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2:00 AM
@AlexW: Look on pp. 182-183 of baby Rudin.
 
Hot damn, @Ted. It's right there indeed.
 
Papa Rudin looks super hard
Do grad students even read this
 
@TedShifrin Thx a lot. I have a more general question:

I noticed (I hope i'm not mistaken), that given $f:M \to N$ that is transverse to $S$. We can phrase this like so: $T_{f(p)} N / T_{f(p)} S = Im(T_p f)$
 
Looks like some good references. I never made it to Chapter 8 in PMA.
 
@TedShifrin Is there something deep behind this?
 
2:05 AM
Very good, @Saal. :)
It's the precisely the condition that you need in order to guarantee that $f^{-1}(S)$ will be a submanifold of $M$. You can deduce that from the regular value theorem.
 
@Ted So, how are class at UGA?
 
@TedShifrin I wouldn't ask you about measure theory, this is a VERY simple problem. Please do read it. It's more.... combinatorics really? (Just the Q, not my working)
 
How were finals scores?
@Ted
 
Finals? We're still 2/3 through the semester. 6 weeks to go.
 
Like the interval [0,5)-another interval is 2 intervals
 
2:07 AM
@TedShifrin Great. thx again
 
@Ted I meant last sem.
(oops...)
 
You're welcome, @Saal.
Oh, some were very good, some weren't. Always the story. You'd think I'd have learned to give easier finals, @Julian, but I can't sell out.
 
Thanks again for the reference, @Ted! Have a good night. :)
 
Oh, you,you person of integrity, you @Ted
 
@Ted haha. ok.
 
2:09 AM
See you soon, @AlexW :)
 
I really dont know what to talk about now...
 
LOL, @Julian. Sorry :P
@Alec: Have you done the $1$-dimensional case? Seems like understanding that would lead you to the answer. So I guess this is very different from the Borel- or sigma-algebra, because the finiteness claim is certainly false there.
 
I've done it in the 1, and I could do it for any fixed n @TedShifrin
For example 3 would have at most 28 sets
 
Wait, the $n$ in your finite union is supposed to be the $n$ in $\Bbb R^n$?
 
I'm not sure..... but it's not really a measure theory problem (as I'm sure you agree) it's a "cutting chunks out of things = chunks"
 
2:12 AM
I don't understand.
 
Did I use an n there? Mistake
 
If you can do it for any fixed $n$, why aren't you done? I'm confused.
 
I can't do it for general n.
 
Is there not an inductive argument, somehow?
 
Like if you say n=3. Then a rectangle - another rectangle = 28 disjoint rectangles (some may be empty)
 
2:13 AM
Well, there's some sort of recursion formula for that as you vary dimension, I'm sure.
 
I think I need to look at Cartesian products TBH, but I'm not sure how to handle something in $J^n\times J^1$
 
But are you trying to find the formula, or just prove it's finite?
 
Finite
 
Well, try to go from 1 to 2, or from 2 to 3 ... and look for an inductive argument.
Well, finiteness of the difference you just wrote down is not hard to prove, using an inductive scheme. I'm pretty sure.
 
I have been for a while now @TedShifrin that's why I finally posted.
 
2:15 AM
You need to proofread your post. It's full of sloppy errors. I pointed out one. You also have $\mathcal J^n = \mathcal J^n\times\mathcal J^1$.
 
Sorry about that - one sec
 
@Ted its not your fault. I just am so blank on what to talk about..
 
@Julian: Talking isn't obligatory :P Have you ever seen the following (one of my favorite elementary questions, to be done by induction): Is it true that whenever you pick $n+1$ numbers between $1$ and $2n$ (inclusive), then there is a pair $a,b$ with $a$ dividing $b$?
 
@TedShifrin I just realized what was the problem. It was a typo in my notebook.
let $f:M \to N$ be transverse to $S \in N$ and $W=f^{-1}(S)$.
What can be said about $T_p f (T_p(W))$? Is it just the tangent space of W?
 
That's a much better question, @Saal (btw, $S\subset N$).
 
