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Martin Sleziak
Martin Sleziak
7:55 AM
Actually, the first query returns many posts, since some posts contain \Delta. We can forbid \Delta or use regex.
One of the comments seems to be false positive - I do not see definition of the macro anywhere on the site:
I must admit I don't get why the proof you wrote should work. It seems to me that you have to prove it for the usual smooth test functions $\varphi$. The proof should go along the same lines as the usual proof that $\Del^2 (1/|x|) = - 4\pi \delta(x)$ in 3D. I have never heard of analytic test functions. — Stephen Montgomery-Smith Mar 7 '15 at 5:51
The other one was already mentioned here, since it contains other macros which are not rendered.
 
 
1 hour later…
Martin Sleziak
Martin Sleziak
9:08 AM
data-explorer When checking for posts which contain some macro but no macro definition, I should also check for \renewcommand - not only for \newcommand.
 
 
6 hours later…
Martin Sleziak
Martin Sleziak
2:51 PM
 
Martin Sleziak
Martin Sleziak
3:06 PM
Very nice, a few details I am curious about though. Why are you using x both as an integration variable and as a function ? I though that $\operatorname{Li}_2(z) = \int_0^z \frac{\log(1-t)}{t} \dt$, oh substitution! Silly me =) Will read through it carefully — N3buchadnezzar Aug 4 '13 at 14:24
@EricAuld: the fact that $\Phi_t$ is the flow of $X$ is $$\dt \Phi_t(h) = X(\Phi_t(h)).$$ Now use the fact $L_g^* X = X$ and choose $h=L_g^{-1} (p)$. — Anthony Carapetis Dec 16 '13 at 17:37
Unless I missed something, only in the second case, the macro \dt is defined on the page.
I have added the macro in this answer: math.stackexchange.com/posts/2960439/revisions (it is defined in the question.)
It seems that several posts and comments contain \floor - although this macro is not defined in that page.
 

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