Mathematics

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Jun 6 17:07
So perhaps orientable 3-manifolds.
Jun 6 17:07
But seems useful to have a volume form on the 3-manifold.
Jun 6 17:07
As of right now, I was just thinking surfaces in arbitrary 3-manifolds.
Jun 6 16:59
Another candidate might be $\int_\Sigma\iota_X\mu$ if we instead have $\mu$ as a volume form on the ambient manifold (instead of just the surface).
Jun 6 16:25
Does defining flux on a general manifold need a Riemannian metric? Strangely can't find much about it, but I was thinking the flux of a vector field $X$ would be defined as $\int_\Sigma g(X,n)\,\mu$ where $\mu$ is a volume form on $\Sigma$, $n$ a unit normal vector field to $\Sigma$, and $g$ a Riemannian metric.
Jun 6 16:17
Oh how I love drawing Seifert surfaces.
Jun 6 15:51
The ducks still frequent it, I hope?
Jun 6 15:47
Any more adventures at the fowl bowl (duck pond)
Jun 6 15:34
LESLIE
May 23 17:00
It's okay, apparently dumb question. :D
May 23 16:36
@Thorgott well the "dual" depends on what type of dual. For example, that's the dual as C^\infty(M)-modules, but the continuous dual (of either 1-forms or vector fields!) is the space of 1-currents. They aren't the same thing.
May 23 14:18
My experience is mostly limited to topological and module duals which I considered in this case but did not work for my purpose.
May 23 14:16
The point is indeed not present, it's rather complicated. I am just mining for any notion of dual that is natural in this case.
May 23 14:07
(in particular, the $C^\infty(M)$-dual of $\mathfrak X(M)$ is $\Omega^1(M)$)
May 23 14:06
Soft question for more algebra-oriented fellows: given a smooth manifold $M$, you get the $C^\infty(M)$-modules $\mathfrak X(M)$ and $\Omega^k(M)$ of vector fields and $k$-forms. You can find the $C^\infty(M)$-dual to these, but I was wondering if there is a more descriptive notion of "dual" that can be ascribed to this special case. Like they are both sheaves, for example, but I don't think this corresponds to a dual notion for sheaf since it heavily relies on the $C^\infty(M)$ part.
Apr 8 12:43
If it's one thing I've learned while doing math, it's not to trust grown-ups.
Apr 2 21:58
@XanderHenderson I can't imagine how there would be that much overhead. It's mathjax (or katex, if you want something faster), which I'd imagine is more efficient than even link previews.
Apr 2 20:48
Though they do have an unrelated page on elliptic chain complexes, also interesting.
Apr 2 20:46
"Remark Notice that there is no notion of cochain in this general setup. What are called cochains are specifically components of certain specific models for H(X,A) . More on this in the section on abelian cohomology below."
Apr 2 20:45
Very intriguing.
Apr 2 20:45
Yeah, the nlab page led me eventually back to the cohomology page where they define a very very general type of cohomology on (\infty,1) categories.
Apr 2 20:41
@BenSteffan Interesting, I didn't know that there were things called a cohomology theory that couldn't be phrased (in some manner) as arising from a cochain complex!
Apr 2 20:37
@BenSteffan Okay, so the "elliptic" part comes up only in the construction of the associated cochain complex?
Apr 2 20:27
@BenSteffan Like just a topological space?
Apr 2 20:06
Elliptic cohomology, huh. What's the object being assigned the cohomology groups in this case?
Apr 2 20:03
same
Apr 2 20:02
How have you been, @BenSteffan? What have you been working on?
Apr 2 20:00
lol stackexchange notifies me of them making improvements to the chat yet we still have yet to get native mathjax and have to run it manually ourselves
Apr 2 19:53
Hello world.
Nov 15, 2024 20:06
I am having troubles with how to make sense of the relative de rham cochain $\Omega^k(i)$ for $i\colon S\to M$. Bott & Tu allow $k=0$ and define $\Omega^k(i) = \Omega^k(M)\oplus\Omega^{k-1}(S)$. But the $\Omega^{-1}(S)$ would be just zero, right?

As a toy example, I was taking $M = S^1$ and $S = \{0\}$. So the chain would be like $\Omega^0(S^1) \to \Omega^1(S^1)\oplus\Omega^0(\{p\}) \to 0$, right?
Nov 15, 2024 19:53
Anyone handy with relative de Rham cohomology?
Oct 27, 2024 20:20
For some reason I was taking it for granted that $N\cong (-\epsilon,\epsilon)\times H$
Oct 27, 2024 20:17
Thanks!
Oct 27, 2024 20:17
Oh it's implicitly through taking the neighbourhood as trivialized!
Oct 27, 2024 20:11
But now I wonder what's wrong/missing with my previous suggestion via tubular neighbourhoods? Am I implicitly appealing to this normal vector field?
Oct 27, 2024 20:08
Seems doable.
Oct 27, 2024 20:08
I guess you can do that by making sure that I guess the normal vector field defines an "in" and "out direction, and so as long as you pick $\rho_\alpha$ so that they agree on sign on the in an out sides, then you get that?
Oct 27, 2024 20:05
It would have to guarantee that all my local defining functions $\rho_\alpha$ have the same sign at $d\rho_\alpha|_p$ for $p\in H$, I guess?
Oct 27, 2024 20:02
@Thorgott I have trouble showing that 0 is a regular value in this case. Maybe tthe normal vector field can be used for this, but I guess I will have to think about it longer.
Oct 27, 2024 19:47
With the tubular neighbourhood idea, I would want to say that since regular points are generic, we can perturb our function $C^\infty$-small (?) to get a function, but this isn't to clean. I am also wondering if the normal vector field condition is even necessary?
Oct 27, 2024 19:43
Feels kind of stupid, but suppose I have a non-vanishing normal vector field to a hypersurface $H\subset M$. I want to define a function $\rho\colon N\to\mathbb R$ for a neighbourhood $N\supset H$ such that $\rho^{-1}(0) = H$ and $d\rho_p\neq 0$ for each $p\in H$. This is easy with the implicit function theorem around some point in $H$, and it's easy to come up with functions without the $d\rho$ constraint using tubular neighbourhoods, but I can't get anything satisfying everything.
Sep 26, 2024 18:53
Chat him up if he ever pops in. Anyway, I gotta go. Nice chatting. :D
Sep 26, 2024 18:50
A guy who used to (?) frequent here. Prodigious in all things topological and geometric.
Sep 26, 2024 18:49
You sound like you'd be a pal to Balarka.
Sep 26, 2024 18:46
Stolz's paper is a great geometric read though, maybe you can read it at some point and identify the more general theory being used.
Sep 26, 2024 18:45
I will have to check that out. Sounds more explicitly homotopy theory than Stolz's paper.
Sep 26, 2024 18:41
Interesting... do we have any good examples of people who purposefully used the language of stable homotopy theory to solve a geometric problem like Stolz?
Sep 26, 2024 18:40
Okay, so here they are just saying because it was with the spin cobordism, it's stable homotopy theory.
Sep 26, 2024 18:34
I am familiar with Stolz's paper, but I don't remember it being relevant to stable homotopy theory...
Sep 26, 2024 18:34
Out of curiosity I was just browsing the nlab page on stable homotopy theory and they have a note "The reduction of geometric phenomena to solvable problems in stable homotopy theory has remained an important mathematical theme, the most recent major success being Stolz’s use of Spin cobordism to study the classication of manifolds with positive scalar curvature."