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 Discussion on answer by DJClayworth: …

Imported from a comment discussion on skeptics.stackexchange.c...
justhalf
Jan 17 11:25
@user1271772 being reputable is a summary based on past evidences provided by that entity, so it is definitely objectively one factor to evaluating the truth value of the news output. As it is just one factor, DJClayworth also provides another factor: some other secondary sources with the same claim. These two factors together is the evidence put forward by him, not reducible to "it's reputable therefore it's 100% true". The missing part here is probably how DJClayworth comes to believe that CTV is reputable. That would be a valid objection to raise (which was not the objection you raised)
 

 Discussion on question by BiriBora: M…

Imported from a comment discussion on academia.stackexchange.c...
justhalf
Oct 21, 2024 02:00
@JFabianMeier as Xander said above, which you can see happening in this question.
 

 Discussion on answer by Fe2O3: When t…

Imported from a comment discussion on academia.stackexchange.c...
justhalf
Apr 11, 2024 15:01
Indeed, yes, hehe. Good art is most of the times inspiring for others.
justhalf
Apr 11, 2024 15:01
While this is an enlightening anecdote about Familiarity Bias for those who haven't yet familiar (ha!) with it, this does not answer the question. :) It is too open ended to be considered containing a claim.
 

 Discussion between Sny Smartie and ju…

Imported from a comment discussion on puzzling.stackexchange.c...
justhalf
Feb 14, 2024 03:53
Probably can just use the main chat room then
justhalf
Feb 14, 2024 03:52
Well, it seems so. I've never really made puzzles here, only solving. But people have been pointing to it all time, haha.
justhalf
Feb 14, 2024 03:51
@SnySmartie the description seems outdated, but people have been posting non-riddle puzzles there (try sort the answers by Date Modified (newest))
justhalf
Feb 14, 2024 03:51
@SnySmartie here's the sandbox. It's to help polish questions, so the final version presented here will be of better quality for the general public (of course some of the people who helped in the sandbox would have seen earlier versions of the puzzle, but it's more useful overall for general users of Puzzling)
justhalf
Feb 14, 2024 03:51
@SnySmartie for longer puzzles, it's generally advised to start in the sandbox to avoid issues such as this. :)
justhalf
Feb 14, 2024 03:51
Yea, the circle in #40 can just cover the bottom right two cells. The center is at lattice point.
justhalf
Feb 14, 2024 03:51
For #39 you can make the edge red. For #32, need to change the cell placements, unfortunately.
 

 Discussion on question by TomR: Retak…

Imported from a comment discussion on academia.stackexchange.c...
justhalf
Feb 1, 2024 22:30
Also, there is also the factor of that exam (and grades) is only a proxy of your ability. The reliability of that proxy can sometimes depend on the assumption that the exam is taken only once. One can see it as a (slightly) random sampling of your ability, if you increase the sample size, the maximum of the sampled population will in general increase, that will need to be taken into account as well, and if the number of samples in each students vary, it'll be harder to trust the numeric grades in general without additional contexts.
 

 Discussion on question by Eric Hernan…

Imported from a comment discussion on travel.stackexchange.com...
justhalf
Jan 17, 2024 15:54
@dda Huh, interviewed one by one? Like everyone goes into a separate room to be questioned individually? When I visited Japan last time this wasn't the case. Where was the entry airport in your case? Narita?
 

 Discussion on answer by Pertti Ruismä…

Imported from a comment discussion on philosophy.stackexchange...
justhalf
Jan 5, 2024 19:46
The negation of "every action is completely determined" should be "some actions are incompletely determined", right?
 

 Discussion on question by ilctf: Leav…

Imported from a comment discussion on academia.stackexchange.c...
justhalf
Jan 4, 2024 08:18
To add to TooTea, is it the case like Genie, where the data source can't possibly be replicated ethically, but still useful to use that as data source "since it's done anyway", or is it probably this way of thinking that's apprehensible and so you would not like to perpetuate it? (e.g., reasonably one might argue that using this data, while not affecting Genie, might inspire others to do unethical thing, and rejecting this publicly will be a step in preventing this to occur again, etc.)
 

