1 min ago, by
Abhas Kumar Sinha $$ \nabla^2 = \left[ \dfrac{1}{r^2} \dfrac{\partial }{\partial r} r^2 \dfrac{\partial }{\partial r} + \dfrac{1}{r^2 \sin \theta} \dfrac{\partial}{\partial \theta} \sin \theta \dfrac{\partial}{\partial \theta} + \dfrac{1}{r^2 \sin^2 \theta} \dfrac{\partial^2}{\partial \phi^2} \right] $$