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Martin Sleziak
Martin Sleziak
04:43
This room has been relatively silent recently. Just in case it gets frozen, I will remind that moderators can unfreeze chatrooms - so you can ask some moderator (from any site) whether they would be willing to do so. See also: meta.stackexchange.com/tags/frozen-rooms/info and How do I unfreeze a frozen chat room?
 
2 hours later…
BooleanWick
BooleanWick
07:08
8
Q: Closed form of $2\sum_{n = 0}^{m - 1}(-1)^n\zeta(4m - 2n + 1)\zeta(2n + 2)$

BooleanWickIs it possible to simplify the below sum? or maybe find a nice closed form (or asymptotics)? $$2\sum_{n = 0}^{m - 1}(-1)^n\zeta(4m - 2n + 1)\zeta(2n + 2)$$ I am very much aware about even values of Riemann zeta (Euler's formula in terms of Bernoulli numbers) and that would definitely give us a ni...

asymptotics riemann-zeta
 
16 hours later…
bobble
bobble
23:16
I attempted to edit this answer to make the image and code block in proper Markdown tables, as that is much more accessible for screen readers. However my edit got auto-detected as spam so it didn't go through :( Here's the Markdown source of my edit as a pastebin if anyone wants to apply it.

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