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12:30 AM
4
Q: Is there a name for this equivalence relation?

Guozhen ShenLet $M$ be an arbitrary set and let $\mathscr{F}$ be a family of subsets of $M$. Is there a known name for the following equivalence relation or its corresponding partition? $\sim_{M,\mathscr{F}}\,=\bigl\{(x,y)\in M\times M\bigm|\forall A\in\mathscr{F}\,(x\in A\leftrightarrow y\in A)\bigr\}$.

 
 
9 hours later…
9:44 AM
5
Q: Does $Ext^1(M,M) \neq 0$ imply $Ext^2(M,M) \neq 0$?

MareThe first question is about group algebras: Question 1: Let $A=kG$ be a group algebra and let $M$ be an indecomposable $A$-module. Does $Ext_A^1(M,M) \neq 0$ imply $Ext_A^2(M,M) \neq 0$ or even $Ext_A^i(M,M) \neq 0$ for all $i>0$? This is true in case $A$ is representation-finite. The next ...

 
 
7 hours later…
4:23 PM
6
Q: Is there an algorithm for determining whether an expression involving nested radicals is rational?

JimSpecifically, consider expressions involving integers, addition, multiplication, division, and nth roots for any positive integer n. Is there an algorithm that can determine whether such an expression is a rational number? If the expression is a rational number, is it possible to determine which ...

 
 
1 hour later…
5:35 PM
3
Q: Is the inverse of a measurably parametrised family of bijections between standard Borel spaces measurably parametrised?

Julian NewmanIt is known that a measurable bijection $f \colon [0,1] \to [0,1]$ has a measurable inverse. (Here, all measurability is simply with respect to the Borel $\sigma$-algebra of $[0,1]$.) Now fix an arbitrary measurable space $(\Omega,\mathcal{F})$, and let $(f_\omega)_{\omega \in \Omega}$ be a fami...

 

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