« first day (2139 days earlier)      last day (2250 days later) » 

12:20 AM
@Rick Zeistsev Rule
 
12:37 AM
@AvnishKabaj Would you stop doing edits, which just remove homework tag?
 
@Mithoron Okay
 
12:54 AM
@AvnishKabaj Thanks, try to make your edits substantial, you can add links and stuff. This is bumped to homepage and needs to be reviewed...
 
1:15 AM
@Mithoron I do see every approved edit and if it has been improved, learn what I missed
I didn't get what you meant by add links
 
Huh? Links to other posts or sites
 
1:30 AM
@Mithoron Will keep that in mind
 
@Rick yep Abcd is right
@Rick dehydration of butan-1-ol through conc H2SO4 forms a primary carbocation, which then rearranges by hydride shift to a stabler two degree carbocation, and then loss of another proton forms but-2-ene
@AvnishKabaj that applies to E2 elimination and not E1 elimination
 
1:53 AM
@GaurangTandon right I was dehydrating 2 Butanol for some reason
 
 
4 hours later…
5:26 AM
@GaurangTandon ok yes
 
6:22 AM
3
Q: Orientation in Benzene Rings With More Than One Substituent

CarrickWhy is it that the chlorination of 1-chloro-3-nitrobenzene 18 gives 1,4-dichloro-2-nitrobenzene 19 as the major product, 1,2-dichloro-3-nitrobenzene 20 as a minor product and 1,2-dichloro-4-nitrobenzene 21 is not formed at all? I know $\ce{-NO2}$ is a deactivating, meta-directing group and hen...

@AvnishKabaj @GaurangTandon I found a duplicate just after I finished typing my question^
@GaurangTandon Page 579 in March's Adv Organic Chemistry
 
6:46 AM
@Abcd That question didn't get answered prope
 
7:14 AM
@Secret it wasn't a dream, or an accident. I did it
Unfortunately, you're still alive
I'll give it another shot tonight
 
7:41 AM
@AvnishKabaj yeah..
 
 
2 hours later…
9:23 AM
@Abcd on chem, or somewhere else?
I just went to the bathroom and reviewed close votes.
Striking resemblance between some of the questions and the thing my body was getting rid of.
True story
 
@M.A.R. nah, somewhere else.
 
Math.
Anyway, each site, or even reach mod, has their own ways of interpreting and dealing with edge cases like that
 
@M.A.R. you have a new liver now?
 
9:59 AM
@AvnishKabaj kidney, and I wish
in The Screening Room, 4 mins ago, by M.A.R.
@AJ no unfortunately
Just read the other chat. I'm lazy.
BTW, @Avnish, no. I'm much more inclined to think someone is cool if they came up with anything other than their real or realish name as a username.
You just got more upvotes most probably because fellow Indians liked to trust your words as someone in the same sinking boat.
 
10:16 AM
@M.A.R. Were you an alcoholic
@M.A.R. I sort of got lucky on a Wikipedia copy paste answer
 
@AvnishKabaj underage and in an Islamic country? Probably not.
 
@M.A.R. HEY MAN ! How are you ? How have you been ?
It's been such a long time @M.A.R.
 
 
2 hours later…
12:47 PM
@Abcd that question got such a boring answer; i'll try formatting it to see what it means
 
Hey In group 16 of the periodic table oxygen has a higher electronegativity yet when an electron is added to it's valence shell other electrons will resist this newly added electron and thus the electron gain enthalpy of oxygen is less negative than suplhur
 
@susanJ it's the same effect as that between fluorine and chlorine
 
According to definition electronegativity is the ability of an atom to attract the shared pair of electrons to itself, oxygen if it attracts the bonded pair of electrons wouldn't this cause electron electron repulsion in valence shell ?
@ Gaurang yes i know that
 
@GaurangTandon Three explanations. First: 20 downvotes after that ; Second:Pro Hacker; Third: Bug
@susanJ You're confused between electron negativity and electron affinity
 
I know that both aren't related but i find it puzzling :P
if oxygen can attract a shared pair of electron to itself they why can't it have a higher electron affinity
the pair of electrons are attracted to the valence shell ryt?
 