2:19 AM
@TedShifrin yeah. another typo ^^
 
You mean the tangent space of $S$ at $f(p)$?
 
yeah
 
Again, it is only a subspace of that, in general. Can you make up an example?
 
@Ted is the induction thing for me?
 
Yes, @Julian.
 
2:21 AM
in that case, no
 
I'll try to think about it. i'm trying to prove a problem with "chain" transversality
 
@Saal: Notice that you certainly don't know that $T_pf(T_pW)\supset T_{f(p)}S$.
Yes, I know what problem you're trying to do.
No: you haven't seen? @Julian ... or no, it isn't true? :D
 
I have not seen?
 
@TedShifrin hey ted!
 
Oh, cool ... So there's a neat problem for you to work on, @Julian.
Hi @Stan
 
2:23 AM
I will think about it after I finish all my homework
:D
 
I learned tensor products! I'm so proud of myself :p
 
LOL ...
 
I like interseting problems
 
Well, @Julian, you probably wouldn't like math if you didn't.
 
And now I can define a wedge product in terms of them, but I still don't really understand the wedge yet. But a step forwards!
 
2:24 AM
Very good, @Stan.
That's why I teach wedge just in terms of determinants.
You get the algebra of alternating $k$-linear maps generated by the signed volumes of projections onto all $k$-coordinate planes.
 
@Ted Haha. True, true
 
Oh, wait before we go into this, let me test myself. So if I have a 3-tensor on 3 dimensional space, then it has $3^3$ components right, so 27 right?
Did I get that right?
 
Yup, @Stan.
Too many $3$'s, though. Make some number different.
 
lol true, that came up though because the first video I watched the guy used 3
in 3 space
so I wanted to sort of come full circle
anyway
um, btw
Do you know a good complex analysis book?
 
Do you know uniform convergence thoroughly?
 
2:30 AM
Definitely not. Is that in a standard analysis course? I have a chance to take a 3 quarter sequence on it next fall and it sounds like a good idea.
So far I have on my list, analysis course and a course on curves and surfaces.
I'd also like to take an abstract algebra sequence
And I need a good knowledge of Lie groups
 
I'm taking intro real analysis, intro algebra, and intro topology
 
To do complex variables thoroughly requires uniform convergence and a good background in complex analysis. You might enjoy browsing at Gamelin's book on Complex Analysis. I rather like it. I was going to teach our graduate course out of it (and add harder exercises), but then I got sick with cancer and didn't teach the course.
Slow down, @Stan.
You need basics on manifolds plus matrix algebra plus more algebra to conquer Lie groups. Save stuff for grad school.
OK, I'm outta here for tonight.
 
mr eyeglasses, my advice to my advisees would be to do real analysis and then do point-set topology, not to do them concurrently.
 
Hi @AlexW, @Ted.
 
2:34 AM
Good night, @Mike.
You done grading finals already?
BTW, Juan says hi, @Mike.
 
Finished, yeah. Going to play some games until the rest of my friends finish... then a drink.
Hi to Juan too.
 
Did your students do ok?
 
Here is My problem problem. $f:Y \to M$, $g:M \to N$ and $g$ is transverse $W \subset N$

$T_{f(p)} M = T_{f(p)} g^{-1}(W) + T_p f (T_p Y)$
$T_{gof(p)} N = T_{gof(p)} W + T_f(p) g (T_f(p) M)$
Then i get:
$T_{gof(p)} N / T_{gof(p)} W = T_{f(p)} g (T_{f(p)} M) = T_{f(p)} g(T_{f(p)} g^{-1}(W)) + T_p gof (T_p Y))$

But here i'm stuck....
@TedShifrin
 
Dunno. Saw lots of very bad Gramm-Schmidt.
 
What are you trying to prove, @Saal?
 
2:39 AM
That if $g$ is tansverse to $W$ and $f$ is transverse to $g^{-1}(W)$ then $gof$ is transverse to $W$
 
OK, good, that's what I expected. It's just linear algebra. Write down what you need to prove about just linear maps and subspaces, and try to remove all the notation with manifolds and $T_{\text{blah}}(\text{blah})$.
In fact it's an if and only if statement.
 
