\newcommand{\summ}
from the title here: math.stackexchange.com/posts/2340811/revisions
5:12 AM
titles I have removed
It seems that this did not break any comments on that post. But I could try whether \summ appears in some other posts/comments.
search posts No posts with \summ: data.stackexchange.com/math/revision/972953/1205843/… data.stackexchange.com/math/revision/1094683/1351462/… data.stackexchange.com/math/revision/1066861/1318473/…
search comments Comments with \summ: data.stackexchange.com/math/query/556789/… data.stackexchange.com/math/revision/1094685/1351465/… data.stackexchange.com/math/revision/1066862/1318474/…
I found only a single comment, which also contains \newcommand, so no problem there: math.stackexchange.com/questions/2436242/…
$\newcommand{\root}[2][]{^{#2}\sqrt[#1]} \newcommand{\derivative}[3]{\frac{\mathrm{d}^{#1} #2}{\mathrm{d} #3^{#1}}} \newcommand{\abs}[1]{\left\vert\,{#1}\,\right\vert}\newcommand{\x}[0]{\times}\newcommand{\summ}[3]{\sum^{#2}_{#1}#3}\newcommand{\s}[0]{\space}\newcommand{\i}[0]{\mathrm{i}}\newcommand{\kume}[1]{\mathbb{#1}}\newcommand{\bold}[1]{\textbf{#1}}\newcommand{\italic}[1]{\textit{#1}}\newcommand{\kumedigerBETA}[1]{\rm #1\!#1}$$x= x_{\text{real}}, \space y = y_{\text{real}}, z = x_{\text{imaginary}}$ Now where is $y_\text{imaginary}$? We need $1$ dimension more. — MCCCS Sep 19 '17 at 16:19
search comments Nothing found with the two newer queries: data.stackexchange.com/math/revision/1066863/1318475/… data.stackexchange.com/math/revision/1066865/1318477/…
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