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Yuvraj Singh...
Yuvraj Singh...
5:58 AM
@JohnRennie hi.
 
Yuvraj Singh...
Yuvraj Singh...
6:15 AM
@malavika ask for permission m
Fine.
How is the wether in kerala.
And what about CAA and NRC.
@Malavika
I heard very much that protest in kerala goes brutal.
@malavika ok
@malavika I got that video.
Some company of Mumbai done that
@skull patrol hey!
@malavika it is not much good to watch that
 
skullpatrol
skullpatrol
Thanks, pal :D
I was starting to think you didn't want me around...
 
Yuvraj Singh...
Yuvraj Singh...
6:31 AM
@skull patrol no, sorry I am suffering from cold, so by mistake I missed your request.
 
skullpatrol
skullpatrol
when I made the request you said "yes skull?" then deleted the message?
 
 
8 hours later…
Yuvraj Singh...
Yuvraj Singh...
2:32 PM
@JohnRennie hi sir, Alesha here have a question!
 
John Rennie
John Rennie
@YuvrajSingh... hi :-)
 
Yuvraj Singh...
Yuvraj Singh...
@JohnRennie actually sir I have two situations!
 
John Rennie
John Rennie
I only have ten minutes before my lunch is ready. Is it a quick question?
 
Yuvraj Singh...
Yuvraj Singh...
One with friction and one without friction.
@JohnRennie yes sir we can finish that in ten minutes.
 
John Rennie
John Rennie
OK :-)
 
Yuvraj Singh...
Yuvraj Singh...
2:34 PM
@JohnRennie and a ball rolled down from inclined.
 
John Rennie
John Rennie
OK
 
Yuvraj Singh...
Yuvraj Singh...
So if I use the energy conservation in both cases.
Like in first one Mgsintheta(s) =change in k. E
Where s is the distance.
@JohnRennie
 
John Rennie
John Rennie
Yes, the increase in total kinetic energy, translational + rotational, is mgh where h = s sin(theta).
 
Yuvraj Singh...
Yuvraj Singh...
And second cases mgsintheta(s) - f_(l) =change in k. E
@JohnRennie but in both cases the final and k. E is zero.
Yes sir?
 
John Rennie
John Rennie
What is f_(l)
 
Yuvraj Singh...
Yuvraj Singh...
2:37 PM
Kinetic friction.
 
John Rennie
John Rennie
Ah, OK, yes sorry I didn't realise it was a rough surface.
 
Yuvraj Singh...
Yuvraj Singh...
Yes.
So as I said in both cases k. E is zero.
If your answer is yes then how can it be possible
Mgsintheta(s) work equal to zero
And friction work too is zero.
@JohnRennie
 
John Rennie
John Rennie
We will have to pick this up tomorrow I'm afraid. My lunch is ready now.
 
Yuvraj Singh...
Yuvraj Singh...
@JohnRennie ok, sir but remember in morning I will be first.
 

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