Adeek

Hi @AkivaWeinberger

Hey @TedShifrin

you 2 nights :)

I am off to sleep I will check it tomorrow

If we think about it as $R = R[y]$ then $R[x]$ the polynomial $xy + x + y + 1 = (y + 1)x + y + 1$ which isn't monic

so it is not monic

I guess $R = R[x]$ so the polynomial is in $R[y]$ this example $xy + x + y + 1 = (x + 1)y + x + 1$

ohhh the theorem applies in R[x]?

i.e. the term $xy$ has coefficient 1

wait isn't monic is the coefficient for the higher degree coefficient ?

@leslietownes yes I read the theorem incorrectly

@Koro can you give screen shot of the theorem?

let me download Dummit

why isn't it monic

wait the polynomial is monic

x + 1 can't be factored in (R/I)[x]

not in the way he wrote

p(x,y)=xy+x+y+1 in the quotient that becomes x + 1

No it is because he isn't applying theorem correct. He wishes to check if that polynomial is x + 1 in Z[x,y]/(y)

yes

?

how can you factor (x + 1) in Z[x,y]/(y)?

why?

$(x + 1) * (y + 1) = (x + 1) * 1$ in the quotient

@Koro non-zero

cool

$\mathbb{Z}[x,y]/(y) \cong \mathbb{Z}[x]$

$5y$ is zero in $\mathbb{Z}[x,y]/(y)$

@Koro what are you working on?

what are you trying to do ?

@CroCo what is V here?

this is because of the common components in the $(2,3)$ we keep intersecting different things in those components

I wanted to ask you. If we have a curve $C$ in $C_1 \times C_2 \times C_3 \times C_4$ product of smooth projective curves. If we take $K_1 = Pr_{1,2,3}(C) \times C_4$. Pick a curve $C_1$ different than $C$ in $K_1$. Now consider $Z_2 = C_1 \times Pr_{2,3,4}(C_1)$. Continue this process alternating between (1,2,3) and (2,3,4). At some point we get K_n that is of the form Curve x Curve x {points} right?

@TedShifrin hi

Hi @copper.hat

Hey @leslietownes

how is life?

how are you doing?

@TedShifrin pretty good.

@TedShifrin hi

Hi @TedShifrin

yeah @love_sodam

@love_sodam expand sin(sqrt(z))

to make sure I don't catch any errors

I think I need to rewrite things multiple times

I did a a lot of computations though

@TedShifrin I have figured out a nice problem

that sucks

but she is ok now

not with chemo though