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11:00 PM
 
11:25 PM
@Mithrandir24601 is this a bad question? Any thoughts?
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Q: Why can this potential be snuck in without violating symmetries?

More AnonymousBackground So if I think of a gas of say having only $2$ point particles $A$ and $B$. Then, the Hamiltonian in the relativistic case is given by: $$ H_1 = \gamma_A m_Ac^2 + \gamma_B m_Bc^2 $$ where $\gamma= \frac{1}{\sqrt{1 - v^2/c^2}}$ and $m$ is mass. However, this doesn't really make sense...

 
11:51 PM
@Mithrandir24601 sigh ... I can be sooo idiotic when I'm tired
 

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