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12:02 AM
Damn, this is pretty dense stuff.
Was Boolean algebra relatively difficult for you when you first learned it?
 
It was a while back when I learned it, but with time, it becomes intuitive. You'll get the hang of it: It gets messy: that's part of the confusing part!
 
messy as in lots of difficult to read notation? cause I can definitely see that.
though I suppose the notation would become intuitive
 
Yes, the notation will become quite familiar. But initially, it is really like learning a new language, with the need to keep translating to what is more familiar. But once you learn the "language", it will read much more smoothly.
 
I am a bit confused still about /equiv. What is the truth table for it?
Other than that I think I understand everything now except are still steps left for the proof
 
12:21 AM
p \equiv q < - > p if and only if q <---> see the truth table here. URL: (wolframalpha.com/input/?i=p+iff+q)
It means the same as [( p --> q) AND ( q --> p ) ]
feel free to accept my answer, when you're ready. ;-) Even if you accept now, I will still be available if you "ping" me: @amwhy, or commenting below my answer --> I get notified.
 
Alright, thanks alot for your help
 
You're welcome!
 
I think I need a break for now. I will accept your answer. Technically I feel that its not complete because it doesn't show the final steps of the proof, but you have taught me so much other stuff that I think you more than deserve the accept.
 
Thanks...I'll be around!
 
Cool. Now I kinda feel bad for nitpicking. It really means a lot to me that you took the time to help. Take care.
 
12:54 AM
Do not worry! I didn't take offense!. Good luck!
 

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