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12:07 AM
@Cristopher Are you familiar with the fact that $|\sin(x)|\le|x|$?
 
@robjohn No, this is the first time I've read it. Would that be another way to prove the limit?
 
@Christopher One (easily corrected) error is that $\arcsin(\varepsilon)$ may simply not exist.
 
@Karl How can it be corrected?
 
@Cristopher If $\varepsilon\gt1$ use $\delta=\frac\pi2$
 
Anyway, using robjohn's idea makes for a less cumbersome proof.
 
12:19 AM
@robjohn Okay. Could you tell me how the proof would be if we use $|\sin(x)|\leq|x|$? I don't see it very well yet...
 
Is anyone here familiar with branching processes?
@Cristopher Choose $\delta = \epsilon$. Then $|\sin(x)| \leq |x| < \epsilon$.
 
@Clarinetist Really? Is it that simple? faceplam haha...
 
@Cristopher Analysis can be frustrating sometimes :)
 
Thanks, @Clarinetist. And yes, I know. I'm struggling with these proofs... :)
Thank you @robjohn :)
 
1:15 AM
@TedShifrin Hey Ted! I've found some stuff to answer that last problem, but I have to figure it out. Some guy explained a bit of it too me, but his answer involved the IFT. math.stackexchange.com/a/1354690/197705
 
1:33 AM
Hi @TedShifrin
 
Hi again, mr eyeglasses
@Stan: I think that's pretty much the proof I gave in the book. I didn't look carefully. Yes, it uses the Implicit F Thm.
 
@TedShifrin Did you find a new house already?
 
1:54 AM
I guesstimate that in 80 days, MSE will have 100000 unanswered questions
 
Renting in San Diego, yes, mr eyeglasses ...
I thought most of the stupid questions got answered, @mixedmath.
 
@TedShifrin unfortunately, most the of stupid questions that do get answered have answers that don't get upvoted
well, most isn't true. But very often
 
Stupid question answers usually get way more votes than the answers that take me an hour ...
 
@TedShifrin Someone from UCSD came to a logic conference at our school last week
 
@TedShifrin yes, I know that feeling
 
2:02 AM
@TedShifrin hows moving going?
 
@Stan: The movers come to pack and load Friday/Saturday. I'll be very glad to get through the next month. Getting cable/internet started at the new place is turning out to be a challenge, too ...
 
Cable is soooo expensive!
 
I have no association whatsoever with UCSD, @morphic.
Well, @Stan, living is expensive, too.
 
LOL true. But I thought you said you were renting, don't they have to have like cables and stuff already hooked up to the building?
How hard can it be after that?
 
In my experience those were only included in rent when I had roommates
 
2:07 AM
Well, getting my landlord to call them up to cancel his service is a prerequisite to their making new arrangements with me, @Stan ... :( He'll get around to it eventually.
 
Uggghhh
 
...
 
Anyhow, @Stan, yes, one needs the implicit function theorem ... and then it's some nice linear algebra about perps (or annihilators, if you know those).
 
Evening, chat.
 
Hi @Fargle
 
2:10 AM
Brb
 
heya @Fargle ... how you doin' ?
 
Alright. I'd like to have gone out tonight, but I guess I can try to be productive meanwhile. And you, @Ted?
 
Were you going out anywhere fun?
I'm happy to be unproductive ... down to the last days of organizing for the move.
 
Well, no. I was trying to make plans and they never coalesced. It'd be as simple as hanging out at a friend's house, though. Strange as it may seem (heh), I'm not much for parties.
And that's good to hear.
 
I didn't quite expect you to be a party animal :) That's not the average behavior of serious math students :)
 
2:16 AM
"Serious" is a strong word.
 
I consider you as such.
 
I'm flattered. :3
 
Even if you have abandoned differential geometry ... sob sob :D
 
I haven't abandoned it! I'm just...stalling?
 
I think I will take diff geo. in 2016
 
2:19 AM
I'll try to be around to see that, mr eyeglasses.
 
2:37 AM
why are there so many people in here while stats is empty?
 
Pure math is cool and stats isn't. ;)
(NOT REALLY!)
 
anyone have any idea how to approach this question?
 
stats rocks
 
@TedShifrin whats your favorite branch of math?
 
