shai horowitz

 Mathematics

Associated with Math.SE; for both general discussion & math qu...
Mar 29, 2023 01:31
That is a fair point
Mar 29, 2023 01:30
Of course not all you ideas/questions are gonna be good ideas/questions, but it is how you learn
Mar 29, 2023 01:29
@user4539917 Thats the fun part
Mar 28, 2023 23:19
Linearity and Stability are the standard terms
Mar 28, 2023 22:59
I accept 3 as the correct answer
Mar 28, 2023 22:57
id say 2, inside outside
Mar 28, 2023 22:56
@A016090 you are very welcome
Mar 28, 2023 22:55
@shintuku oh you liked my answer?
Mar 28, 2023 18:30
i appreciate your earlier example
Mar 28, 2023 18:30
i dont think we have any actual disagreements though
Mar 28, 2023 18:29
it is frustrating
Mar 28, 2023 18:29
at every step you told me i was wrong without reading my post
Mar 28, 2023 18:28
and now were here
Mar 28, 2023 18:28
then you lost the train of the convo
Mar 28, 2023 18:28
then i posted a link to an argument
Mar 28, 2023 18:28
we were talking about the second thing. then you brought back in the first with "Your fourth line seems to follow from $1-4+9-16+\dots$ is equal to $1+2+3+4+\dots$
I don't see that"
Mar 28, 2023 18:27
i agree 1 does not equal 0
Mar 28, 2023 18:26
RobJohn my man. why are you doing this to me

The first thing i asked about what the zeta(-2) heuristic. to which you replied that my wrong formula was wrong

then someone else asked me a question and i answered them that these sums are never linear and stable and i proved it with a proof by contridiction. namely i assumed stability and linearity and ended with 1=0. you replied to this by saying that i was wrong
Mar 28, 2023 18:24
this is the heuristical argument that makes that tempting
Mar 28, 2023 18:23
16
Q: Combinatorial proof that binomial coefficients are given by alternating sums of squares?

J..A student recently asked whether there was a combinatorial proof of the following identity: $\begin{equation*} \sum^n_{k=1}(-1)^{n-k}k^2 = {n+1 \choose 2}. \end{equation*}$ I was in a rush and couldn't come up with anything nice off the top of my head. Any ideas or pictures to make this clear...

Mar 28, 2023 18:22
i understand that the reason is your not actually allowed to deal with infinite sums this loosely but I just want to know do any similar huerstic arguments actually work out
Mar 28, 2023 18:22
i stated
Mar 28, 2023 18:22
i shouldnt say proof for the thing earlier its not proving something
Mar 28, 2023 18:22
ok so now we are the eariler proof. not the one where i just showed a proof by contridition
Mar 28, 2023 18:20
what bad step? what single thing did i assume besides stability and linearity
Mar 28, 2023 18:18
what is incorrect in my proof by contradiction?
Mar 28, 2023 18:18
this one started with the assumption that these sums were linear and stable and ended at 1=0
Mar 28, 2023 18:16
earlier i said here is an incorrect proof and you told me my proof had an error
Mar 28, 2023 18:14
followed by a proof by contradiction
Mar 28, 2023 18:14
i'm arguing
"In general once we start talking about a series like 1+2+3...=c we already leave the combo of linearity and stability behind
because if not... "
Mar 28, 2023 18:14
i'm not arguing thats not true
Mar 28, 2023 18:12
i did aproof by contridicition and people are saying i derived contradiciton
Mar 28, 2023 18:12
sigh...
Mar 28, 2023 18:11
@robjohn Thanks this is a great example of what I was looking for
Mar 28, 2023 18:11
and if $1+1+1...=0$
$0+1+1+!...=0$
and
$(1-0)+(1-1)+0+0...=0$
Mar 28, 2023 18:09
Nope, i'm not that good. I only know when i'm doing it incorrectly...

In general we want our summation technique to be regular, linear, and stable.
regular here loosely means that it sums convergent series correctly to the correct convergent value

linear means comes means you can add or subtract series from each other and the sums also add an subtract.

stable means adding a term at the beginnig of the series has the result of adding that value to the sum of the series.


In general once we start talking about a series like $1+2+3...=c$ we already leave the combo of linearity and stabilit
Mar 28, 2023 17:44
@robjohn which it seems like you do
Mar 28, 2023 17:38
I asked if you knew of any similar heuristic arguments
Mar 28, 2023 17:38
Also i never said these manipulations were sound. I said specifically that they are not sound
Mar 28, 2023 17:37
I suppose you missed the beginning of my post.
Mar 28, 2023 17:37
its tempting to say $...5^2-4^2+3^2-2^2 +1^1= 1+2+3+4+5$
Mar 28, 2023 17:36
i.e. $c=1+2+3+4...$
$4c = 4+8+12...$
$c-4c= 1+2-4+3+4-8..=1-2+3-4...=1/4$
$c=-1/12$
Mar 28, 2023 13:35
I gave you an example of where Ramanujan did what I was asking for on a similar series. Simply asking if there existed any similar arguments
Mar 28, 2023 13:31
"which is obviously wrong
i understand that the reason is your not actually allowed to deal with infinite sums this loosely but I just want to know do any similar huerstic arguments actually work out"
Mar 28, 2023 13:29
How can I be more clear in what I am asking? He just replied to my question by restating my last sentence
Mar 28, 2023 13:26
Good job
Mar 28, 2023 13:26
Wow you really read my question
Mar 28, 2023 13:24
i understand that the reason is your not actually allowed to deal with infinite sums this loosely but I just want to know do any similar huerstic arguments actually work out
Mar 28, 2023 13:23
$d=1+4+9+16...$
$8d = 8+32+72+128$
$d-8d=1-4+9-16$
$-7d=1+2+3+4..$
$d = 1/84$
which is obviously wrong
Mar 28, 2023 13:21
its tempting to say $...5^2-4^2+3^2-2^2 +1^1= 1+2+3+4+5$