1:43 PM
@AvnishKabaj ha yeah; it still is weird
 
Affinity is when the electron enters the orbit; negativity is the pulling tendency
2
 
ohh
I thought so damn i wasted hours thinking why
 
@GaurangTandon moderators may convert posts to comments where needed
 
@orthocresol oh, that makes sense
mod magic ;)
 
Thanks @AvnishKabaj
 
1:45 PM
@susanJ You're welcome
@GaurangTandon So much for my awesome theories
 
@AvnishKabaj I had one more question. In NCERT it's said that oxygen has a covalency of 4 ( 1 s and 3 P) orbitals but, the covalency of oxygen is usually 2 why??
 
@AvnishKabaj haha :P lesson learnt: next time if you see anything weird in the site, know that the mods are behind it ;P
@susanJ which page number is that?
 
hm 182
 
@susanJ Dunz I don't like inorganic
 
It reads " The absence of d orbitals in oxygen limits its covalency to four and in practice it rarely exceeds two "
@AvnishKabaj Hahaha it's interesting for me
 
1:50 PM
@susanJ page 184 is thermodynamics for me
 
Anybody got the answer?
 
@susanJ Make the electron box diagram you'll figure it out
 
thermodynamics is the most hate deserving :P
 
@susanJ ha but I meant to say the thing you're quoting is not on that page;
this is NCERT Class 11th right?
 
no no
ncert 12th
part 2 chem
 
1:52 PM
@susanJ Probably it says Oxygen can at max make 4 bonds like in here: en.wikipedia.org/wiki/Zinc_acetate#Basic_zinc_acetate
 
@susanJ ¯\_(ツ)_/ ¯
 
hmm
 
@susanJ that's page 182 -_-
 
yep
 
6 mins ago, by susan J
hm 182
 
1:54 PM
@Rick wow!
@Rick ok nvm i misread
@Rick my prof told me that the max covalency is 3 as in hydronium ion
@Rick and that diagram, how come three bonds of oxygen are in the plane and only one bond is wedge?
one of those three solid bonds should be a dash bond instead, at least, if it's a tetrahedral structure
what say?
^-- can anyone tell how this is possible?
I think this is wrong, anyone disagrees with me?
 
I have a question
 
@GaurangTandon It's correct
 
IS covalency and hybridisation related
?
 
@susanJ yeah
No
 
How?
 
2:01 PM
Dunz
 
@AvnishKabaj and why?
@Curio just ask
 
@susanJ for your oxygen thing it takes a lot of energy to excite the paired electron pair to the d orbital
 
Consider C2H4. How can I write the angle bond? I saw that I have to split the molecule
 
@AvnishKabaj ? oxygen doesn't have d orbitals?
 
@Curio do you know the hybridization of each carbon atom?
 
2:02 PM
@Rick No?
 
No
 
@AvnishKabaj covalency is the no of pairs of electrons shared usually oxygen shares it's 2 bonds that's why covalency is 2 . I understand that it takes a lot of energy to excite the electron but i was wondering if hybridisation is involved in this bonding process.?If oxygen has a covalency of 4 then it's for coordination compounds but then again it has only 3 pairs of valence electrons
 
@Rick do you agree with that reso I posted above? @AvnishKabaj Why do you think it's correct?
 
@susanJ I'm in eleventh no idea about co-ordination compounds
@GaurangTandon I don't see what's wrong
 
@AvnishKabaj from where did the third pi bond come into the ring?
 
2:05 PM
@AvnishKabaj wow im in 12th and still have no idea abt the basics im just starting
 
@GaurangTandon Hyperconjugation?
 
@susanJ just remove the covalency thing from your mind; you'll pass 12th easily without caring about it; it doesn't matter
 
:/
 
@susanJ ¯\_(ツ)_/ ¯
 
@susanJ well i've had my fair bit of a poor experience with it; you may read if you want to
 
2:07 PM
It's just a fact thing; inorganic
 
@AvnishKabaj no, hyperconj is just a temporary effect; cannot permanently introduce a pi bond into the ring
 
@GaurangTandon It does if the compound regains it's aromaticity
The enol tautomer of benzene is like waaaaay more than ketone
 
@GaurangTandon yeah...i think there should have been a (-) charge at the left C-Cl
what's the context/full question?
 
