user100000000000000

the function is continuous on the set E*

is "f restricted to the set E is continuous" the same thing as saying that $the function if continuous on the set E"

In the last displayed equation, how do they get \mu^*(E)+\epsilon\ge \mu(B\cap A)+\mu(B\cap A^c)\ge \mu^*(E\cap A)+\mu^*(E\cap A^c)? math.stackexchange.com/questions/2443845/…

@LeakyNun for all b when b is m^ast(E+a). I thought that quantity was fixed here

@LeakyNun Why does it make sense to talk about

@LeakyNun I understand the logic in what you wrote, but what plays the role of b in my question?

I agree with equation 1, and I also think that m*(E) \leq \sum(l(I_n)).

mathonline.wikidot.com/… on this proof how does equation * follow?

Why did Springer pull the free book thing? (gist.github.com/bishboria/8326b17bbd652f34566a)