I thought it might be something like that that's why i asked about the quotients...
 
Your quotient statement was absolutely correct.
 
Anyway how do you know so much?
 
LOL ... I've taught differential topology approximately 12 times and graduate differential geometry approximately 6 times.
 
2:42 AM
lol
 
Ok that explains it..
 
Also written a textbook for it
 
No, not a textbook for this, mr eyeglasses :P
 
Well, when will you? :p
 
2:43 AM
I won't. I love Guillemin and Pollack ... it's just fine.
I just add more exercises to it.
And besides, I'm quitting math in 7 weeks.
 
You're quitting math?!?!
 
Formally
 
We'll see if i miss it, @Stan.
 
Ah, but you're such a stud. Everyone will miss you!
lol
 
If you join the math cult, you're never allowed to leave
 
2:45 AM
I brag to my family about you all the time because you're lectures are awesome. A shame to lose a good teacher. They are rare!
 
I'm going to enjoy being a bum ... and getting back to be a good bridge player :)
 
Bridge is fun
love me some bridge
 
Thanks for the complement, @Stan. I'm sure your family is quite bored. :)
We should play sometime, @Stan :)
 
I'd love to. I'll email you about it along with my 1 page write up on how a tensor product works :p
 
LOL, ok
 
2:46 AM
hahaha
and no my family is never bored
 
I need sleep. Tomorrow is one of the most complicated and crammed lectures in the diff geo class.
 
my father is a law professor and creating a MOOC
:p
 
ah, cool
 
What topic @Ted
 
just ask him not to sue me, @Stan
Codazzi and Gauss equations, mr eyeglasses, and showing that any flat surface with no planar points is a ruled surface.
 
2:47 AM
hahaha there ya go. as if he would have the reason, desire, or time. Sueing math teachers doesn't tend to yield profit
lol
 
Maybe proving Liebmann's Theorem, if I can go warp speed.
 
I only understood "Gauss"
 
No, we're poor, @Stan.
It's section 2.3 of my notes, mr eyeglasses.
 
Start out at warp 1-you can always switch to ion propulsion if the students canna handle the g's
 
Wow, almost 2/3 done with the semester already?
 
2:49 AM
I will ponder what to skimp on, @DavidW ... being buried in too many technical things isn't interesting for even the better students.
yes, mr eyeglasses. Our finals start at the end of April.
 
Oh right
 
OK, night.
 
Ours start in mid-May
Night @Ted
 
@TedShifrin Survey the summit, and you can tell how much ballast to jettison by how the climb is going.
 
@TedShifrin OK, finally. Last question before i go to sleep:
$(T_p f)^{-1} (T_{f(p)} S) = T_p f^{-1}(S)$
I'm pretty sure i proved it just now...
$f transverses S$
Is this generally true?
 
3:22 AM
Hi @ᴇʏᴇs.
 
@Committingtoachallenge Hi, I am going to take a nap in 30 min.
 
Naps are good
 
My OCD thoughts are so ridiculous that you won't even believe them if I told you sometimes.
 
If I didn't study at university most of the time, I would take a nap every day at midday
What is an example?
 
3:24 AM
I would rather not say now, maybe another time.
But it's just so bizarre, yet I can't get out of it.
So yesterday you went back and slept for a long time?
 
Unintentionally yes
I went for a 'one hour' rest and slept for 12 hours by mistake
But it was fine because all of my work was in on time.
 
When I quit working many years ago, I thought I would take only 1 year to get well.
But now it might take 10 years or more.
Very painful indeed.
But that's also because even after I quit many bad things continued to happen.
 
Were the symptoms the same where you quit?
 
They are much worse than before right now.
Basically, they go up and down.
 
Do you thinking quitting was a bad choice? Do you think your problems have worsened due to being out of the work force?
 
3:28 AM
What I need to do is to bring it to a level low enough and let it remain there.
@Committingtoachallenge No.
I said no after thinking about this for a very long time.
I asked myself the same question too.
 
