But it sounds like rotation is defined in terms of Euler's notation theorem: "When a sphere is moved around its centre it is always possible to find a diameter whose direction in the displaced position is the same as in the initial position."
@keshav, this is a totally intuitionist answer, but my gut feel is that the reason a fixed point implies well-defined-ness of an axis of rotation is tautological
I am asked to solve the following ODE involving constants $\alpha, L, V_0 > 0$ and $E < 0$:
$$-\psi'' - \alpha V_0\psi\cdot [\delta(x)+\delta(x-L)] = \alpha E\psi.$$
In particular, we want solutions $\psi:\mathbb{R}\to \mathbb{C}$ that are:
Continuous
$L^2$
We are given that the solutions l...
I have a normed vector space X and its dual X*, and X* induces a 'weak topology' on X (the weakest topology where all the functionals in the dual are continuous, i.e. a sequence (xn) --> x weakly in X iff (psi(xn))--> psi(x) for any psi in X*)
Hello I have a small question, the weak open unit ball in a hilbert space $\mathfrak{H}$ looks like: $B_\varepsilon(0) = \{x\in\mathfrak{H}|\,|(x|y)|<\varepsilon \forall y \in \mathfrak{H}\},$ right?
it would be nice if, given a stopping time you were interested in, there were some general way to identify a martingale in terms of how that stopping time was defined
Look, the guy even knew the answer before it was posted. He comments to one of the answerers: "Your answer is not useful. I think checking the eigenvalue of the Hessian matrix maybe a good approach"
It is clear what orderings some cones induce, e.g. the positive orthant of Rn creates an ordering where x<y if each component of x is less than its corresponding y component.
Everyone knows every proper cone in Rn defines a partial order on the space... but how are we to understand the partial ordering of an arbitrary proper cone K???
Hi everyone, I'm a gambler and I start with $x$ money, i put down a dollar and get 2 dolalrs back with p=0.5, and lose my dollar with p=0.5. I am interested in how long it will take me to either A) go broke or B) reach N dollars. Take T to be this stopping time.
I showed $(X_n^2-n)$ is a martingale and that I reach N dollars with probability $x/(N+x)$, but now how do I get the EV of how long it takes to finish the game?
skimming the wikipedia article it looks like its an open question that so far is partially resolved by just pulling it from the second law of thermodynamics
This article is an overview of the subject. For a more technical discussion and for information related to current research, see Entropy (arrow of time).
The Arrow of Time, or Time's Arrow, is a concept developed in 1927 by the British astronomer Arthur Eddington involving the "one-way direction" or "asymmetry" of time. This direction, according to Eddington, can be determined by studying the organization of atoms, molecules, and bodies, might be drawn upon a four-dimensional relativistic map of the world ("a solid block of paper").
Physical processes at the microscopic level are believed to be...