Stats is kind of like math
just more... dynamic
 
2:40 AM
Mathematical culinary
 
stats is like Math with uncertainty
 
You could sell it as a self-help tool if you called it "quantum math".
 
Quantum culinary
 
oooh, I like the sound of that. Henceforth statistics will be known as quantum math
schrodinger's math
 
@flakmonkey: There's a standard way of expressing the unit disc as a union of squares. (Draw the biggest square you can; now one on top, to the left, to the right, underneath; etc...) Figure out how much area you're gaining in each step. This formula should help you figure out how close the size of your dyadic squares need to be to the original size of the squares to get within $\varpesilon$ of the whole area with finitely many.
 
2:44 AM
@MikeMiller thank you!
Is the proof that there is a way of expressing the unit disc as a union of squares simple?
 
Actually, the above is too complicated. Just tile the whole plane with squares of a given dyadic area, and show that by decreasing the radius they take up more and more of the area of the unit disc. (Bound the area of the union of the squares that intersect the unit disc above; show that as the area of the squares decreases, this goes to zero.)
 
What does "dyadic square/area" mean
 
Dyadic rational is a rational of the form $a/2^n$, $a$ an integer.
 
the unit disc is the union of all the squares it contains
okay, you want finitely many dyadic ones with total area arbitrarily close
 
3:03 AM
@anon why is the unit disc the union of all the squares it contains?
 
because every point in the disk is inside a square that is inside the disc
 
3:16 AM
@anon: we want them to intersect only along the boundary
 
3:27 AM
a quick and I think easy question guys, how can you justify formally than $\lim_{x \to + \infty} 1^x=1$?
 
@Masacroso Pick $\epsilon > 0$; note that we may choose any $M \in \Bbb R$, and it will be the case that if $x > M$, $|1^x - 1| = 0 < \epsilon$, and we are done.
 
ty very much @Fargle
 
No problem.
 
 
2 hours later…
user147690
5:35 AM
A module is just a vector space over a ring, rather than a vector space over a field?
 
user147690
Meaning the scalars form a ring rather than a field, is what I mean to say, i.e. we may not have inverses for our scalars
 
yeah
however aside from the operations behaving how you'd want, very little carries over to a general $R$-module from linear algebra, in my experience
 
user147690
That seems a valid concern
 
e.g., considering $\mathbb{Z}/2\mathbb{Z}$ as a $\mathbb{Z}$-module, the set $\{1\}$ is linearly dependent because of the nontrivial linear combination $2 \cdot 1 = 0$
 
user147690
Oh jeez xD
 
5:40 AM
because of this, there's no well-defined notion of dimension or anything like it in the general case
 
user147690
Interesting
 
you can look up free modules for the next best thing though
I'd say more but I need to go to bed
 
user147690
That's fine, thanks for the example
 
user147690
I have just started the chapter in Artin
 
o/
 
5:49 AM
@AlexClark yes, that is correct. a modules is an abelian group with an R-action. a vector space is an abelian group with an F-action. this makes the notion of vector spaces a special case of modules.
 
@AlexClark you've been quiet.
 
as @SamuelYusim hinted, classifying modules is hard, unlike vector spaces.
 
user147690
@AlecTeal Non-math distracted me for a little over a week, and after that I have been working on the research project for tropical geometry
 
user147690
@BalarkaSen That (R/F)-action is scalar multiplication from the linear algebra perspective?
 
Right.
 
5:53 AM
Well I've noticed no changes since your exams, nor replies (Worm diagrams Alex, WORM DIAGRAMS!)
 
user147690
 
This was an odd time to come back to chat.
 
user147690
Ahahaha
 
user147690
My diagram above was a joke admittedly
 
user147690
@AlecTeal How do I read this worm diagram?
 
5:57 AM
Top down
It should be pretty obvious
 
user147690
It isn't
 
Link it
 
user147690
 
user147690
I looked up worm diagram, but my picture above shows my dilemma
 
Okay, well each coloured bar is the state of a book.
Red indicates read lots, and blue not read. Grey skimmed, as usual.
 
user147690
6:00 AM
Wait so, each bar going down vertically is at a different time?
 
user147690
I.e. each time you update it?
 
