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17:00
*stack
*stock
Stock Exchange is the thing with all the stocks and shares and stuff
*snoke
I've seen the NYSE building, but I've never been inside
Zee
Zee
17:00
Spoke
I hear it's nice.
Spook
@AkivaWeinberger yeah. this is the stockings exchange
17:01
Stoke
Zee
Zee
Break
everyone give me your stockings
hello I am facing a problem
NAOW!
gives stalk of corn
17:01
XD
well, this took a turn.
@IccheGuri details?
Zee
Zee
@Typhon totally not gibberish
@Semiclassical rerouting destination
assuming direct control
17:02
we are now going to the moon
@Semiclassical DC outlet activated
fly me to the moon, let me play among the stars...
freak out in the moonage daydream, oh yeah
@Zee sends you to Mars
17:03
pretty sure the scanners clip is again relevant for the chat as whole right now
Zee
Zee
Eva
because we're just all over the place
I have 6 boxes
Nice
Can I have one
Six is too many for one person
17:03
@Semiclassical Nooooo! I don't wanna be scanned!
THe no of choclate in boxes are respectively :
6 8 3 1 1 4
i'm listening to that song right now. i dunno why but i am
Zee
Zee
Me too
Alright am gonna go play video games to wake my brain up
i really wonder how much cocaine one needs to take to dress up like that and waltz around on stage with that much self confidence
$1_0^2~1_1^2\mid6_{-1}^2~1_1^2\mid7_{-1}^2~7_0^2\mid 7\sharp_{-1}^2~5_0^14_0^1$
17:07
@Zee I'm gonna go work on my game to wake up.
@AkivaWeinberger what key?
@Secret $A$ minor
I want to take some chocklate from one box and place these choclate in another box
harmonic A minor?
@Secret Well, there's both a $7$ and a $7\sharp$ so I dunno
When it's a $7$ it's the normal one
(forget what it's called)
@IccheGuri I'll take box $2^{sin(\frac{\pi}{2})}$ please
what is the reason to choose this ?
Oh (censored), I cannot handle combinitorics problems. Guess you need to ask someone else
gives everyone in chat a piece of chocolate
17:09
@Typhon
yes???
@IccheGuri He was joking
^^^
made my day
it had 8 pieces in it (the most)
17:11
but I can not finding the logic behind this problem .
so im taking that box and giving everyone some chocolate
Can you help me ?
i have no clue
Find the ones that are opposite the parity they're supposed to be
and move chocolates among them
Ok Simply let me state the problem first
17:14
$1_0^12_0^13_0^14_0^1\mid \underbrace{7_{-1}^4\mid 7_{-1}^4}\mid3_0^2~2_0^2\mid 1_0^2~7_{-1}^2\mid \underbrace{1_0^4\mid 1_0^1}\emptyset^3$
$$\sum_{t=0}^k\binom{n-t}{r-t}$$
@Secret I realized I didn't decide how to do ties (notes that are longer than a measure)
So I did that ^
(Again $A$ minor)
That's what measure theory is, right? /s
how to find a closed form for $$\sum_{r=1}^k\binom{r+9}r$$
Dunno but my first instinct would be to look at Pascal's triangle @RE60K
Sounds like hockey stick
17:23
@RE60K what makes you assume it has a closed form?
It telescopes , I had solved it in past
unfortunately I lent out my old notes
Yeah it probably does
@RE60K I'm pretty sure that'll be covered by the hockey-stick identity
It becomes $$\frac{k+1}{10}\binom{k+10}{k+1}-1$$
Is it called Pascal's identity, when two binomial coefficients add to another one?
17:24
As discussed in this question here: math.stackexchange.com/q/1490794/137524
Use the symmetry of the coefficient
No it has fixed bottom in binom
None of the answers use telescoping unfortunately
You have $\binom{r+9}r=\binom{r}{9}$
Oh!
So yours can also be expressed with a fixed denominator
TBH, though, I started by visualizing where those binomial coefficients would be on Pascals triangle
And remembered the connection to hockey-stick from there
17:30
@Semiclassical Wait
$\binom{r+9}9$
$$\binom{n+k}k=\frac{(n+k)..1}{k..1}\frac{((n+k+1)-k)}{(n+1)}=\frac1{n+1}\left[ \frac{(n+k+1)..1}{k..1} - \frac{(n+k)..1}{(k-1)..1}\right]$$
something like this
With that in mind, I searched again and found this:
4
A: Telescoping series of form $\sum (n+1)\cdot...\cdot(n+k)$

robjohnHint: $$ \sum_{n=k}^m\binom{n}{k}=\binom{m+1}{k+1} $$ A generalization is discussed in this answer. The equation above is equation $(1)$ with $m=0$. Telescoping sum To turn the sum in the question into a "telescoping sum", we can use the recurrence for Pascal's Triangle: $$ \binom{n+1}{k+1}=\...

