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2:30 AM
@CharlesRezk what does it mean? i seem to remember something like... if you pull back along the inclusion of an interval, it becomes Cartesian, or something?
 
2:41 AM
That's the definition. But you can actually say it the following way: an edge $f$ is locally $p$-Cartesian if there exists a pullback square $q\Rightarrow p$ such that $f$ is the image of a $q$-Cartesian edge. In other words, locally Cartesian edges are the smallest class containing Cartesian edges which is "local", i.e., detected by taking pullbacks.
 
 
6 hours later…
8:29 AM
Ever since I read the definition of locally cartesian fibration over an $\infty$-category $\mathcal{C}$, I wanted to think of it as an unstraightning of a functor to some kind of $(\infty,\infty)$-category of $\infty$-categories $\mathcal{C} \to Cat_{(\infty,\infty)}$. Was anything of the sort ever done?
 
9:18 AM
@SaalHardali By analogy with the classical case, locally cartesian fibrations over C should be equivalent to normal lax functors from C^op to the (infinity,2)-category of infinity-categories. I don't know if this has been proved.
 
10:06 AM
@SaalHardali @AlexanderCampbell @DenisNardin the locally cocartesian case is section 3 here: math.harvard.edu/~lurie/papers/GoodwillieI.pdf
 
It seems my memory is unreliable. Ignore me, please :/
 
@DylanWilson Of course! Thanks.
 
 
8 hours later…
6:14 PM
I thought I recalled a discussion of the "straightened version" of locally cartesian fibrations in Clark and Jay's note but I can't find it in there now.
 
 
5 hours later…
11:09 PM
Is it possible to compute the dual Steenrod algebra directly, without first knowing the Steenrod algebra?
 
11:52 PM
@TimCampion you should be able to compute the Hopf ring for HFp without Steenrod operations, and get at the dual Steenrod algebra this way.
I think Wilson does something like this in the BP sampler.
 

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