(That’s okay. In the Klüfers group, I was writing up the report of my research project, came back a few weeks later and the PhD student supervising me said ‘yeah, by the way, you doubled your crystal structure yields. You left a flask in the fridge which happened to crystallise by accident.’)
@orthocresol Yes, the crystals were so large, the Elschenbroich group sent them in for neutron diffraction.
@Jan Heh, just like that. Furthermore, the raw solution of my bisbenzene vanadium was almost black; so you couldn't see the crystals before filtration.
hmmm elschenbroich is actually not that expensive in English. I thought it would be like Holleman-Wiberg, but no. Maybe I will buy one. My prof is incredibly French and he tells everyone to use a combination of Didier Astruc and Yves Jean's books, though.
@Chemobot @Hipp: Please, no space between First author and the colon. We’re not french ;) Same for between DOI and colon. Also, a link would be cool ;) I would assume journal and citation to be more difficult, though. feature-request
If I have aqueous sulfuric acid solution as electrolyte and the anode electrode is made out of copper and the cathode electrode is made out of graphite, what are the two reactions at the respective electrodes and why?
Anode: $$\ce{Cu → Cu^{2+} + 2e-}$$
Cathode: $$\ce{2e- + 2H+ → H2(g)}$$
Total...
I have a question about the derivation of the formula for relation between Specific Conductance and Equivalent Conductance
i.e. Eq. Conductance = k.V
where, k= Specific Conductance ,V=Volume in ml
Given link explains the derivation http://www.adichemistry.com/physical...chemistry.html
(Check u...
We were dealing with the Third Law of Thermodynamics in class, and my teacher mentioned something that we found quite fascinating:
It is physically impossible to attain a temperature of zero kelvin (absolute zero).
When we pressed him for the rationale behind that, he asked us to take a l...
DOI http://dx.doi.org/10.1021/om00034a077 "Methyl transfer reactions to tetracarbonylferrate(2-): rate and mechanistic studies" First author: Ping Wang
o/ I very much think so... unless someone comes forward and presents good reasons, why chem.se should not participate :D
@MelanieShebel I don't think there is much to salvage there, the link points into Nirvana and the question itself, well..., errr..., I don't understand what it asks O.o
Despite the fact that oxygen is much more electronegative than carbon, the bond in $\ce{CO}$ presents a weak dipole moment.
This observation can easily be explained using the concept of "dative bond", that is, one bond is formed with two electrons from oxygen, producing a polarization $\ce{O\bond{->
This question was in my book. According to me CO should be polar as it should have a dipole moment.
But I found that the $\sigma$-electron drift from C to O is almost nullified by the $\pi$-electron drift from O to C. What is about the $\pi$-electron drift towards the Carbon atom?
In Google it...
Carbon monoxide (CO) is a colorless, odorless, and tasteless gas that is slightly less dense than air. It is toxic to hemoglobic animals (including humans) when encountered in concentrations above about 35 ppm, although it is also produced in normal animal metabolism in low quantities, and is thought to have some normal biological functions. In the atmosphere, it is spatially variable and short lived, having a role in the formation of ground-level ozone.
Carbon monoxide consists of one carbon atom and one oxygen atom, connected by a triple bond that consists of two covalent bonds as well as one...
@MartianCactus yes, in principle. Every system tries to be in it's lowest energy/ most stable configuration - sometimes the "rules" to accomplish that are not quite obvious and you might need a firm grasp of higher concepts
you'll learn more when you advance in your studies
just keep an open mind about it and don't take everything you learn for the ultimate truth
it gets really exciting when the easy models like Lewis structures, VSEPR, hybridisation, etc... completely break down and you have to dig deep into the real science
Wikipedia has defined the Inductive effect thus:
"In Chemistry and Physics, the inductive effect is an experimentally observable effect of the transmission of charge through a chain of atoms in a molecule, resulting in a permanent dipole in a bond."
Recently, I learned from a teacher that t...
I don't believe that it requires hydrogen to compare. Any atom or molecule which exhibits either +I or -I doesn't depend whether or not there is hydrogen atom around.
Wikipedia has defined the Inductive effect thus:
"In Chemistry and Physics, the inductive effect is an experimentally observable effect of the transmission of charge through a chain of atoms in a molecule, resulting in a permanent dipole in a bond."
Recently, I learned from a teacher that t...
in simple answer No. Inductive effect is not measured relative to hydrogen. You don't require hydrogen to check whether an atom or a molecule exhibits +I or -I
Well I know for a fact that cis alkenes are less stable than trans alkenes due to steric repulsions.
