8, 2012 05:00
just take the limit as n\rightarrow \infty of the sum of these three values?
Feb 8, 2012 05:00
Okay Dylan sorry I'm quite slow at integration and concepts like this just getting to understand it, so we've got $\frac{1}{18}\int_0^1 uF_n(u) du for \int^{1/3}_0 F_{n+1} and we can do \int^{1}_{2/3} similarly, and $\int^{2/3}_{1/3} is always the 1/12 correct? but then I still can't see how to conclude
Feb 8, 2012 04:22
oh gotcha
Feb 8, 2012 04:21
@Dylan Sorry I think maybe i'm missing something silly how did you get to $F_n$ instead of $F_{n+1}$? "Write $u = 3x$ and work out the details; you get $\frac{1}{18}\int_0^1 uF_n(u) du$."
Feb 8, 2012 04:13
ok, I'm back sorry my friend needed something
 

 Wolfram Mathematica

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Apr 17, 2012 19:00
See I knew it wouldn't be substantive enough for a question on the site ;)
Apr 17, 2012 18:47
should solve it, but then when I just define a function to be the solution to this and evaluate its derivative at 0 it doesn't give me 0, which was my initial condition
Apr 17, 2012 18:46
It seemed to me, like "sol1 = DSolve[{x1''[t] + 2 b x1'[t] + w0^2 x1[t] == a Sin[w t],
x1[0] == 0, x1'[0] == 0}, x1[t], t];"
Apr 17, 2012 18:46
Essentially I'm just trying to get mathematica to solve the differential equation for a forced harmonic oscillator,
Apr 17, 2012 18:44
Hey guys I have a quick question about a differential equation in mathematica that I was hoping someone could help me with here, as its not really substantive enough to pose as a question on the main site