@AvnishKabaj there isn't any sp3 hydrogen atom for hyperconj to be possible
@Rick this user's answer; his other answers are usually good, but this one's a bit wrong; link - chemistry.stackexchange.com/a/89619/5026
under "Chlorine attack at C-4"
i'm willing to downvote the answer and leave a note explaining why; if you confirm that resonance is wrong
@Rick i assumed that negative charge to be neutralized by the incoming Cl(+) electrophile
 
oh lol
 
2:14 PM
i've formally downvoted that answer and left a comment explaining why
 
@GaurangTandon sp2, but how can this be useful?
 
@GaurangTandon Oh well..in that case I think 1 H+ is lost and not shown
 
@Curio you know the bond angles in various hybridization schemes? 109.5deg in sp3; 180deg in sp; ???deg in sp2?
 
Yup
 
2:19 PM
But I was asking a different question
 
@Curio how? explain
 
as done here
 
In this case (C2H4) we don't have the form AXn. I mean, there isn't a central atome. So do I have to split the molecule?
 
@Rick oh god wasn't that supposed to be lost right after the first step!
@AvnishKabaj yep good catch!
ok I reverted my downvote
but I don't understand what he's trying to say. @Rick @AvnishKabaj any idea?
@Curio well, you can view each carbon atom directly; you don't necessarily have to split the molecule; VSEPR works on any atom you want it to make it work on
 
Hello. Why in nitration of aniline para product is more dominant? (In acidic medium)
 
2:27 PM
it's almost 50:50 if I remember
 
@Fawad well para is almost always dominant for any op directing group like aniline; though it's definitely not "major" in this case you're talking about
 
It’s 51:49 in my text book
 
@Curio just see the left atom; it has three sigma bonds and zero lone pairs; so it's hybridization is sp2; simple! what's your query in it?
 
The double bond splits the molecule in 2. So we have AX3 2 times and we can say that the angle is 120
 
2:30 PM
@Curio just don't rote learn those AX3, AX3L, AX4,etc. stuff too much; instead remember that if hybd. of an atom is sp^n it implies that sum of lone pairs and sigma bonds = n
 
sp^(n-1)
According to your previous message
However to say that n=3 you've splitted the molecule in 2 parts. In fact all bonds are 5
 
in Tavern on the Meta on Meta Stack Exchange Chat, 1 min ago, by Taryn
@Fawad the answer was converted to a comment by a mod
 
@GaurangTandon for example, what about HNO2?
 
16
A: Is the ammonium substituent (-NH3+) really meta-directing in electrophilic substitution?

ron how is anilinium ion meta directing for electrophiles? Actually, anilinium is not meta directing (I know it is often taught that way), but rather it inductively deactivates the entire aromatic ring. To explain the electrophilic substitution pattern observed with any aromatic system we must...

read this
 
What exactly happens to an electron when energy is provided for it's penetration of a metal's valence shell?
the energy of the electron increases does that mean it moves to an even high potential energy state but what would be the use?
If the exited electron enters the valence shell of the metal which is at a lesser potential i suppose some amount of energy will be released, is that so? But this ENERGY is less than the provided energy.
I thought of the meteor analogy, a meteorite falling from the sky would lose most of it's kinetic energy as heat i guess the same happens with electrons...
 
2:52 PM
@Curio each carbon atom has only four bonds
@Curio you need to know its structure
@Fawad oh thanks!
@susanJ what do you mean by "penetration" of the shell? o.O
 
@GaurangTandon youtu.be/uwctdg83K6g
 
@Curio so.... what?
 
Here we don't have a center
 
@Curio i said you don't need a center; VSEPR works on any atom you want it to make it work on
 
How can I determine the angle in this case?
 
3:03 PM
@Curio if hybridisation of an atom is sp^n, it implies that sum of lone pairs and sigma bonds it forms is n
do you agree?
 
