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4:42 AM
@JohnRennie Sir have you woken up?
 
@Knight hi :-)
 
@JohnRennie Hello
Your tea done?
 
I have about 5 minutes work to do ...
 
Okay sir. I’m waiting
 
OK, I'm free now.
 
5:03 AM
@JohnRennie hi
Hello Hello Hello! Is anybody in there ?
 
I'm just answering a question in another room
 
@JohnRennie 😁
 
14 hours ago, by John Rennie
> The external force F cannot produce a moment either, this is certainly true when we assume a continuous distribution of lines of force; such a distribution can be always considered as parallel in any infinitesimal region (the field of gravity is a simple example for what is meant)
Is that what you want to ask about?
 
@JohnRennie Yss
Especially that “lines of force” part
 
Consider the Earth's gravitational field.
Here we also have lines of force, and when you do basic physics problems you draw these lines of force as parallel lines pointing down. Yes?
 
5:20 AM
Yes
 
But the lines of force aren't parallel. They all point towards the centre of the Earth, so if you zoom out to view at a large scale you see radial lines of force all pointing towards the centre of the Earth.
But when you zoom in to say human scales than the divergence of the lines is so small they appear parallel to us.
And this is what Sommerfeld is saying about lines of force in a liquid.
 
Yes
 
When you look at a large scale the lines of force diverge and/or converge.
But in Sommerfeld's treatment we are assuming infinitesimal cubes in the liquid, and on such a small scale the divergence of the lines is too small to be detected so the lines just look parallel.
 
@JohnRennie Yes. So, how that parallelism has to do something with torque or moment?
 
Let me dig out Sommerfeld's book again.
 
5:26 AM
Yes
Sir
 
Yes
 
If you have parallel force lines than they cannot produce a moment because for any point there are the same number of lines either side of the point.
 
@JohnRennie But the volume element is not infinite. If we take the right most point then?
 
So if you calculate $\sum Fr$ for the point the positive and negative values of $r$ cancel and the net moment is zero.
@Knight you're going to be calculating the torque about the centre of the cube.
 
5:33 AM
@JohnRennie Sir, I’m sorry but I think I’m missing something, can that cube rotate only about the axis passing though it’s center?
 
If you take an isolated object it can only rotate about its centre of mass.
 
Okay
 
The cube isn't isolated, but we assume its surroundings are symmetric.
 
Symmetry = isolation? I think that requires too too much explanation, let’s just accept it
Okay that parallel lines of force doesn’t permit any rotation because we got equal number of lines on both the sides
 
5:51 AM
I don't think Sommerfeld is describing this very well. What he's basically saying is that the curl of the vector field is zero.
And what he's leading up to is saying that any vector field that has zero curl can be written as the gradient of a scalar potential.
I would guess you already know this as it's a very standard result e.g. in gravity and EM.
 
Yes sir!
 
It's also not true that a fluid flow always has zero curl unless you impose some extra conditions to make this so.
 
There are two possibilities: either he was really obtuse in that explanation or translation messed up something
 
For example water flowing in a river has a non-zero curl and it can and does make objects in the flow rotate.
 
Yes
I see it every day. I think tap water can be assumed to have zero curl
 
5:58 AM
What are you trying to achieve by reading Sommerfeld? I'm not sure it would be my first choice of physics book ...
 
@JohnRennie Hahahahahaahha, He is complete in himself (just like you) that’s why I like him. But I think my reading of him causes you so much trouble :-)
Explaining someone else’s work is very hard (and even to someone like me)
God bless you, God bless your patience !
 

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