J4FNrPQ8?-3%@N1 4*J+1@N0?%2@N0=JJ=JZJ

Can anyone help me debug this sums of squares code?

@isaacg @Maltysen ^^^

@isaacg why doesn't this translation of the Julia answer by AlexA. not work for the multiplication answer?:

J}1Q;S{*.TJJ

mine should do exactly that, why doesn't it work?

@Sherlock9 so you need help finding the unexpected EOF?

@TanMath Not exactly. The code prints when it shouldn't

@Sherlock9 when I run the code, I get an EOF error

I'm running it in the online interpreter

@Sherlock9 i see...

@TanMath .T does matrix transpose. That means it needs a nested list. If the list isn't nested, it casts the list's int elements to unary range.

So .TS4 gives [[0, 0, 0, 0], [1, 1, 1], [2, 2], [3]].

@ThomasKwa ok.. so how would i do a transpose like in Julia

By the way, I hadn't used .T before. I figured it out by reading.

Well, Pyth doesn't do outer product when you multiply a column vector by a row vector.

So you wouldn't want to do transpose.

@ThomasKwa .W!%Q2=Q/Q2Q the shortest way to divide Q by 2 until there are no factors of 2 left?

@Sherlock9 I'm not even very good at Pyth.

@ThomasKwa Ah well. Thanks

Why is everyone asking me their Pyth questions all of a sudden?

Nah, I just can't find the others

They might be asleep or something

/Qi^2QQ could work

Divides Q by gcd(Q,2^Q)

@ThomasKwa what would i want to do?

No I found a stupid, stupif workaround

J4FNrPQ8 ?-3%@N1 4?-2@N1=J*J+1@NZ=JJ?%2@NZ=JJ=JZ;?QJ1

FREE AT LAST

@TanMath That's your job

@ThomasKwa so I want an outer product function?

@ThomasKwa How do you do an if without it breaking?

blarg

Oh wait

@Sherlock9 alienG again?!

@TanMath I am an actual new guy

This is still much too long at 45 bytes J4FNrPQ8K%@N1 4IqK3I%@NZ2=JZ))IqK1=*J+1K;?QJ1