Yes
 
and we know that hybridisation is related to bond angles; sp=180deg; sp2=120deg;etc.... agreed?
 
Yes
 
so if an atom is symmetrical like CCl4, all its bond angles will be equal; yes?
 
Yes
 
3:05 PM
great!
well that's the boundaries of VSEPR
in the case of ethene, as you probably already know, 120deg is a rough approximation
now that your base is clear, read this question
3
Q: What's the H-C-H bond angle in ethene?

RobChemThe carbon is $\mathrm{sp^2}$ hybridised and is therefore planar and should also, theoretically be $120^\circ$. However, VSEPR theory suggests that the π bond would "need more space" due to greater electron repulsion. As a consequence the $\ce{H-C-H}$ bond angle would be smaller. However, since the

 
In my case N's hybridization is sp2, isn't it?
 
(brb 10mins)
 
Ok
 
@Curio yes it is
 
3:23 PM
@GaurangTandon I noticed that because of the double bond. Does this always happen?
 
@Curio you might wish to read chemistry.stackexchange.com/q/91650/5026 ...
and then ask again
 
@GaurangTandon I meant forcefull entry of the electron
As it's entry wouldn't be promoted by the atom we provide external energy
IS this external energy provided to the atom or the electron?
 
@susanJ you meant electron affinity, right?
 
Yes or the negative of it - electron gain enthalpy , for metals it's positive
indicating external energy rather than energy released
 
@susanJ it's most probably provided to the electron
because the electron requires extra energy to enter the atom's orbits
 
3:30 PM
That is to say the electron goes to even a higher potential
so if it is to enter the valence shell which is at a comparitively lower potential it must lose some of it's energy
which contradicts the fact that energy is not released
Not some energy actually it would lose more than the unexcited case
 
i don't actually understand what you just said :/
 
Hmm suppose a man is standing at the top of a mountain
he is to fall from that height he'll lose all his potential energy and maybe he'd burn and produce thermal heat
 
if we were to displace this man to even a higher height the energy produced will surpass the one frm scenario one
 
3:35 PM
that's what I think happens when we excite the electron we are trying to stick into the valence shell of the metal
 
@susanJ "excite the e-" out of the shell or into the shell?
 
it'd release even more energy , that's the energy we provided and the energy released by this electron will be almost the same
out of the shell
exciting always means it gets more energy ryt
so why would it stay in a low energy orbital
 
you excite when measuring ionization potential
you forcefully insert electrons in case of electron affinity
 
so no energy is imparted to the electron?
no excitation?
 
well i don't at all understand what you're saying :/
better re-read your book
or ping someone else here
sorry
 
3:38 PM
there's nothing in my book
 
it's getting confusing for me
 
i overthought everything
yeah i know i confused everyone :P
 
overthinking is the worst enemy
take a good night sleep and rethink again
my suggestion
 
yeah the problem with indian education system is that it obstructs thinking
everybody just mugs up . I'm not boasting but yeah that's a sad truth.
Are you doing your bachelors in chem?
 
@susanJ i'm about to pass high school
 
3:40 PM
Oh i thought you were doing your masters or something
your answers are very thoughtful
 
you're welcome :)
 
Well all the best for your exams :)
 
thanks :)
 
hahah bye good night
 
yep good night to you too!
 
3:41 PM
btw what 's ionisation ppotential?
 
@susanJ arrrggghhhh :P
 
:P
 
it's just ionisation energy divided by charge on electron
 
okayy
 
just like potential=work/charge
 
3:42 PM
i see
thanks for the help see ya bye
 
4:03 PM
@GaurangTandon I think that I got it! Many thanks!
 
4:24 PM
@GaurangTandon but hybridization works only for the second period
 
4:40 PM
@GaurangTandon For example H2O has sp3 hybridization. However the bond angle isn't 109.5 but 104.5 and above all the shape isn't a tetraedron but bent!
 