C major (actually I should have used D major, but renumbering this under D major is a headache thus will do that next time...)
$$4\sharp_0^14\sharp_0^14\sharp_0^11_0\sharp^{\frac{3}{2}}6_0^{\frac{1}{2}}4\sharp_0^{\frac{3}{2}}1_0\sharp^{\frac{3}{2}}6_0^{\frac{1}{2}}4\sharp_0^{2}\emptyset^11_1^11_1^11_1^11_1\sharp^{\frac{3}{2}}1_1^{\frac{1}{2}}3_0^{\frac{3}{2}}1_0^{\frac{3}{2}}6_0^{\frac{1}{2}}4\sharp_0^{2}$$
See if you recognise it
Which appears to be the desired proof of H-S by telescoping @RE60K
what am I going to do now
17:33
@Secret star wars imperial march?
bingo
@Semiclassical teach me electrostatics man
What do you want to know?
Said in this tone of voice: youtu.be/7udsYPVhl6Y
@LeakyNun actually, how are you able to read so fast?
@Secret I just sound each note in my head, and after the first six notes I pretty much figured it out
oh, and I ignored the other numbers, just the notes themselves
17:36
I see
(Mostly for the end of that bit, heh)
@Secret The second half looks off but I might be wrong
@Semiclassical I probably don't have a specific question lol. I am reading capacitors now.
$\emptyset^{273}$ @Secret
my life sucks
17:51
Recognize this? @Secret $\emptyset^15_0^15_0^15_0^1\mid 3_0^4\mid\emptyset^1 4_0^14_0^14_0^1\mid2_0^4$
also C major?
Anything minor
@AkivaWeinberger should it be $3\flat$?
I initially get the wrong key (I started with A minor hence 1 is A), but the pattern of the melody allow me to recognise it
[Random]
@LeakyNun I meant for it to be in a minor key, so that it's already a minor third
but otherwise, sure
17:56
${\Large\emptyset^{\omega}}$
@Secret Do… do you have perfect pitch?
(Also, I probably should have made each note like twice as fast)
I think not, it took me some years before I can get the pitches right from audio to text form of anything, I think it's just practice makes perfect for me
Ah, upon listening, I got the rhythm completely wrong, didn't I
@AkivaWeinberger how does your notation work?
What is this game
17:59
@AkivaWeinberger you are just 2 times slower than the original, I think
@AkivaWeinberger because any notation I know would use 6712345#6 for minor
lmfao
(Ooh, harmonic minor!)
...and is it in minor?
what's this notation called?
18:00
The numbered musical notation (simplified Chinese: 简谱; traditional Chinese: 簡譜; pinyin: jiǎnpǔ; literally: "simplified notation"), is a musical notation system widely used in music publications in China. Not to be confused with the integer notation. It dates back to the system designed by Pierre Galin, known as Galin-Paris-Chevé system. It is comparable to the Gongche notation from the Tang Dynasty. It is also known as Ziffersystem, meaning "number system" or "cipher system" in German. It should be noticed that some other unrelated musical notation systems are also called cipher notations. The...
@LeakyNun Just specify a scale and then use the numbers for that scale. So if I specify minor, then $12345678$ is (for example in the key of $A$ minor) $ABCDEFGA$
If I specify major, then $12345678$ is (for example in the key of $A$ major) $ABC\sharp DEF\sharp G\sharp A$
(I think?)
(Yeah)
I would seriously use 6712345#6 for minor
I would find that confusing, to be honest
Read my link
$123\flat456\flat7\flat8$ would be better, perhaps
18:01
I actually prefer the base to be letters, that way it is much clearer what key is
> The notation uses a movable Do (1) system. The key signature defines the pitch of "1". So 1=C means "C major". Minor keys are based on the natural minor or the Aeolian mode, and the key signature defines the pitch of "6" of the minor key's relative major. So 6=A means "A minor", the tonic of which is written as 6. Naturally, the Dorian mode of D should be marked as 2=D and based on 2. Some people prefer to write "Key: C" or "Key: Cm" instead.