Yeah.
 
user147690
Okay that was the integral piece of information (that I was missing) lol
 
user147690
That's really awesome
 
Yeah, I can see how knowing about kisogo.com, the domain of that image and stuff would make it a hard concept to grasp :P
To see your "diagrams" login and they'll appear on book pages. to make them public go to a volume, then volume control, then add public link
 
user147690
6:02 AM
I kind of wish you always had this feature :P
 
I told you before, the data was there. I wrote it during exam season it was only really meant to store and display
Anyway, the data is live. Despite the ".png" access rule. (That's just mod-rewrite)
 
@AlecTeal I feel like this could be used in psych research
 
I feel like I'm the only one using it.
 
I dont know. But graphs and how you represent data matter. And this is a nifty way to spot patterns
 
I also wrote a mediawiki plugin that can display like your most recently read 5 things and such (also live)
 
user147690
6:05 AM
@AlecTeal Well it doesn't help that I fell behind and I have so much to update into it
 
I'm working on auto-linking sources (opt in of course)
 
@AlexClark I like Atiyah-MacDonald's list of examples of A-modules : 1) A = k; k-vector space 2) A = Z; abelian group (any abelian group is a Z-module by defining the Z-action as $n \cdot x = x + \cdots + x$ (n times). any Z-module is an abelian group by forgetting about the Z-action structure). 3) A = k[x]; an A-module with a linear transformation (the linear transformation M --> M is obtained from restricting the action A x M --> M to (x, -), i.e., the x-action)
4) A = k[G]; k-representations of G (an A-action on M inducesa hom A --> End(M). this gives you a hom G --> End(M))
 
No but what little data there is is still graphable Alex
 
the side-notes inside the parenthesis are there for an explanation, btw.
 
user147690
6:08 AM
@BalarkaSen Thanks for the list, I will go get that book now aswell
 
No, don't.
 
user147690
Don't?
 
user147690
I remember someone recommending it for algebraic geometry anyway?
 
Oh @AlexClark I also added inline theorem boxes (see maths.kisogo.com/index.php?title=Subspace_topology for example)
 
It's not meant for beginners. It talks very little, for one.
Learn about modules thoroughly from somewhere else first.
 
user147690
6:09 AM
@AlecTeal It would be nice if I could edit the read fields in the volume information page(kisogo.com/book/volume.php?VolumeId=64)
 
user147690
@BalarkaSen Alright, modules->commutative algebra->algebraic geometry?
 
e.g., I have added the explanations in the parenthesis. A-M just gives a list of things, and lets you figure out if it's right or not. He does that to almost everything :P
@AlexClark sure, if you want. that'd take some fair amount of time, though!
what kind of algebraic geometry d'you want to learn?
 
user147690
@BalarkaSen Well I wanted to learn toric varieties - but that led me to find many algebraic geometry words and concepts I don't know
 
@AlexClark I can't see that page
 
user147690
@AlecTeal I just mean on the volumeID pages
 
6:11 AM
There is a button to make adding them a bit faster. There's an entirely re-written version almost done (that'll require no DB changes!) and is MUCH much nicer.
 
user147690
When will you release that?
 
It also supports exam papers and stuff, and there's an API (that goes both ways) so for example, I can link maths.kisogo.com solution pages right to the volumes
Hopefully on Friday
 
@AlexClark I don't know what it is either. Seems like you have to hunt through Grothendieck-type algebraic geometry.
 
user147690
I will hold off on updating until then, since I have 20 textbooks with pages scattered all over them
 
It'll then run live at beta.kisogo.com (same DB) then be switched over on Monday is all goes well.
 
user147690
6:13 AM
@BalarkaSen Well question: What is a non-topological torus?
 
I don't know.
 
user147690
Well that's what toric varieties are based upon it seems
 
Where did you find that terminology?
 
@AlexClark you should do that now. The beta will be in "read only" mode until the transition.
 
user147690
One sec
 
6:14 AM
Right, I just google, and it turned up algebraic torus.
The definition seems involved. You have to learn much more than classic algebraic geometry to grok that, it seems.
 