But what bugs me is the fact that why systems such as 2-Methylprop-1-ene (where I believe steric repulsions are greater than that in cis-But-2-ene) are stabler than its cis and trans counterparts...
@hBy2Py Brian, you are an active user of ORCA if I recall correctly. Did you ever install it yourself and do you have any recommendation for a nice little tutorial?
I've written a bunch of shell scripts to streamline my workflows; probably you should write your own, to suit whatever environment you set up.
ORCA works on queued clusters, but it can be tricky to get the environment set up properly -- I have no experience there, so if you're running in that enviro and need help, the forum is the best place to ask for help.
If you want parallel execution, you need to have OpenMPI installed. For v3.0.3, if you have a choice you should absolutely use v1.6.5. Other versions can work ok, but sometimes there are weird misbehaviors.
> But in theory, one and one carbon decides to leave behind it's friends bound by the diamond structure boundaries behind to seek their fortune in the hippie camp that is called liquid.
I have been trying to understand the colour change in litmus paper from a quantiative point of view. I have knowledge of the particle in a box model of quantum mechanics, and i would like to apply this to the conjugated system in the active indicator-component of litmus dye.
In other indicators I...
Hey Experts i am new to regex.I am really confused by studying this regex.I have found something which is very difficult to understand for me.The thing is the use of question mark and equal to symbol in regex.An eg :
"(?<=\d)(\s)(?=[\d-])"
I just need to know the use of ?= in this regex code....
@CowperKettle Off the top of my head, I think that's a lookahead. A match will only be found for a comma with a following digit, but the returned match won't include the digit, just the comma.
Beware, implementation of lookarounds in the various regex engines out there is highly variable -- I've had a lot of trouble getting it to work in some cases. mainly bash shell scripts.
@Hexacoordinate-C some people like watching YouTube videos, some like reading books. For me, books work much better :p If you find something that works for you, that's good!
I've heard good stuff about Susskind's lectures, but just never really liked watching online lectures, so never bothered.
Given $\ce{SO2}$, $\ce{SO4^{2-}}$, $\ce{SO3^{2-}}$
arrange them from the shortest bond length to the longest.
I actually did arrange them, but i am not sure
(my answer: $\ce{SO3^{2-}}$, $\ce{SO2}$, $\ce{SO4^{2-}}$)
In a poorly ventilated room, I'd certainly avoid using both at the same time. Ammonia is very volatile and will usually "find" the only slightly less volatile chlorine gas - or perhaps the bleach itself.
-Chemist.
PS: A poorly vented bathroom is in itself a bad idea. ;)
I'd like to see an experiment where the answerer's name and reputation weren't shown on the review page.
I feel that this is maybe a bad answer, but not NAA.
@orthocresol But if you want to analyse it by NMR, you probably want to dissolve it in CDCl3, so you’ll need the neutral form. The question doesn’t say it’s in that form in vivo ;)
Reminds me of all the variants of ‘Two people go into a bus, three people come out. What scientists say what.’
Mathematician: If one enters now, the bus will be empty. Biologist: There has to be a nest. Physicist: We have a significant error in our data collection.
A physicist, a biologist, and a mathematician are sitting on a bench across from a house. They watch as two people go into the house, and then a little later, three people walk out.
The physicist says, "The initial measurement was incorrect."
The biologist says, "They must have reproduced."
And the mathematician says, "If exactly one person enters that house, it will be empty."
I have on hand a high-precision wavefunction expressed in Slater orbitals. I need to express it as accurately as possible in a minimal Gaussian basis set.
For background: I am currently working with STO-6G, but it is not good enough to describe the cusp condition with the accuracy I need. How c...
In a country in which people only want boys…every family continues to have children until they have a boy. If they have a girl, they have another child. If they have a boy, they stop. What is the proportion of boys to girls in the country?
Hi all!
Google published recently questions that are asked to candidates on interviews. One of them caused very very hot debates in our company and we're unsure where the truth is. The question is:
In a country in which people only want
boys every family continues to have
children until ...
With every pregnancy, there is a 50 % chance that it’s a boy. Thus, this ratio will not change for very large number of pregnancies, i.e. an entire country. Whether or not couple A stops after two children while couple B stops after twenty-seven is irrelevant.
Proof: 5!/2 is the order of the group A5. It is known that A5 is a non-abelian simple group. Therefore A5 is not solvable. But the Feit-Thompson Theorem asserts that every finite group with odd cardinal is solvable, so 5!/2 must be an even number.
I registered my Stack Overflow account using the Stack Exchange OpenID provider. I later changed my e-mail, but I cannot change the e-mail address associated with my OpenID for some reason. Why is that, and how do I change it? I logged in to Stack Exchange and it lets me change my password, but n...