Sep 14, 2022 14:02
@Luthier415Hz True, but typically you specify IC because of the model (could be a Physical model). IC fixes the model, but the IC themselves have to mean something - an example, if we are are integrating a function with singularities then having a definite integral with that singularity between the bounds of integration is unlikely to be informative.
Sep 14, 2022 14:02
@Luthier415Hz in short yes - you only want the same number of ICs as free coefficients - if you have Second Order and only one IC then you would only get to $c_1 = -c_2$ and not define what value either one would be exactly. This may be ok for some work. (look at en.wikipedia.org/wiki/Overdetermined_system)
Sep 14, 2022 14:02
I think you are confusing a few things - but the solution until you specify the IC can only be written in terms of coefficients. Once you pick ICs you then fix what the coefficients are. If you have too many ICs e.g. y'' = k then you may run into a problem as you have too many constraints for too few coefficients so you may not satisfy all the ICs.
Sep 14, 2022 14:02
@student91 it is a different ODE solution he is using as an example.
Sep 14, 2022 14:02
yes fix parameters/coefficients based on the IC values - as the function can take any form. It is only once you fix the integration constant do you satisfy your IC (now not all IC can be satisfied by your function) but then you go back the drawing board then :)
Sep 14, 2022 14:02
the question of different coefficient values given the same IC comes down to uniqueness of your solution. Depends on what you mean, a limit cycle can have the same final form (shape of solution after some time period) regardless of initial conditions (subject to criterion for limit cycle behaviour)
Sep 14, 2022 14:02
You solve an ODE to give you a function of the form you see with $C1, C2$ these are integration constants - you will then need the initial conditions and or boundary conditions to specify the constants that yield the specified IC. So ODE => Solve ODE => Fix parameters
 
Nov 6, 2015 17:59
When solving integrals you have definite and indefinite? Basically with limits and without. Since I did an integration without limits I needed a constant (which you find by inserting in the starting information)
Nov 6, 2015 17:58
The C is an integration constant
Nov 6, 2015 17:58
It came from when I moved the half from the one side to the right.
Nov 6, 2015 17:15
You can relabel terms to make it clearer .. So substitute $y = v^2$ and see what you get
Nov 6, 2015 17:09
A real mathematician (which I am not) would disagree with my terminology - but you divide both sides by the right hand side leaving unity on the rhs
Nov 6, 2015 17:09
You are correct in terms of the last equation
Nov 6, 2015 17:04
A real mathematician (which I am not) would disagree with my terminology - but you divide both sides by the right hand side leaving unity on the rhs
Nov 6, 2015 17:03
Let's not worry about numerical values at the moment.
Nov 6, 2015 16:54
but essentially you are correct. Then you move the $dx$ over to the rhs
Nov 6, 2015 16:54
almost remember that you have $\frac{1}{2}\dfrac{d}{dx}v^2$
Nov 6, 2015 16:51
This leads to $v\frac{dv}{dx} = \frac{1}{2}\dfrac{d}{dx}v^2$
Nov 6, 2015 16:51
$\frac{d}{dx}v^2 = 2v\frac{dv}{dx}$ this is implicit differentiation. But we require only $v\frac{dv}{dx}$ so to achieve this we divide both sides by 2.
Nov 6, 2015 16:48
then you can define $y = v^2$ then you have a linear ode $\frac{1}{2}\frac{dy}{dx} = g - ky$ which you may be able to solve?
Nov 6, 2015 16:46
I am running out of ideas how to prove the solution. So essentially what I do is state $$\dfrac{d^2 x}{dt^2} = \frac{dv}{dt} = \frac{dx}{dt}\frac{dv}{dx} = v\frac{dv}{dx} = \frac{1}{2}\dfrac{d}{dx}v^2$$
Nov 6, 2015 16:45
Ok, so you understand the chain rule so from that you can integrate the ode.
Nov 6, 2015 16:44
NP. Are you happy with the chain rule $\dfrac{dv}{dt} = \dfrac{dx}{dt}\times \dfrac{dv}{dx}$
Nov 6, 2015 16:44
I am not sure how just knowledge of integration by parts will help you here. I will keep thinking. Do you have any idea how the problem should be solved? initial equations? - failing that I will give a short edit on solving the equation you start in the comment above.
Nov 6, 2015 16:44
This is why I think my solution does not satisfy your requirements. Have you worked with differential equations?
 
