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2:42 AM
Now consider a finite set A and some element b not in A. then by definition of finite sets the inductive-A-system is P(A). Let B = A ∪ {b} and let R be an inductive-B-system. Thus for all C⊆R we have (∅ in C and X in C ⟹ X ∪ {b} in C for x in B) implies B in C
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In particular, B= A ∪ {b} in C suggests A in C and hence P(A) in C by the definition of inductive-A-system. Moreover, {b} in C and by the definition of inductive-B-system, {b}∪ D in C, where D in P(A)
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In particular, B= A ∪ {b} in C suggests A in C and hence D in C, where D in P(A) by the definition of inductive-A-system. Moreover, {b} in C and by the definition of inductive-B-system, {b}∪ D in C
Hence P(A) ⊆ R
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[ SmokeDetector | MS ] Email in answer, potentially bad ns for domain in answer, potentially bad keyword in answer (77): How do I claim bitcoin from an old wallet? by Ronald Sean on bitcoin.SE
 

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