@AlexClark use it by Friday. I shall not ask again
 
user147690
@AlecTeal That's a little full on
 
user147690
I have to go now, need to pack up(at uni atm)
 
@AlexClark I'm fed up now, so that really was an ultimatum
 
user147690
I don't like ultimatums
 
6:19 AM
Oh noes
@AlexClark you're also... not using mathjax? Seriously? codecogs.com/latex/usage.php
 
@AlecTeal What kind of wiki is that. Is there some general information about that website?
3
Is it your personal wiki?
 
6:44 AM
@MartinSleziak I own/host/wrote-most of it but it isn't "mine" personally. It will however be ad-free forever and stuff, I can guarantee you that.
 
7:03 AM
Night then. Before I go @MartinSleziak I wont e annoying and link pages you'll never read but there's a lot of good stuff there. I actually use it A LOT. It's really handy to link in answers as it has the definitions (always, at the top, first thing) but then see also and immediate properties and such.
Anyway, night
 
Later pal.
 
@BalarkaSen hi
 
hello
 
what is the attaching word of the 2-cell in this space?
(1 sec)
i.e. take $D^2$, remove two open disks and identify all boundary circles
 
recall that this space is a punctured torus with a cylinder attached to the bd of the puncture and one of the longitudes.
so instead, you can give it a two 2-cell CW structure, which is seemingly simpler than doing it with one 1-cell.
the words are simpler in this case too. try this one out!
 
7:14 AM
ok
so there's no way to immediatly see the attaching word otherwise?
 
i don't know. the one 2-cell structure freaks me out a bit.
 
me too
 
Thanks for the reply, Alec Teal!
 
@BalarkaSen im looking for the most algorithmic solution in case i don't immediately recognise the homotopy type in the exam
but i think this particular problem would be too hard for my exam anyway
we didnt do much cellular homology
 
there is no algorithmic way for finding cell complex structure of a given space.
use cellular only if your space has an easy cell structure.
 
7:23 AM
ok
 
in this case, you're given an identification space. the best you could do is to try doing the identifications by hand and see where it leads you
mayer-vietoris is easiest in this case, as we've discussed previously
 
fair enough
a couple days ago i asked you about finding all 2-sheeted coverings of $S^1\vee S^1$
 
i have pinged you about that one in the alg top chat
 
7:49 AM
user image
3
An animation of my own making!
Square grid, all movement is strictly along x or y axis, apparent curving is because of hyperbolic geometry.
 
 
2 hours later…
9:41 AM
@El'endiaStarman nice work :-)
 
 
2 hours later…
12:09 PM
hey chat
 
12:23 PM
aw, shucks, chat is ded
 
hye guys anyone knows about n-parasitic numbers and how to find it in bases other than 10? its got me overthinking about it
 
@SohamChowdhury long live chat!
 
continuing from above, I thought of applying same logic as base10 here:

$$2 * num_{base} = lastdigit * base^{digitlen - 1} + firstnum$$
ref post here: https://math.stackexchange.com/questions/1361368/n-parasitic-number-in-a-base-different-than-10
but that doesn't work
 
@SohamChowdhury viva las chat!
 
user147690
@AlecTeal Yeah, using a plugin since the other plugin needed me to download a bunch of files and I just wanted to get it done
 
user147690
12:37 PM
@AlecTeal I see you are using simplemathjax, and I am just using simplemath - what are the advantages?
 
user147690
@BalarkaSen What more than algebraic geometry?
 
user147690
Fairly sure it was this that I found it @Balarka gen.lib.rus.ec/…
 
user147690
I found it to read more about polyhedral fans/cones
 
12:56 PM
@AlexClark I said much more than classic algebraic geometry.
Schemes aren't classical algebraic geometry.
 
user147690
1:43 PM
@BalarkaSen Apologies, that makes sense
 
no need to apologize.
 
user147690
Hey @SohamChowdhury
 
hey @Soham
 
hey. :)
was est up, @Alex?
 
user147690
nothing much xD. Least math today for ages though, since I went rock climbing
 
1:46 PM
I'm studying for a chemistry test. Although it's not what I would call real chemistry -- it's all sorts of numerical crap.
 