@Curio i see you're just getting started in hybridisation
there's a lot of small details
as I said before, the O atom isn't symmetrical
there's a lone pair disturbing the symmetry and taking up extra space than a bond pair
it's impossible for me to explain everything in chat, you really want to read some introductory book on this topic
 
So I have to apply some changes
If there are lone pairs I have to change the angle and the shape then
In fact C6H6 hasn't these problems
 
@GaurangTandon How was ISC chemistry?
@GaurangTandon Benzene's reaction with ozone gives how many many products? (not my question, just asking you ...)
@AvnishKabaj "Orbit", huh?
 
@GaurangTandon @AvnishKabaj got any answers lately? For the boiling point trend question of mine.
 
 
1 hour later…
5:58 PM
@Rick @Mart did say he'd disappear this time, unlike every other time
@Tanuj thanks . . . THANKS! I DON'T GET THE EXCITEMENT. I WASN'T GONE FOR A YEAR
@AvnishKabaj Veiled rant on treating atoms as planets
 
6:19 PM
Anyone in here willing to help me out with some lab stuff?
I'm thinking of making a SE post but thought I'd run it by here first
 
Just post the question here. Anyone that can help comes by and answers
Don't ask to ask. Just ask.
^ The only sentence in Math chat that has made sense so far.
Or maybe it was some other chat.
 
Alright
 
@M.A.R. physics
 
@Loong Ohai master Loong
2
@MichaelHarding was that a trick "alright"?
Oh crap, maybe you're posting on main
 
Essentially I'm an undergrad doing a small research project on biofuels. I decided I want to investigate the relationship (if any) between the fatty acid content in vegetable oils and the quality of the biofuels produced.
So I have two things I need to work on: producing the biofuels, i've chosen to do it through a transesterification. And also determination of the fatty acid content of the biofuels.
In the lab today I chose to do a titration. Decided the best solvent for vegetable oil was propan-1-ol and made up a solution of approximately 0.1M KOH which I titrated it against. However I've
My rough titre was something like 1.50 cm3 which would have a massive error with a 50 cm3 burette
I was wondering if I wanted to calculate acid number if I need to do such an accurate titration since i had troubles pipetting the oil
I might go and post on the main SE
Since there's quite a lot i want to discuss
And I need help lol
 
7:02 PM
@M.A.R. @Abcd Dear kind sirs < insert snarky reply >
@MollyCooL I haven't been able to find any proper source but I Excel at cooking up justifications for observed phenomenon.
 
7:41 PM
@GaurangTandon I do not quite understand your edit to my question chemistry.stackexchange.com/questions/91783/…;. Why don't you want the URL to be clickable? Why did you put a clickable "URL" next to the - now not clickable - http:/ /...?
 
@mhchem You can just roll back.
 
@Loong I want to understand first.
 
8:12 PM
Wow, years in bold looks cool.
2018
I would follow a guy to hell if they type years in bold.
 
My "Is that ironie, sarcasm or dangerously weird?" detector spins frantically in circles.
 
Zhe
8:33 PM
@mhchem We have a bunch of new reviewers, and they might not be up on best practices yet
 
 
1 hour later…
9:35 PM
Loong is on fire
Meaning, reacting with oxygen
Edit needed:
-1
Q: Determining the equilibrium constant for titrations given Ka

SpeedoGiven info: H3PO4 + H2O <--> H2PO4- + H3O+ Ka1= 6.9e-3 H2PO4- + H2O <--> HPO42- +H3O+ Ka2= 6.2e-8 HPO42- + H2O <--> PO43- + H3O+ Ka= 4.8e-13 Solve for: K' values. Weak acid+ strong base H3PO4 + OH- <--> H2PO4- + H2O K'=? H2PO4-+ OH- <--> HPO42- + H2O K''=? HPO42-+ OH- <--> PO43- + H2O K''...

Preferably from young male, graduated from Harvard
3
Shoe size 4
 
10:08 PM
@M.A.R. what does he/she mean by 6.9e-3?
Actually leave it. I am not editing it. I am just flagging it as homework.
@AvnishKabaj Could you please make me mark the 11th level questions of MS Chauhan because I end up wasting time on 12th level stuff? I'll be really grateful to you.
@GaurangTandon Consider starting a bounty for this?
 
@Abcd 6.9 × 10^-3
 

« first day (2139 days earlier)      last day (2250 days later) »