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6:17 AM
I'll also need to add a mode that acts as a "wrapper" for "calculate such-and-such real number to N digits" or "return the Nth digit" questions such as this, in which it runs a regex that works like my "divide by sqrt(2)" one, i.e. divides the input by it if it's a number >1 or multiplies by it if <1, and then processes the resultant integer to get the desired digit(s) and prints that in the format required.
 

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