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10:06 AM
Oh, dear. Everybody seems to have moved to the quantum channel, and I try to join the conversations there seem to change :)
 
 
9 hours later…
7:19 PM
@MoreAnonymous There's likely a newer one, but this is the one I read at the start of my PhD a few years back: arxiv.org/abs/quant-ph/0610030
The important thing to understand is that if 2 parties don't know each others' frames, you have to average over all possible frames, which cause decoherence-like effects
 
7:32 PM
@MaartenBodewes There just don't seem to be a lot of people regularly using this room :/
@MaartenBodewes I have a very rough number - if you have fully connected number of logical qubits equal to the key size, then that should be more or less enough
However, For each of those, you'll need a load of physical qubits (maybe 100? I can't remember the number that everyone plucks out of nowhere)
 
 
3 hours later…
10:34 PM
@Mithrandir24601 Thanks, I'm hoping for an answer from the team of b degnan as well. I hope it matches up. I got a ballpark figure from Poncho from our site too, but neither of all has some kind of back up.
 
11:32 PM
Ah, that's good - It's definitely possible to sit down and work it out (and I suspect the answer is O(n) anyway)
 

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