You have made a little more than 1% of this chat pages messages
Do you think you can do productive things while you are still sick? Like learning to program?
 
I did learn a few things here and there during this period, but nothing too much.
I will do what I can do.
I am targeting to be completely well by the end of next year.
 
What stopped you from starting Mathematics this year?
 
Too disturbing thoughts. OCD/PTSD.
 
What does the average day look like in your life?
 
3:33 AM
Let me put it this way. When the the thoughts are not too bad, one can work and then improve your condition.
But when the thoughts are so bad, one cannot even work.
So very often during this long period, my thoughts are just so bad.
@Committingtoachallenge That has varied quite a bit over the years.
Right now, it is severe anxiety almost the entire day.
Some time ago, I spent much time answering questions on SE.
So there is a lot of variation.
 
What areas of Mathematics were you formally educated in?
 
I just take one day at a time and see how things go and then change my decisions accordingly.
@Committingtoachallenge My courses? Well, I can't recall them all, lol.
 
What major though?
 
Analysis, algebra, physics, applied, finance
 
3:37 AM
Algebra, analysis, geometry.
I know that people will look at my life and say I am doing it really wrong, otherwise I would have gotten well long ago. But they don't understand all the things that happened that made it turn out this way. I do my best, so I have no regrets.
 
So three majors really
 
I need to find a therapist who is really good and who has dealt with very bizarre things.
When I was in undergrad, I was already sick, which is why I did not do very well.
Rather than accept I will never be well this life and perform a poor job all the time, I must do my best to get well, however long it takes, whatever others say.
Of course, I have my own definition of well, which I think is reasonable.
 
@DavidW Are you experienced in Analysis as well as Algebra?
 
Some people will say you cannot be well but can only manage, that is because they have a different definition of well.
@Committingtoachallenge You should not capitalise them, lol.
 
You had a therapist in the past, what happened with that?
Are they not names?
They seem like names to me :P
 
3:41 AM
I only went for a couple of sessions. I did not learn anything new, so I stopped.
@Committingtoachallenge Names need not be capitalised. Apple is also a name. Banana is also a name.
 
@Mike Are you experienced in Analysis?
 
Only German nouns are always capitalised, lol.
 
das ist gut :P
 
On better days these few years I read up on various things, not math. Just for fun.
I did try to get back to work on some occasions with disastrous results.
It led to more OCD themes.
 
$a_n \to a\implies f(a_n) \to f(a)\implies (|f(a_n)| \geq \frac{|f(a)|}{3})$ for some $n\geq N$ right
 
3:45 AM
Is f continuous?
 
Yep $f:\Bbb R \to \Bbb R$ is cont
and $f(a)\ne 0$
 
Yes that is right.
 
So now I just need to prove both of those implications formally
 
Even if 0, still right.
 
3:48 AM
I am going to sleep, I hope my miracle comes soon.
 
Enjoy your nap Jasp
 
 
6 hours later…
9:35 AM
Hi, anyone here?
 
Hi @DanielFischer
 
Hi @TimDavids.
 
@DanielFischer I' m not sure how to add pictures, but I wanted to know if [](the following) is the correct plot for the function $y = x^{\frac{1}{3}}y^{frac{1}{3}}$
@DanielFischer It's not giving the correct link.
@DanielFischer Can I not add pictures to chat?
 
9:52 AM
@TimDavids I'm not sure what kind of images can be directly placed in chat. If you want to link something, [link text](http://path/to/thing) is the format.
 
@DanielFischer Well the graph I get for $y = x^{\frac{1}{3}}y^{frac{1}{3}}$ is the graph i get by typing "graph (x^(1)*y^(1))^(1/3)" into google.
 
@TimDavids Should that be $z = x^{\frac{1}{3}} y^{\frac{1}{3}}$?
 
@DanielFischer programmming languages like maple and calculators seem to have difficulty plotting graphs which have fractional exponents.
@DanielFischer Yes that's correct.
@DanielFischer It should be that but I am writing it in this form for because it gives strange results otherwise.
@DanielFischer Oh sorry I see the typo.
 