 Discussion on answer by David K: Why …

Imported from a comment discussion on math.stackexchange.com/q...
justhalf
Dec 6, 2023 15:18
@DheerajGujrathi yea, your function has full domain and restricted range. That'll increase number of solutions. What we need is restricted domain.
justhalf
Dec 5, 2023 23:31
Hmm, you're right. But you get the idea. Define a function that is undefined in some domain.
justhalf
Dec 5, 2023 23:31
I was wrong indeed, I stand corrected. I guess we slightly talk past each other, and I missed that you already gave that example before.
justhalf
Dec 5, 2023 23:31
@mawaior about whether there are more, it's easy then to generalize your example. Just take any function with restricted domain, like $\log$ or square root. $x^2=1$ has -1 and 1 as solutions, but when you convert it by using $f(x)=\sqrt{x}$ (domain, positive numbers), you lose the negative number solution.
justhalf
Dec 5, 2023 23:31
@mawaior About your function, now it's clear how it loses a solution, no? The domain of the conversion function excludes $n=0$, which happens to be one of the solutions to the original problem.
justhalf
Dec 5, 2023 23:31
Just curious, who said $x=y \Rightarrow x=f(x)$?
justhalf
Dec 5, 2023 23:31
Since your argument in the main question depends on the property $x=y \Rightarrow f(x)=f(y)$, please provide an example of $f$ for converting $n^2-n=n\sin(\theta)$ into $n-1=\sin(\theta)$. Then we can talk on common ground. =)
justhalf
Dec 5, 2023 23:31
@mawaior In mathematics (which is this what this stack is about) the term "function" is not used the way you describe. It's evident when you say you're not claiming $f(n^2-n) = n-1$ in DavidK's example. You're doing an operation to convert $n^2-n$ into $n-1$. So you're doing an operation which takes the argument $n^2-n$ then outputs $n-1$. If it's also a function in mathematical terms, you would write it as $f(n^2-n) = n-1$ (which is read as: the function $f$ when given the value $n^2-n$ returns the value $n-1$), but you already said it's not the case.
justhalf
Dec 5, 2023 23:31
Agree with DavidK here. I think OP is conflating operation and function. The one that has the property defined in the first sentence of the question (x=y -> f(x)=f(y)) are functions. Operations may or may not have the same property, but that hasn't been established in the question (and they don't)
 

 Discussion between mawaior and justhalf

Imported from a comment discussion on math.stackexchange.com/q...
justhalf
Dec 5, 2023 10:05
@mawaior About your function, now it's clear how it loses a solution, no? The domain of the conversion function excludes $n=0$, which happens to be one of the solutions to the original problem.
justhalf
Dec 5, 2023 10:05
Just curious, who said $x=y \Rightarrow x=f(x)$?
justhalf
Dec 5, 2023 10:05
Since your argument in the main question depends on the property $x=y \Rightarrow f(x)=f(y)$, please provide an example of $f$ for converting $n^2-n=n\sin(\theta)$ into $n-1=\sin(\theta)$. Then we can talk on common ground. =)
justhalf
Dec 5, 2023 10:05
@mawaior In mathematics (which is this what this stack is about) the term "function" is not used the way you describe. It's evident when you say you're not claiming $f(n^2-n) = n-1$ in DavidK's example. You're doing an operation to convert $n^2-n$ into $n-1$. So you're doing an operation which takes the argument $n^2-n$ then outputs $n-1$. If it's also a function in mathematical terms, you would write it as $f(n^2-n) = n-1$ (which is read as: the function $f$ when given the value $n^2-n$ returns the value $n-1$), but you already said it's not the case.
justhalf
Dec 5, 2023 10:05
Agree with DavidK here. I think OP is conflating operation and function. The one that has the property defined in the first sentence of the question (x=y -> f(x)=f(y)) are functions. Operations may or may not have the same property, but that hasn't been established in the question (and they don't)
 

 Discussion on question by ChadTheVlad…

Imported from a comment discussion on cs.stackexchange.com/que...
justhalf
Dec 5, 2023 04:48
@ChadTheVlad the mistake is that you use structure to limit your true randomness. That structure you used is the structure of 3SAT problem. You can very well generate any problem with true randomness as a source to generate an instance of that problem. For example, you can use true randomness to generate a 2SAT problem. But we know that 2SAT can be solved in polynomial time.
 

 Discussion on answer by Wolfgang Bang…

Imported from a comment discussion on academia.stackexchange.c...
justhalf
Dec 1, 2023 22:42
@WolfgangBangerth when I said "it's not clear cut", that's precisely what I meant. PhD is not improving average salary across the board, only on some disciplines. Although, I have to give it to you, here we're talking about Mathematics (based on OP first sentence). Perhaps this clarity in scope will help other to see your point too (which might be diluted by other disciplines, as it's not a salient topic in the answer -- not a necessity since OP mentioned Math, but it's easy to see your answer as a general claim)
justhalf
Dec 1, 2023 22:42
@WolfgangBangerth I was about to find a link that support your answer, since I too believed so (anecdotally, many HRs do have a separate, higher, salary range for PhD), but what I found is not that clear cut. So I guess the money aspect is not really a big aspect worth of a confident answer such as this.
 

