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Mann
Jul 15, 2020 11:48
@AdvilSell Yes. issues are going on right now. :/
Mann
Jul 2, 2020 09:19
Thanks dudee
Mann
Jul 1, 2020 10:09
If things goes well with visa then cornell
Mann
Jul 1, 2020 05:03
I would prefer higher studies gotta wait for complete covid update atm
Mann
Jun 30, 2020 14:36
😂
Mann
Jun 30, 2020 14:36
Graduated and ghar ka kaam
Mann
Jun 29, 2020 11:44
Hi
Mann
Jun 13, 2020 19:20
@Yuvraj hi
Mann
May 25, 2020 19:41
Yes
Mann
Apr 8, 2020 15:15
@HrishabhNayal no issues
Mann
Apr 8, 2020 14:17
@HrishabhNayal?
Mann
Apr 8, 2020 13:25
In that case, the result become obvious.
Mann
Apr 8, 2020 13:24
I think $a=0^{+}$ and $b=\infty$
Mann
Apr 8, 2020 13:22
@HrishabhNayal
Mann
Apr 8, 2020 13:22
And in the second integral put $t=-\frac{1}{X}$
Mann
Apr 8, 2020 13:21
$$\int_{a}^{b}f(t-\frac1t)\textrm{d}t + \int_{a}^{b}\frac{1}{t^2}f(t-\frac1t) \textrm{d}t =1$$
Mann
Apr 8, 2020 13:20
$\int_{a}^{b}f(t-\frac1t)\times \left(1+\frac{1}{t^2}\right)\textrm{d}t=1$
Mann
Apr 8, 2020 13:19
But anyway, the general scheme I used; is this.
Mann
Apr 8, 2020 13:19
Ahh I see, I had forgotten to change the limits here, yes yes my mistake.
Mann
Apr 8, 2020 13:17
Substitute $x=t-\frac1t$
Mann
Apr 8, 2020 13:17
$$\int_{-\infty}^{\infty}f(x)\textrm{d}x=1$$
Mann
Apr 8, 2020 13:17
Okay lemme write down
Mann
Apr 8, 2020 10:25
Put x = t - 1/t
Mann
Apr 8, 2020 10:25
It's simple just in the first integral f(x) dx
Mann
Apr 8, 2020 10:25
@HrishabhNayal are you sure about this. I think it's 1/2. Barring any calculation mistake.
Mann
Apr 8, 2020 07:54
@AjayMishra going to be graduated. Here xD
Mann
Jan 16, 2020 17:43
Need to finish things up
Mann
Jan 16, 2020 17:43
anyway, I will go now
Mann
Jan 16, 2020 17:43
It has happened many times
Mann
Jan 16, 2020 17:43
Yeaaa, that is actually very physical xD
Mann
Jan 16, 2020 17:42
As natural solution died
Mann
Jan 16, 2020 17:42
And resulted in a final 180 phase out
Mann
Jan 16, 2020 17:42
But in the other case, slow phasing out started to accumulate
Mann
Jan 16, 2020 17:42
In the one case Natural frequency always dominated and they kind of remained in sync
Mann
Jan 16, 2020 17:41
Yea, this seems a reasonable enough explanation. Maybe the point here was to actually considered what happened during the time of natural oscillations
Mann
Jan 16, 2020 17:40
Ahh okayyy
Mann
Jan 16, 2020 17:38
Okayy thats a constant Stretch
Mann
Jan 16, 2020 17:37
I am seriously wondering about the situation $w=0$ right now
Mann
Jan 16, 2020 17:34
Right?
Mann
Jan 16, 2020 17:34
So you said the speed has to be such that you can see at least one time period of motion
Mann
Jan 16, 2020 17:34
Okayyy This is definitely a very weird thing to think but I got your problem. But first I need to define a speed that is good enough here.
Mann
Jan 16, 2020 17:32
The train scenario will compare are systems at different instants
Mann
Jan 16, 2020 17:31
Do you want to view all of the systems at once or each system at some different instants?
Mann
Jan 16, 2020 17:31
Or wait no, not exactly the same
Mann
Jan 16, 2020 17:30
But you need the answer physically
Mann
Jan 16, 2020 17:30
?
Mann
Jan 16, 2020 17:30
You are essentially asking why the behavior of $x(w)$ as a function of $w$ for a fixed instant $t$ is so. Where the range of $w$ contains $w_0$
Mann
Jan 16, 2020 17:29
Okayyy I got the kind of problem you are asking for
Mann
Jan 16, 2020 17:27
Yeaa
Mann
Jan 16, 2020 17:27
Okayy