It is up to you to decide. When voting for the project, you'll be asked how much you'd be willing to pay for such a set. LEGO then takes the prices the people enter and calculates from there how large the set should be.
CUUSOO projects even more so, because they are limited, and with higher-quality boxes and instructions.
@PedroTamaroff yeah another stupid question. Everyone just enters 1 there, obviously. Unless you have ten grandchildren and don't want any of them to be missing out.
@RegDwigнt You know, I once bought an X-fighter, and lost a piece. When I filed a thingy to LEGO to get the pieces back, I mistakenly clicked to option the pieces were missing. They sent them all the way from Denmark to my place, here in Argentina. BANANAS.
It's Japanese for something like "wish to come into existence" or some such.
There might be others in this room more qualified to answer, I don't speak enough Japanese.
The original site was only in Japanese and only for the Japanese market. The first two projects only got released in Japan. A Japanese submarine, and a Japanese satellite.
@PedroTamaroff, $$\max_{x_1}f(x_1,g(x_1)).$$ And, let $f$ attends max at $x_1^*$, so first order necessary conditions imply that $$\dfrac{\partial f(x_1^*,g(x_1^*))}{\partial x_1}+\dfrac{\partial f(x_1^*,g(x_1^*))}{\partial x_2}\dfrac{d g(x_1^*)}{dx_1}$$ as well as first order necessary conditions imply that $$\dfrac{\partial f(x_1^*,g(x_1^*))}{\partial x_1}=0$$ and $$\dfrac{\partial f(x_1^*,g(x_1^*))}{\partial x_2}=0.$$
my text says "If the differential function $f(x_1,\dots,x_n)$ reaches a local interior maximum at $(x_1^*,\dots,x_n^*)$, then these hold simultaneously: $$\dfrac{\partial f(x_1^*,\dots,x_n^*)}{\partial x_1}=0;\dots;\dfrac{\partial f(x_1^*,\dots,x_n^*)}{\partial x_n}=0 $$
@PedroTamaroff that's the asking price for the most common pieces, yes. As pointed out above, for more rare ones it goes all the way up to 150 dollars, though.
@PedroTamaroff, robjohn said $\dfrac{\partial f(x_1^*,g(x_1^*))}{\partial x_1}=0$ and $\dfrac{\partial f(x_1^*,g(x_1^*))}{\partial x_2}=0.$ do not hold. Why so?
The set has 2040 parts. I have a collection of roughly 180,000 parts, and I'm specifically collecting as many different parts in as many different colors as possible, and yet I am still missing 75 parts for that set, or almost 4%.
Even if I completely ignore colors, I'm still missing 10.
@PedroTamaroff MultiCollider bait. The MultiCollider is that thingamajig with the top questions network-wide that used to be a dropdown in the top left corner of every page, and is now an embedded list on the right of some pages.
Besides, what if the language happens to be so beautiful you want to expand and read poetry in it? And more to the point, what if it's so hideous that you don't?
Hey guys, i have a short question: if $f:\mathb R\to \mathbb R$ is continuous and bijective, can you follow for f that the image of open sets is always open? a yes or no would be enough. thanks.