user147690
Ahhh that's not so fun
 
@AlexClark ah, cool. getting more and more ripped by the day? :P
 
Hello@SohamChowdhury@AlexC
 
user147690
Oh god haha, it didn't go too great, girl I was with did better than me xD
 
user147690
I am really strong, but I am really heavy now, so I can't endure
 
user147690
1:47 PM
Hey Sayan
 
rock climbing is useless. everything excluding math is useless.
3
 
user147690
hahaha
 
user147690
It was fun :P
 
True!!
 
user147690
Also not entirely sure if you were joking
 
1:48 PM
another star-farming comment from the great B
3
 
user147690
HAHA
 
Haha
 
I have gone rock climbing exactly once. I'm pretty sure that I'll say exactly the same thing if you ask me about it twenty years later. :P
 
user147690
Wait was he joking or not
 
that is better left ambiguous.
3
this is getting silly.
 
user147690
1:49 PM
I didn't star that one for what it's worth
 
Balarka should do research in numerical methods of farming.
 
user147690
lmao
 
The star panel is in tatters!! :p
 
he seems good at it
 
user147690
How much alg geometry have you done @BalarkaSen?
 
1:50 PM
eek.
that's a Bengali cussword, @Alex
 
none so far.
 
user147690
Oh really? How long have you been working on comm alg?
 
user147690
Alg? @SohamChowdhury
 
Star-farming? I haven't come across this term before.
 
@AlexClark tried doing it a long time ago, but done alg top instead.
 
1:51 PM
@AlexClark no, your other contraction. nevermind, I just thought B might be sensitive or something.
 
user147690
Ohhh
 
you're having fun, @Alex?
with comm alg?
 
user147690
Oh I haven't started really
 
i have started doing A-M again recently.
 
ah, good luck.
molarity calls
 
user147690
1:52 PM
Alright yes, I will be back in 40 or not until tomorrow aswell
 
user147690
cya later @Rememberme @SohamChowdhury @BalarkaSen
 
@SohamChowdhury done normality?
Cya
 
bye
 
later pal
 
@BalarkaSen what's A-M?
 
1:54 PM
a book on commutative algebra. contraction of atiyah-macdonald.
 
Ohh...
@BalarkaSen does there exist any other space except a point ,line ,plane to which there always exists a quotient map from any given structure ?
 
I don't know. I don't think about the quotient map like Munkres does. I think of it as the natural map $X \to X/G$.
 
Hmm...
 
Did you think about normal subgroups anymore afterwards?
 
Yes ... I did and I was trying to find an example of a normal subgroup...
Any abelian subgroup of a group does the job right?
 
2:00 PM
Exactly.
For a nonabelian example, $D_{2n}$ and the subgroup of all rotations.
 
Yes...
 
@Rememberme Careful! Did you mean any subgroup of an abelian group?
"any abelian subgroup of a group is normal" is false.
Example : $D_{2n}$ and the group of all reflections (isomorphic to $\Bbb Z/2$, which is abelian)
 
I meant an abelian subgroup.. A subgroup which is abelian .. Not the group
 
then what you said is false
 
@BalarkaSen
Why?
 
2:10 PM
i just gave you an example above
 
Okay so every subgroup won't be most of 'em will be...
 
no, that too is false
why should it be true?
you have a group $G$ and a subgroup $H$ and an action $g \cdot h = ghg^{-1}$. you want to prove that this is well defined, that is, for every $h \in H$ and $g \in G$, $ghg^{-1}$ is in $H$. what you want is to have the total group $G$ to be abelian, as then $gh = hg$, implying $ghg^{-1} = h \in H$ by left-cancellation.
 
Hmm... I have to go it seems .. I will surely come back to you next when I come back online @BalarkaSen
 
ok, I have to go too.
 
Later guys
 
2:19 PM
later
pals
:-)
 
2:40 PM
@AlexClark mathjax looks A LOT better. Because it's vector graphics instead. Also all you do is put something in the extensions folder, it's not a lot of work.
 
user147690
@AlecTeal What's something in this case? It seemed I needed to download a few things, but it might have been a different extension. Is is still <math></math> based?
 
