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1:23 PM
What represents equivariant cohomology? That is, given a $G$-space $X$, is there a $G$-space $Z$ such that $H^n_G(X; \Bbb Z) := H^n(X\times_G EG; \Bbb Z) = [X, Z]_G$ naturally? Looking around tells me about "equivariant Eilenberg MacLane spaces" but these seem to represent Bredon cohomology, not Borel equivariant cohomology.
 
2:06 PM
@BalarkaSen I think Map(EG,K(Z,n)), viewed as a G-space by the action of G on EG, does this.
 
You're right, I just realized.
Thanks, this is helpful
 
 
2 hours later…
4:04 PM
Where was the equivalence KO/(\eta) = KU first shown? This gets attributed to Wood, but I can't find a reference.
 

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