@ABeautifulMind I am here
 
Anyway, @TimDavids, the graph looks right.
 
9:58 AM
@DanielFischer Thanks.
@DanielFischer Much of the reason for the confusion with the previous discussion about cusps is that I was graphing $z = x^{\frac{2}{3}}$, but it was only showing the one branch for $x \geq 0$.
 
@TimDavids Try with $(x^2)^{1/3}$, that should give you a graph including negative values of $x$.
 
@DanielFischer Yeah I did that. The calculators take the cubed root first for some reason. Thanks.
 
I dont know whether this is the correct place for a trivial question so excuse me if its not . The question is : Does the reputation from main site get copied to the meta site ? Since I see 90 on main site and 78 on the meta . Thank you.
 
@Klosew Yes, your "meta rep" is your main rep, but it's updated only every hour or so, hence meta often lags behind.
 
@TimDavids A lot of programs will only parse $a^b$ for $a > 0$
 
10:04 AM
Alright . Thank you. @DanielFischer
 
Oh okay.
 
10:43 AM
Is $a_n \to a \implies f(a_n) \to f(a)$ always true when $f$ is continuous?
$f:\Bbb R \to \Bbb R$
 
10:57 AM
Well what do you mean by $a_n \to a$? @Committingtoachallenge
 
If $f$ is continuous, then $\lim_{x \to a} f(x) = f(a)$.
 
How many hours do you sleep a night @DavidW if you don't mind me asking
 
Suppose $\{a_n\}$ converges. This means that for any $\epsilon > 0$ we like, there is some integer $N$ so that for all $n > N$, we have $|a_n - a| < \epsilon$.
 
@DavidWheeler Yep
 
11:04 AM
Now suppose we pick a 2nd $\epsilon' > 0$
Since $f$ is continuous, we can pick some $\delta > 0$ so that $|x - a| < \delta \implies |f(x) - f(a)| < \epsilon'$
yes
Now pick $N$ such that $n >N \implies |a_n - a| < \delta$
 
So that first epsilon becasme delta?
And $a_n$ became $x$?
 
Sure, our "delta" is a positive real number, ya?
 
Yep I just meant notation wise
And $\epsilon = \epsilon(\delta)$?
 
By continuity, for each such $a_n$, we have $|f(a_n) - f(a)| < \epsilon$, so $f(a_n) \to f(a)$.
 
Our real analysis class uses $a_n \to a \implies f(a_n) \to f(a)$ as the definition of continuous
And $\epsilon - \delta$ as a theorem
 
11:12 AM
Wait so continuity asserts that $|f(a_n) - f(a)| \lt \epsilon$?
 
The reverse implication is more interesting: if $a_n \to a \implies f(a_n) \to f(a)$ for EVERY $\{a_n\}$ that converges to $a$, then $f$ is continuous in the $\epsilon-\delta$ sense.
 
Hello @Committingtoachallenge @ᴇʏᴇs @DavidWheeler. I am waiting for my mum to come home with dinner.
 
@Committingtoachallenge No, continuity asserts that given $\epsilon > 0$, we can FIND $\delta > 0$ so that $|x - a| < \delta \implies |f(x) - f(a)| < \epsilon$
 
Hi @ABeautifulMind Do you know how to cook
 
@ᴇʏᴇs No. I never cooked.
 
11:15 AM
@ABeautifulMind Hello Jasper
 
Certainly, if "all the terms" $a_n$ for sufficiently large $n$ are within $\delta$ of $a$ for ANY $\delta$, then we can find an $N$ big enough so that $f(n)$ will be within $\epsilon$ of $f(a)$ by continuity, once we get $\epsilon$
 
@ABeautifulMind My mom always used to make me cook food for her
 
@ᴇʏᴇs My mum always buys dinner from outside. We never cook.
 
