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3 hours later…
3:15 AM
@UnrelatedString 2 is possible :P
 
3:34 AM
:P indeed
 
Why doesn't fE work? Edit: never mind, I'm dumb
@ChartZBelatedly ⁼f
I feel like some variation of ḟ¬ should work too :(
 
4:02 AM
@user ḟṆ?
 
@UnrelatedString Noce, thanks!
And another possible 2 byte solution would be prepending A to the list and then doing E
 
@user Yep, ;E is another possible solution :)
 
4:26 AM
@ChartZBelatedly There serm to be a lot of these
Tine to find q one byte solution :P
E if input fornqt hqs the number qs pqrt of the list
 
4:42 AM
@user I very much doubt there’s a one byte solution unfortunately
 
@ChartZBelatedly Lemme just hack into TIO’s server and make an empty program implement your cmc :P
(btw replace q with a above, I switched to azerty)
 
 
10 hours later…
2:58 PM
CMC: Given a list A and an integer I, test if all elements of A are less than or equal to I. Your solution should work for lists with arbitrary depth (i.e. lists within lists etc.)
 
 
2 hours later…
4:39 PM
@ChartZBelatedly So for A=[[3,4,5],6], I=6, would it be 0 or 1?
Would 6 be compared to 3, 4, 5 separately or to the list [3,4,5], I mean?
 
@user 1
Comparing the integers, not the lists
 
5:06 PM
Oh ok
 
 
3 hours later…
7:54 PM
@ChartZBelatedly >FẸṆ, but there's probably a better way.
 
@user There is. It's doable in 2 bytes, but good first shot :)
 
8:09 PM
÷ỊFẠ is another disappointment
 
8:20 PM
@ChartZBelatedly Does it have something to do with Ṁ>? (and does it invert the outputted boolean?)
 
@user It kinda does I guess and it outputs normal boolean
 
@ChartZBelatedly Mmm, this is a tough one.
 
@user Let me know if you want a hint
 
I'm a bit surprised Jelly doesn't have ≤ or ≥, actually
@ChartZBelatedly I think I'm going to tear out my hair for a few minutes more first :P
 
@user As you should :P
 
8:37 PM
Look, I increased my score! F>ƇȦ¬
@ChartZBelatedly Can I have that hint now? I'm stuck :P
 
@user Take a look at my latest Jelly tip
Spoiler, it contains the answer
Try and do it without looking at the table of atoms in the answer :P
 
@ChartZBelatedly It's going to be hard.
 
@user How so?
 
@ChartZBelatedly Not looking at the table, I mean
 
@user The answer's nearer the end so just don't scroll down :P
 
8:44 PM
So basically, you need a dyad that gives you x if x is less than or equal to I, and something else that is not x otherwise
 
@user Yeah, basically
 
Looks like the minimum of x and I should do that.
@ChartZBelatedly «Ƒ (Thanks for all the help!)
 
@user Nice :D
 

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