@AkivaWeinberger actually, in sol-fa, you still use la as the first note of the minor
Oh, that's an interesting link
I didn't know that existed
Rehi chat
Thanks for sharing
I was just having subscripts say which octave and superscripts say how many beats
18:03
@AkivaWeinberger well it's a Chinese thing so
reeeely?
@Secret But I don't know what key most things are in
I don't have perfect pitch
and it's too much hassle to open up the piano app on my phone :P
(And I'm nowhere near my actual physical piano at the moment)
$1\sharp~2\flat ~1\sharp~2\flat{{}:}\|^\infty$
@AkivaWeinberger what?
There we go
Right now I'm learning Erik Satie's Gymnopedies No. 1
very satisfying piece to play
18:07
@LeakyNun It's the most pointless trill
@AkivaWeinberger I wouldn't say that it's a trill
It's the most pointless… thing
Ever time I sing an A, there's a 25% chance it's actually a C triple flat
Hm. I just realized:
In a sense, $\aleph_0$, $\Bbb N$, and $\omega$ are "enharmonic."
I cannot sing perfect pitch, but music played under slightly different keys will feel off to me
They're the same set but spelled differently.
18:10
D major: $3 - - - | - - - - | - \underline{6 4} \underline{2 1} \underline{7 1}| 7 - \underline{6 5} -$
What are the dashes, again?
extension from the previous note
so the first note is 9 beats long
and $|$ are the barlines
I don't think I recognize that tune
Wait
I misunderstood the underlines
Those make them shorter?
18:12
D major: $3_1 - - - | - - - - | - \underline{6_1 4_1} \underline{2_1 1_1} \underline{7_0 1_1}| 7_0 - \underline{6_0 5_0} -$
@AkivaWeinberger yes
I don't recognize it, no
This is not a math question. This is just an announcement. For the past year, I have been considering myself the most mathematically and logical rigorous human alive. I consider myself more rigorous than even Fields Medalists like Timothy Gowers and Terrence Tao. I feel like Bill Gates all the time. In fact, I don't think even Bill Gates feel this happy and on top of the world all the time. But I do.
@AkivaWeinberger Air on the G String
Oh, never heard it
Ah, Bach?
@user107952 and then?
@AkivaWeinberger yes
18:15
@LeakyNum I want to tell this annoucement as many human beings as I can in my life. I want to tell everyone how happy and confident I feel.
@user107952 Nice to know
Timothy Gowers is foolish compared to me.
32
Q: Does it really make difference to play a song in a different key?

Saeed NeamatiI hear sometimes players and composers say that this song won't sound good in F Major for example, and you should play it or write it in G Major (this was just an example). In other words, it seems that they assign aesthetic attributes to keys. My question is that, imagine a baby growing up in ...

So no, a key sound weird does not imply perfect pitch
@LeakyNun If you're doing something in minor, where do you mark the octave changes?
Like, is it $6_07_01_12_13_1$, etc.?
18:20
OK
6=? $~6-6'-\mid 4-6'-\mid 5-5'-\mid5\sharp-3'2'$
(prime mark = next octave)
Not an actual song, I just think it sounds cool
I see
Even Timothy Gowers and Terry Tao should consider it an honor to shake hands with me.
Do I have to listen to you, or do I also have to agree with you
Prove using set theory that the following is true:
$$\int_0^{\infty} e^{-x^2}dx=\frac{\sqrt{\pi}}{2}$$
(anyone else (you know who you are), continue on the musics)
@Akiva Weinberger, I just want to know what you think of my claims. And yes, even you should consider it an honor to shake hands with me.
18:28
typo: Forgot the [random] before the word "Prove"
I think, no matter how good I get, I would never feel comfortable saying the things you just said.
And I'm suspicious of anyone who is.
@Secret Using… set theory??
@AkivaWeinberger don't worry about it, that one is totally random. However, I suspect such a proof will be very long
Oh, like, from basic principles ZFC?
I'mma pass, then.
