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 The Nineteenth Byte

The Nineteenth Byte: General discussion for codegolf.stackexc...
15
Mutador
Dec 22, 2015 01:43
spacex.com/webcast
Mutador
Dec 22, 2015 01:40
IT LANDED
Mutador
Dec 22, 2015 01:39
OMG
André Muta
Dec 22, 2015 01:27
@gnibbler thank you man, I knew it must have a name.
André Muta
Dec 22, 2015 00:44
I am going it in R and didn't wanna use a for loop.
André Muta
Dec 22, 2015 00:43
yeah
André Muta
Dec 22, 2015 00:43
Does this have a particular name?
André Muta
Dec 22, 2015 00:43
[1,2,3],[2,3,4],...,[98,99,100]
André Muta
Dec 22, 2015 00:42
e.g. n=3
André Muta
Dec 22, 2015 00:42
for n numbers
André Muta
Dec 22, 2015 00:42
how can I calculate all the possible consecutive combinations
André Muta
Dec 22, 2015 00:42
lets say I have a sequence [1,2,3,..,100]
André Muta
Dec 22, 2015 00:41
Anyone know how could I do this:
André Muta
Dec 22, 2015 00:38
Hello
André Muta
Dec 21, 2015 20:13
@CᴏɴᴏʀO'Bʀɪᴇɴ I just had 666, there should be a hat for that.
André Muta
Dec 21, 2015 20:12
@Dennis really
André Muta
Dec 21, 2015 20:11
@CᴏɴᴏʀO'Bʀɪᴇɴ so I have to write a program that doesn't have any of the characters that your output had? Is my output allowed to have them?
André Muta
Dec 21, 2015 20:08
Well, to be fair weather can affect suicide rates
André Muta
Dec 21, 2015 20:00
Why that?
André Muta
Dec 21, 2015 19:57
Oh, I didn't know that.
André Muta
Dec 21, 2015 19:56
@CᴏɴᴏʀO'Bʀɪᴇɴ wat?
André Muta
Dec 21, 2015 19:54
~27% by NBZ
André Muta
Dec 21, 2015 19:53
15
André Muta
Dec 21, 2015 19:50
How can I see if someting is going to stdout in R?
André Muta
Dec 21, 2015 19:49
here
André Muta
Dec 21, 2015 19:39
hello
André Muta
Dec 18, 2015 18:37
For what type of applications is Perl usualy used?
André Muta
Dec 18, 2015 18:30
matlab
André Muta
Dec 18, 2015 18:21
user image
André Muta
Dec 18, 2015 18:20
z <- sample(100000)
for(i in 1:1000){
k[i]=mean(sample(z,15))
}
hist(k, breaks=20)
André Muta
Dec 18, 2015 18:20
The mean of the samples of a uniformely distributed variable goes to normal
André Muta
Dec 18, 2015 18:19
Yeah, that was what I was thinking about
André Muta
Dec 18, 2015 18:19
Yay
André Muta
Dec 18, 2015 18:13
I quit, hahaha
André Muta
Dec 18, 2015 18:12
The mean of the samples will be normaly distributed?
André Muta
Dec 18, 2015 18:09
Just tested it, shame on me
André Muta
Dec 18, 2015 18:09
That is true, sorry
André Muta
Dec 18, 2015 18:09
Well
André Muta
Dec 18, 2015 18:08
What is a infinite support?
André Muta
Dec 18, 2015 18:07
No? :(
André Muta
Dec 18, 2015 18:06
Let A be 1000 random (uniform) picks from 1:1000 and B be 1000 random (uniform) picks from 1001:2000 then A+B is Normal
André Muta
Dec 18, 2015 18:04
The sum is normaly distributed
André Muta
Dec 18, 2015 18:04
That is what I meant
André Muta
Dec 18, 2015 18:02
their sum will be normaly distributed
André Muta
Dec 18, 2015 18:02
The best I can come up with is that is they are uniformely distributed
André Muta
Dec 18, 2015 18:02
well
André Muta
Dec 18, 2015 18:01
Are they randomly chosen?
André Muta
Dec 18, 2015 17:53
Hello
André Muta
Dec 18, 2015 17:26
@yeti fixed
André Muta
Dec 18, 2015 17:24
Just sent it to main