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Bob
9:11 AM
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Q: What to do with incompetent questions?

kludgI recently tried to close this question. It did not work. The OP started the question by "I want to show that if one measures $M_1$ on $|\psi\rangle$ then measures $M_2$ on the resulting state and then the associated probability space will be the same as the one for measuring the product $M_2 M_1...

 

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