No one likes those
Jun 15 at 11:23, by Leaky Nun
To me, "ZFC is a basis for most mathematics" seems like "Quantum physics is a basis for the design internal combustion engines" - yes, you could build up from quantum physics to derive how an internal combustion engine works, but usually you don't bother. — immibis Jul 1 '16 at 13:36
18:32
Hint: Unlike most [random] this one is actually triggered by a ★. I will let you guys figure out what it is
hence that footnote: anyone else (you know who you are), continue on the musics
Given the fact that I am the most rigorous human, it logically follows that I am more rigorous than even the mathematician who proved the abc conjecture. So, I should be able to rigorously verify the correctness of the abc proof. I might need to learn some definitions first, but once I do, it should be easy. I would be doing the mathematical community a huge favor.
@Secret yea sure: not a ★, but seven ★s
@LeakyNun nope, it's not me.
I post [random] regardless of stars
@Secret what?
@user107952 you may find the following article a good read:
In the field of psychology, the Dunning–Kruger effect is a cognitive bias, wherein persons of low ability suffer from illusory superiority when they mistakenly assess their cognitive ability as greater than it is. The cognitive bias of illusory superiority derives from the metacognitive inability of low-ability persons to recognize their own ineptitude. Without the self-awareness of metacognition, low-ability people cannot objectively evaluate their actual competence or incompetence. As described by David Dunning and Justin Kruger, the cognitive bias of illusory superiority results from an internal...
@LeakyNun well, assume I get you right, currently the only item in the visible starboard that has 7 stars is my random bunch of symbols, which is why I think you might be referring to me
18:37
@Secret yes
but I can clarify that it is not me, why would I post a troll sounding [random] (that set theory integral) given that I don't really care about how many stars I get?
and because most of you knew me well, you know that question is not directed at you
@user107952 Ok. I have an actual question for you that logic might be used. Prove or show counterexample, that there exists no model theoric object that will allow division by zero to be nontrivial. NB I am not sure how to proceed that proof
@user107952 "lol"
@user107952 we knew that that is impossible for rings because of the 0x=0 axiom, but it seems for more general structures the question remains open. Given that you said you are rigorous and careful, perhaps you might be able to help me to find a proof or counterexample that I otherwise don't know
@Secret, I am a rigorous proof verifier, not a proof maker. I ask very clever questions, as my math stack exchange questions reveal, but I am bad at doing proofs. Although, if P=Np is true, a rigorous proof verifier can be converted to a proof maker.
ok noted
18:46
It's easy, just check every possible setting
@user107952 Sorta like how I feel about chess. If someone gives me a chess problem, I feel like I can more or less understand the thinking there.
With this iterative formula:
$$x=2 \pi \exp \left(W\left(-\frac{-c n+\frac{\vartheta (x)}{\pi }+\frac{x \log \left(\frac{2 \pi e}{x}\right)}{2 \pi }+2}{e}\right)+1\right)$$
we can find these points:
Since I am the most rigorous, I consider it my life mission to teach people rigor. I will tell you all a secret very, very few humans know. The argument "I am the most rigorous human. H is a human. Therefore, I am more rigorous than H." is invalid. You need the additional premise, "H is not me." Consider yourself all honored to learn this secret from the most rigorous human.
Any thoughts on IUT (Inter Universal Teichmüller Theory) of Shinichi Mochizuki? Even with my academical experiences, this is unlike anything I've seen before. Truly marvellous.
of the Riemann zeta function.
18:51
But that's tactics. By contrast I have much less sense for strategy, of seeing the big picture and how everything should develop.
$c=\frac{1}{4}$
@GregorPerčič my thought is: It's hard enough to appreciate math where there's only a handful of people who know enough to make progess. It's another level of difficulty entirely when there's only a handful of people can evaluate that progress.
My thought is that I can't distinguish a random paragraph from his IUT papers with a random paragraph from a mathgen paper.
So I guess I prefer to leave such matters alone in favor of stuff I can actually do meaningful work on. (Not that IUT is anywhere near my subjects of interest to begin with.)
So now, I have made you all more rigorous.
18:57
@Semiclassical True. Still, I know enough to recognize a great work. It still haunts me: we, with our ordinary brains even after years of labor can't catch a brink of genius that simply manifests and leaves us with the uneasy feeling of smallness.
Eh, it's a glimpse into an alien viewpoint about mathematical reality
Whether that viewpoint is inspired or delusive is beyond my capacity to evaluate
@user107952 Gödel's two incompleteness theorems have your rigor beat. They are the equivalence of mathematics committing philosophical suicide (AKA there are limitations to what we can prove with rigor).

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