 Discussion between Eddymage and justhalf

Imported from a comment discussion on rpg.stackexchange.com/qu...
justhalf
Nov 4, 2023 23:07
For X=1, p=0.4, you will have two columns, right, and the expected number of 1 in your first column should be 0.16 (p^2), and the expected number of 1 in your second column should be 0.064 (p^3). (1) do you agree with this assessment, and (2) is that what you see in your simulation?
justhalf
Nov 4, 2023 16:15
Probably you should describe your simulation details as well. My simulation matches MannerPots' and my calculations. Count a hit whenever main attack or BA attack hits, divided by the number of iterations (not divided by the number of total attacks! that'll just measure accuracy) (also, I assume you really mean "number of expected hits")
justhalf
Nov 4, 2023 16:10
And I put a table as well. For the expected number of hits, and for a 1d4+3 dagger.
justhalf
Nov 4, 2023 15:56
@Eddymage which ones are you comparing? (also I just fixed a typo on my final result)
justhalf
Nov 4, 2023 15:28
@Eddymage if we're saying the same thing, then we should both get 0.2240 for the expected number of hits (including hits from BA) when p=0.4 :)
justhalf
Nov 4, 2023 15:14
Full answer posted! But no table yet, need to code it to generate nice table like in MannerPots
justhalf
Nov 4, 2023 15:13
Yep, I'm separating D (from dice) and d (from flat damage bonus)!
justhalf
Nov 4, 2023 14:27
(I am currently writing an answer which includes crits, bear with me)
justhalf
Nov 4, 2023 14:26
@Jacco that'll be needed when calculating expected damage, yes. Eddymage and I were discussing expected number of hits for now :)
justhalf
Nov 4, 2023 14:17
@Eddymage or if you want, we can also divide into 3 cases: (1) main miss, (2) main hit + BA miss, (3) main hit + BA hit. The probability of (1) is (1-p^2), probability of (2) is p^2 x (1-p), probability of (3) is p^2 x p. Expectation is (1-p^2)x0 + (p^2 x (1-p))x1 + (p^2 x p)x2 = p^2-p^3 + 2p^3 = p^2 + p^3 = p^2 (1+p), which is what I have.
justhalf
Nov 4, 2023 14:00
You need to. Consider the two only possible cases: you miss the main attack -> probability (1-p^2), number of hits is 0. You hit with your main attack -> probability p^2, number of hits is 1 + expected number of hits from BA. Your overall expected number of hits is (1-p^2) x 0 + p^2 x (1 + expected number of hits from BA). We agree thus far, I assume?
justhalf
Nov 4, 2023 12:53
@Eddymage that's what the \$p^2\cdot p\$ is doing. It's the probability to trigger the BA and for that BA to hit.
justhalf
Nov 4, 2023 11:38
The expected number of hits if you're doing 1 attack at dis is simply 1 x p^2, no? @Eddymage basically the first column in the "Chance of Triggering Bonus Attack" in this answer. The 0.2240 I referred to includes the expected number of hits from the additional BA as well.
justhalf
Nov 4, 2023 11:38
I ran 10mil simulations 3 times, the results were 0.2241, 0.2239, 0.2239. I suppose since your theoretical result is different, maybe we have different assumptions. The expected number of successful hits for 1 attack (p=0.4) is $$\underbrace{p^2}_{\text{p first attack hits, at dis}} + \underbrace{p^2}_{\text{p BA triggered}}\cdot \underbrace{p}_{\text{p BA hits}} = 0.2240 (\text{for }p=0.4)$$. What do you have for your theoretical calculation? @Eddymage
justhalf
Nov 4, 2023 11:38
@Eddymage What's your simulation result (and for how many iterations) for p=0.4, 1 attack, number of successful attacks including the bonus attack? 0.2240 here should be exact.
justhalf
Nov 4, 2023 11:38
@Eddymage are you comparing average damage? The average damage will be different, since here it doesn't take into account crit damage properly (if you modify the calculation here to include crit properly, the answer will be something that depends on N, the number of attacks). But probability to hit and probability to trigger bonus attack should be exact.
justhalf
Nov 4, 2023 11:38
Fixing that typo makes the result the same as this table :)
justhalf
Nov 4, 2023 11:38
@Jacco in your simulation, the only comparable thing is the chance to trigger bonus attack? I agree with the calculation here, though. For 1 attack, to hit +0, AC 13 (so p=0.4), your simulation says bonusAttackTriggerProbability is 0.2572, that can't be right. Both of your attack rolls need to be 13 or above to hit. The chance of that happening is 0.4*0.4 = 0.16, which is what the first cell in this table shows. In your code, you have a typo in "if (attackRoll === 1) {return 'mis';}" which causes the number of misses to be undercounted.