Dec 22, 2014 20:34
Ah ok. So I only dealt with equilbria for rotating plasmas in the two fluid limit. So which Department are you atracked to? I only know two personally warwick (place of study) and leuven (having given a talk and had my an examiner for my viva from there goosens)
Dec 22, 2014 20:24
One more question whilst working thought model I am assuming you only have variation in the z axis? For all variables? I.e $B_x(z,t)$ and similarly for pressure?
Dec 22, 2014 19:39
You should check a paper by Ken mcclements and chippy dealing with the this very problem where the toroidal rotation is much. Larger than and poloidal so can be neglected in expansion. So are you working on tokamak dynamics? As I was looking at rotational plasma with the grad shafranov equation?
Dec 22, 2014 19:25
Hi there. It actual fact I was working on nonlinear axis metric solutions for rotating plasmas. So what area of MHD you looking at?
Dec 22, 2014 19:24
I meant uniqueness instead of existence.
Dec 22, 2014 19:24
I would modify the question with the full model as outlined in your comment..this will get my brain churning (thumbing over my thesis ;) )
Dec 22, 2014 19:24
I assume you are trying to prove existence? Or the work done by the wave is constant? I have a background in nonlinear MHD and I haven't come across this formulation of conservation? Also do you have other initial conditions ?
Dec 22, 2014 19:24
@gage if you check his profile he has a non trivial account on MO so I assume he understands the rules? No?
Dec 22, 2014 19:24
Ah my beloved MHD waves. :).
 
Dec 8, 2014 20:45
@ArthurFischer I second the opinion of alex. The moderators here seem to take pride in what they do and do it well..I guess I am bias since I haven't been on the wrong end of the "law" ;)
 

 Mathematics

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Oct 15, 2014 20:32
@JasperLoy basically I only thought the rep score for answers were +10 or -2 but I had a score of +1? But not to worry I was looking for a quick answer :).
Oct 15, 2014 20:25
Good evening (London) everyone, Random question which I felt shy to ask on meta..but what does a +1 and a "removed" message on an answer I posted a while back mean?
Oct 9, 2014 22:33
@jasperloy I don't know why? I think I know why.
Oct 9, 2014 22:24
I get you on that point. I am a data scientist /risk developer now (so maybe not the best person in terms of advice for academia ;) ) . See ya.
Oct 9, 2014 22:20
That last msg was rather convoluted for me. But I feel the best way to resolve the issue you have is to focus on the mathematics and use the physics as an application. I was asked in my viva was a trained mathematician ;/..
Oct 9, 2014 22:18
It is an issue but then you have to look at Edward Witten and realise that you can be both. I was always a more capable maths guy than the rest of the physics phd students at the time.. But I would definitely say I can hold my own with most math undergrads in the more applied maths (and not so applied) but as for beyond that I would have to accept that I am more of physics than maths.
Oct 9, 2014 22:13
My quantum mechanics days were gone before I did my phd. Sadly. I was looking at MHD theory so a smoothed scale above the stat mech (kinetic theory). I was always intrigued about the transport equations as they have an important place in turbulence dynamics for tokamaks.
Oct 9, 2014 22:10
Awesome. So you used used minimisation of an eigenvalue problem? Of sorts.
Oct 9, 2014 22:06
I used WKB whilst studying plasma physics (my research area) .. But back then I would apply (try) all sorts of techniques.. Especially perturbation theory for nonlinear odes. So which area are you focused on? Or better still which length scale ;)?
Oct 9, 2014 22:01
@semicassical given your awesome answers I guessing you are theoretical physicist like I was ;)? If not then you could be a "mentalist" (here I am covering all bases) .. So what is your research field?
Oct 9, 2014 21:58
@nickolas used to be? I hold a phd in physics.
Oct 9, 2014 21:55
So what topics are people (in this chat room) covering at the moment maths wise? Self taught, course etc? I can kick off with probability theory in particular the mathematics underpinning stochastic calc
Oct 9, 2014 21:45
@jasperloy it is due to my evolution from the stackexchange site to meta and now onto chats. But I was being rather over dramatic ;).
@hipstermathematician ah depends on the rate of new users vs the rate of users I meet, no? Or I completely mis read your msg!!
Oct 9, 2014 21:20
Hey @IceBoy and the rest of the room. Slowly my MSE world is increasing!!
 
Feb 26, 2014 13:58
I suggest that you put that in to another question "what is the geometrical inter. of the second order derivative and higher orders" as this is beyond the scope of this particular question. But please check this site for other occurrences of this question, and be specific as such a question can be closed down if certain criteria are not met.