@SaalHardali FFES = fully faithful and essentially surjective
@SaalHardali Yes, and I would say this is known, though the general topos version might need some slight variants of what's actually in the literature. (Note these are internal operads though, not enriched)
For a general topos, I think you want to localize w.r.t. something like the product of the Segal inclusions with a set of generating objects
@RuneHaugseng When you emphasis these are internal as opposed to enriched do you mean that this definition might work in the generality of a Topos but not necessarily for arbitrary symmetric monoidal categories?
I think in a topos enriched categories are the same as internal category with constant space of objects, but I don't know a reference off the top of my head. No idea of what happens for operads
So how does one model enriched operads in the Lurie framework? I only just touched this part in HA but from the beggining it seems like hes developing "plain" $\infty$-operads...
I don't think people have a well-developed theory of that yet. You can pretty much work out the theory for enriched operads with one object by mimicking the classical definition, and that's been enough so far
Although there are people in this room that know much more than me on this
So do I understand correctly that the content about Operads in HA is in the framework of symmetric $\infty$ multi-categories and it doesn't directly talk about stuff like "operad in spectra" for example?
@DenisNardin I mean, the ∞-category of spectrally enriched ∞-categories is symmetric monoidal by Gepner-Haugseng, so we can take $\mathbb{E}_{\infty}$-objects in there?
Slightly unrelated question. What's the stabilization of the category of (single coloured) $\infty$-Operads? Actually I don't even know what's the stabilization of $A_{\infty}$-Spaces so maybe this first?
(I need to add pointed everywhere)
user131753
Probably a naive question, dut does anyone know the rationale behind the name of "commutative diagrams"? To be precise, what is(are) the reason(s) for calling those diagrams "commutative" and in what sense?
@user170039 I assume MacLane was thinking of natural transformations when designing his terminology. The naturality square can be thought of as a commutation relation for the natural transformation.
From Eilenberg & Steenrod, Foundations of Algebraic Topology, preface:
The reader will observe the presence of numerous diagrams in the text. Each diagram is a network or linear graph in which each vertex represents a group, and each oriented edge represents a homomorphism connecting thegroups at its two ends. //
A directed path in the network represents the homomorphism which is the composition of the homomorphisms assigned to its edges. Two paths connecting the same pair of vertices usually give the same homomorphism. This is called a commutativity relation. The combinatorially minded individual can regard it as a homology relation due to the presence of 2-dimensional cells adjoined to the graph.
(It's still not clear to me why commutative is the word chosen for this.)
I am with @TomBachmann: It expresses the fact that the order of doing things does not matter. If $f:A\rightarrow A$ and $g:A\rightarrow A$ then there is one obvious diagram one might write down. If it is commutative then $fg=gf$. If one interprets a group as a category (The group as the single object: morphisms are left multiplication by group elements) then every diagram in the category is commutative iff the group is commutative.
But a commutative diagram can also express something like $fg=hk$, which is not in any sense a matter of "order of doing things does not matter". It's just an identity between two different expressions.
@EspenNielsen I feel like this might be doable using Hinich's results, which give a really nice way of getting (say) spectra as a spectral infinity-category, but haven't thought about it.
2 hours later…
user131753
6:06 PM
@CharlesRezk I had some discussion with one of my friends regarding this. He said that maybe the idea that is intended to be conveyed is something like the following, namely that the operation done first along a "row" and then along a "column" is equal to the operation done first along a "column" and then along a "row" (for a commutative square, of course).
user131753
I have asked a question regarding this in MO here.