The definition you are using is called "sequential continuity", and the $\epsilon-\delta$ version is called "limit continuity". They are equivalent.
There is a THIRD characterization: $f: \Bbb R \to \Bbb R$ is continuous if and only if the pre-image under $f$ of any open interval $(a,b)$ is a union of open intervals.
A fourth characterization goes like this: a point $P$ is said to be NEAR a set $A$, if: every neighborhood of $P$ has non-null intersection with $A$.
We write this as $A \leftarrow P$
Then $f$ is continuous iff $A \leftarrow P \implies f(A) \leftarrow f(P)$
So, in easily understood lay terms: "continuity preserves nearness"
 
Q: Calculate the cardinal number of the set of all sub sets of Z, if each sub set consists of only two members.
 
11:27 AM
@ABeautifulMind What do you guys normally buy
Hi @Parth
 
@Ali.B that is the same as the cardinality of $\Bbb Q$
 
@Nick Thanks for the advice. It was really true.
 
@David how can I show that ?
 
Can you give me advice too
 
@ᴇʏᴇs Hello, how're you?
 
11:29 AM
@Parth I haven't seen you in a while
 
@Ali.B The classical way is called "Cantor's First Diagonal Argument" google it.
 
ok searching now
thanks for the help
 
@ᴇʏᴇs Yeah, I haven't been around. Do you have a username that I happen to know you by?
 
@Parth Just my picture
 
Morning, fellas
 
11:41 AM
Hi @teadawg
 
I need some help proving that $3\ln^2\left(\frac{\sqrt{5}-1}{2}\right)=\ln(\sqrt{5}-2)\ln\left(\frac{\sqrt{5}-‌​1}{2}\right)$. Any ideas?
 
Do you mean $\ln\cdot \ln$ or $\ln\circ\ln$?
 
$\ln\cdot\ln$
It came up when I was working with inverse hyperbolic functions, and I'm at a complete loss
 
On the left side I did $3(\ln(\frac{\sqrt{5}-1}{2})\ln(\frac{\sqrt{5}-1}{2})) = \ln((\frac{\sqrt{5}-1}{2})^3)\ln(\frac{\sqrt{5}-1}{2}) = \ln(\sqrt{5} - 2)\ln(\frac{\sqrt{5}-1}{2})$
 
Wow, it was really that simple?
I must be super tired...
I wanted to separate $3\ln^2\left(\frac{\sqrt{5}-1}{2}\right)$ into $3\left(\ln(\sqrt{5}-1)-\ln(2)\right)^2$ for some reason...
Which is perfectly valid, but led me nowhere
Anyway, thank you @ᴇʏᴇs
 
11:52 AM
ya, it's easy: $\left(\dfrac{\sqrt{5}-1}{2}\right)^3 = (1/8)(8\sqrt{5} - 16) = \sqrt{5} - 2$
 
I need some coffee before I continue my work...
 
If you know anything about "quadratic extensions" you know that expressions like $a + b\sqrt{d}$ keep looking like that in higher powers
it's just "algebraic trickery", lol
 
Something I seem to butcher this early in the morning :(
 
dun feel bad, i hate computation with a passion
 
What I don't understand is how I was able to solve for $x$ in the equation $\sinh^{-1}(x)=\tanh^{-1}(\sqrt{x^2+1}-x)$ so easily...
Erm, how do you format higher-order roots in LaTeX again?
 
11:59 AM
this took me an obscene amount of time: math.stackexchange.com/a/1192369/23285
like \sqrt[3]{2} so: $\sqrt[3]{2}$?
 
Oh, I thought it was \sqrt[n]{x}, I was just making sure
 
Wanna give the equation above a shot? It involves solving a cubic
 
@DavidWheeler Very interesting thanks for that David
@DavidWheeler Where does this fourth characterization come from? Is this neighbourhood in the metric sense?
 