@AlexClark you can also get plugins for mathjax, like say: maths.kisogo.com/index.php?title=Xypic xypic here. Which is great!
@AlexClark that's just the tag, That's arbitrary, as you know I use <m> and <mm> for inline/display math respectively. I left <math> only because stuff already uses it.
maths.kisogo.com/… check out that diagram, isn't that sweet.
 
user147690
"Alec's 'super' diagram"
 
user147690
It is indeed sweet xD
 
@AlexClark if you zoom in on your one, you'll see the maths gets all fuzzy and not smooth, zoom in on mathjax and you'll find it gets sharper and sharper.
 
user147690
2:43 PM
Yeah just saw that, although I don't know if anyone will be zooming in
 
It makes a big difference on screens made in the last 3 years.
It's VERY noticeable on both my laptops and extremely so on my tablet
 
user147690
Both of mine were in the last 3 years haha
 
And you can't tell?
 
user147690
I can if I zoom for sure
 
user147690
Anyway I must sleep now, talk later
 
2:45 PM
Bye Alex C.
 
.... are your laptops 800x600 or something?
WHAT YEAR IS IT?!
 
CRT monitor
 
3:14 PM
Hello!!
 
Hi!!
 
3:32 PM
Hi @MaryStar and @skullpatrol
 
Hi pal
 
I am ಠ_ಠ
2
 
Hi, everybody. Can someone check my final results here: http://math.stackexchange.com/questions/1362135/2-exercises-finding-the-limit-and-showing-continuity-and-differentiability#

Cause people commented but nobody gave me final answer is it correct. I'll be thankful.
2 not hard exercises, with a little work to do, but I wrote the whole calculations, so it shouldnt be hard
 
4:17 PM
Hello eyes @morphic
 
morning chat
 
http://math.stackexchange.com/questions/1362280/pl4201-power-line-overheating-in-laptop

Can we all just vote to close this already?
 
@Semiclassical hi!!
 
yeah, that's pretty bad. i've gone and voted to close as off-topic
 
"I actually checked there is a site for bicycle repair but none for laptop on Stack Exchange"
lol
 
4:27 PM
I'm just shaking my head in amazement. xD
 
Greetings
http://math.stackexchange.com/questions/1358792/number-of-unordered-factorizations-into-k-distinct-parts
Does anyone have an idea? Is the question clear? I thought it would get more than 18 view in 2 days
 
4:47 PM
The question is clear
but I don't have an idea :/
 
@iluso :-) refresh the page
 
Thank you @Hippalectryon
Very kind of you
 
@Hippalectryon Oh thanks!
Btw, this could provide a way to answer this (mine to)
http://math.stackexchange.com/questions/1315109/distributing-groups-of-objects-into-boxes
 
Well once someone put a 500 bounty on one of my questions :P I'm just redistributing that
I'll look at it, I gtg for dinner :-)
 
Later @Hippalectryon
 
5:15 PM
Ahh... I get it now @BalarkaSen
I found an example...
 
5:49 PM
@Fargle Can I ask you a question ? Its about topology
 
Sure. I may be out of my element, though.
 
No problem , I just want your views on it
does there exist any other space except a point ,line ,plane to which there always exists a quotient map from any given structure ?
 
Alrighty.
Hmm. I don't know. That's definitely a question I'm not equipped to answer, haha.
 
Hmm..
Thanks , anyways
 
Remember: what do you mean by "any given structure"?
 
5:53 PM
@Eric I mean any given space as in the unit sphere,$S^1\times S^1$,etc
 
I don't think this can be true, because a quotient map has to be surjective, and finite topologies exist
Maybe one of the two- or three- point topologies will work, but something is telling me no.
ermmm my brain went
completely off the rails a sec
 
I want a full fledged proof @Eric or else I won't be able to make my brain happy
 
What I mean is that of your three examples only "point" can be valid.
 
Yes I just found an example where the line doesn't work
Unit sphere@Eric
 
(please stop tagging me I'm right here :/)
 
5:57 PM
Okay sorry.
 
So if the theorem is "The point is the only topology $A$ for which there exists a quotient map $X\to A$ for all $T$", then the goal is "Given a topology $A$ with at least two points, construct a topology $X$ for which it is not a quotient."
For that we need some kind of quotient invariant ?
 
Can you explain me what you mean by a quotient invariant
 
I mean, like, homotopy is a homeomorphism invariant
Order of a group is an isomorphism invariant
 
okay..
 
etc. etc.
 

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