No, continuity in the $\epsilon-\delta$ form comes from metric spaces....an interval $(a-\epsilon,a+\epsilon)$ is a "one-dimensional $\epsilon$-ball centered at $a$"
 
12:05 PM
Yes, an $\epsilon$-segment
 
This is also written in the notation $B_{\epsilon}(a)$, and also as $\{x \in \Bbb R: |x-a| < \epsilon\}$
In the real numbers, the metric, or "distance function between two points" is $d(x,y) = |x - y|$
 
Yes, my metric space knowledge isn't too bad here
 
In more dimensions, a different function is used, but still written $|x -y|$
sometimes $\|x - y\|$ to emphasize the different nature of it
 
!!!!!!! The Maclaurin series for $\tanh^{-1}(z)$ is $\displaystyle \sum_{n=1}^{\infty}\frac{z^{2n-1}}{2n-1}$, so $\displaystyle \chi_1(z):=\sum_{n=0}^{\infty}\frac{z^{2n+1}}{2n+1}=\sum_{n=1}^{\infty}\frac{z^{‌​2n-1}}{2n-1}\implies\tanh^{-1}(z)=\chi_1(z)$
 
You refer now to the inner product?
 
12:08 PM
!!!!!!!
Sorry for interrupting :S
 
Or this is the norm sorry
 
Well, with the "standard" inner product we have $||x - y|| = \sqrt{\langle x-y,x-y\rangle}$
 
Should one of those be a plus?
 
In the plane this is the usual "hypotenuse" function: $d((x_1,y_1),(x_2,y_2)) = \sqrt{(y_2-y_1)^2 + (x_2-x_1)^2}$
@Committingtoachallenge No.....one should not be a plus
 
@DavidWheeler What are your favourite Math textbooks David?
 
12:15 PM
My favorite was Herstein's Topics In Algebra. I liked the blue cover.
 
@DavidWheeler The way you write that makes it look like the blue cover was the deciding factor
 
Well, it felt good to hold.
Most of the texts I have now are pdf or djvu
 
@DavidWheeler Was the content better than other algebra books?
 
Yes, and no
 
Was it on average better than the other textbooks you have used?
 
12:16 PM
It's very well-written. It doesn't cover as much ground as other books I have.
 
Is Dummit and Foote good as a stand alone in your opinion? Or just for recovering things you have learnt
 
For example, it has a "section" on Linear Algebra, but Hoffman&Kunze is a much more in-depth text on LA
 
Dummit & Foote can be hard going reading it on your own
 
Well I must go to sleep now, thanks for your opinions
 
12:18 PM
The problem sets are quite good
 
I would stay and chat but I am starting to become stupider
 
as you wish
 
12:59 PM
@Committingtoachallenge wow did you make that excel spreadsheet?
 
 
1 hour later…
2:24 PM
@ᴇʏᴇs Rice, chicken, egg, spinach.
 
Hi @DanielFischer
 
2:42 PM
Back from my dental appointment, much quicker than I was expecting
 
Do you know much about vector fields, @teadawg1337?
 
@Khallil Very little, I need to relearn vector calc
 
Ah, I just started learning about them. Do you know how to show that a vector field isn't conservative, @teadawg1337?
 
@TimDavids Hi.
 
@KhallilBenyattou If its curl isn't zero but its partial derivatives are continuous
The following identities are important in vector calculus: == Operator notations == === Gradient === Gradient of a tensor field, , of order n, is generally written as and is a tensor field of order n + 1. In particular, if the tensor field has order 0 (i.e. a scalar), , the resulting gradient, is a vector field. === Divergence === The divergence of a tensor field, , of non-zero order n, is generally written as and is a contraction to a tensor field of order n − 1. Specifically, the divergence of a vector is a scalar. The divergence of a higher order tensor field may be found by d...
 
2:54 PM
Yep, I need to relearn vector calc with a different textbook...
 
@DanielFischer For a surface $g(x,y) = \{ \frac{y^{2}(x-y)}{x^{2}+y^{2}}~~\text{ if }(x,y) \neq (0,0), ~0~~\text{ if }(x,y = (0,0) \}$. I found that if there were tangent plane at the origin it would be $y + z = 0$. But then I found that the directional derivative in the direction $(1,1)$ is $D_{(1,1)}g(0,0) = 0$.
Can you give me a hint of how to show that the tangent line in the direction $(1,1)$ at the origin is not in this tangent plane. Can I simply observe that this tangnnt must be in the plane $z = 0$?
 

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